L Equation (4) from Equation(4x - 4x) + (6y -6y)-16-7i.e.,Th09, which

1.	L Equation (4) from Equation(4x - 4x) + (6y -6y)-16-7i.e.,Th09, which is a false statementerefore, the pair of equations has no solution.Example 13 : The sum of and thethe digits is 66. If the digits of the number differ by 2. find thenumbers are there?a two-digit number and the number obtained by revenumber. How many s
Answer» Let the ten’s and the unit’s digits in the first number be x and y, respectively. So, the first numbercan be written as 10x + y in the expanded form. When the digits are reversed, x becomes the unit’s digit and y becomes the ten’s digit. This number, in the expanded notation is 10y + x. According to the given condition. (10x + y) + (10y + x) = 66 11(x + y) = 66 x + y = 6 ... (1) Youare also given that the digits differ by 2. Therefore, either x – y = 2 ... (2) or y – x = 2 ... (3) If x – y = 2, then solving (1) and (2) by elimination, you get x = 4 and y = 2.In this case, the number is 42. If y – x = 2, then solving (1) and (3) by elimination, you get x = 2 and y = 4.In this case, the number is 24. Thus, there are two such numbers 42 and 24.

L Equation (4) from Equation(4x - 4x) + (6y -6y)-16-7i.e.,Th09, which is a false statementerefore, the pair of equations has no solution.Example 13 : The sum of and thethe digits is 66. If the digits of the number differ by 2. find thenumbers are there?a two-digit number and the number obtained by revenumber. How many s

Answer»

Let the ten’s and the unit’s digits in the first number be x and y, respectively. So, the first numbercan be written as 10x + y in the expanded form.

When the digits are reversed, x becomes the unit’s digit and y becomes the ten’s digit. This number, in the expanded notation is 10y + x.

According to the given condition.

(10x + y) + (10y + x) = 66

11(x + y) = 66

x + y = 6 ... (1)

Youare also given that the digits differ by 2. Therefore,

either x – y = 2 ... (2)

or y – x = 2 ... (3)

If x – y = 2, then solving (1) and (2) by elimination, you get x = 4 and y = 2.In this case, the number is 42.

If y – x = 2, then solving (1) and (3) by elimination, you get x = 2 and y = 4.In this case, the number is 24.

Thus, there are two such numbers 42 and 24.