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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
broight a cycle for Rs 315 and sol month hater at a loss 12% How many lose? |
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Answer» Question you have submitted is incomplete. Please post a complete question. A brought a cycle for Rupee 375 and Sold it one month letter at a loss 12% how much did I loss A lady btoughht 50 sweet at 20paise each in her house 10sweets where consumed see sold th remaining sweet at 40 paise each what is her gain or loss percent please solve |
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| 2. |
Find the selling price if CP = Rs. 120, loss = 12 1/2 % |
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| 3. |
5.\sqrt{6+\sqrt{6+\sqrt{6+\dots+\infty}}}(A)-3(B)3 |
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Answer» so x = 3, (B) thanks B 3 ..... Subscribe GAMING WITH BARUN CHANNEL ON YOUTUBE |
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| 4. |
The equation of the circle with centre (1, 7) and radius is |
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| 5. |
sample 18 : Factorise(4+70ab |
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Answer» 49a² + 70ab + 25b² (7a)² + 2 × (7a) × (5b) + (5b)² (7a + 5b)² |
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| 6. |
Factorise.4 p^{2}-9 q^{2} |
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Answer» Use a² - b² = (a-b) (a+b) 4p² - 9q²(2p)² - (3q)²(2p - 3q) ( 2p + 3q) |
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| 7. |
Factorise4 n^{2}-8 n+3 |
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| 8. |
The angle of elevation of the top of a tower at a point on thfrom its foot is found to be 45°. find thCHAPTER9 SOME APPLICATHONS OF TI0On its foot is found to be 45°. find the height of the tower.(ans. 160 m)e ground, at a distance of 160 m |
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| 9. |
My grandfather gave me 150 on my birthday. Ispent 89. How much money is left? |
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Answer» Amount given=₹150Amount spent=₹89Money left=₹150-₹89=₹61 grandfather gave ₹150- i spend ₹89= ₹ 61 left |
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| 10. |
2. Factorise.4 p ^2 - 9 q^2 |
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Answer» thank u for giving answer |
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| 11. |
factorise x^4+x^2y^2+y^4 |
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Answer» x*x*x*x + x*xy*y + y*y*y*y = x*x*x*x + 2x*xy*y + y*y*y*y - x*xy*y = (x*x + y*y)(x*x + y*y) - (xy)(xy) = (x*x + xy + y*y)(x*x - xy + y*y) If you find this answer helpful then like it. |
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| 12. |
Factorise:(i) 15(5x -4)2 10(5x-4) |
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| 13. |
Factorise x ^ { 4 } + x ^ { 2 } y ^ { 2 } + y ^ { 4 } |
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Answer» x^4+2x^2y^2+y^4-x^2y^2=(x^2+y^2)-(xy)^2=(x^2+xy+y^2)(x^2-xy+y^2) |
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| 14. |
Factorise:(i) 15(5x - 4)^2-10(5x - 4) |
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| 15. |
Find the equation of the line throughthe point C2,3) such that the segmentthe line intercepted between the axesis bisectedl st this Point.s point |
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| 16. |
Q.9 Find the equation of the locus of a point which is equidistant from the point (1,3)and X-axis. |
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Answer» answer of your question is 0 |
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| 17. |
By selling a refrigerator for Rs.15000, I loss 12%.What did I pay for it? |
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Answer» Loss is 12 percentagesowe have to find cost price |
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| 18. |
Mobile marked at Rs. 15000/- is sold for Rs. 14000 / - .What is thediscount and discount percentage. 1000 x 1001221 |
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| 19. |
6. Find the equation of the circle whose centre is at the point (2.-3) and which passes through thepoint(0,1). |
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| 20. |
10. Find the equation of a line passing through the points A(0, 6, 9) and B(-3,-6,SIDis the foot of perpendicular drawn from a point C(7, 4,-1) on the line AB, then find thecoordinates of the point D and the equation of line CDAICBSE20 |
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| 21. |
UWhat is the equation of strIs the equation of straight line passingrough the point (4, 3) and making equalinterctercepts on the coordinate axes?2014 |
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Answer» x/a + y/a = 1Since it passes through (4, 3)4/a + 3/a = 1a = 7Equation of line isx + y = 7 |
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| 22. |
Ll 1t [2 k15 B 0=T+X9—X 8Te |
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| 23. |
4. At what point to the co-ordinate axes meet?5. Find the point where the graph of liner equation 7-2x +4y 0 cuts the y-axis. |
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Answer» 4. at origin (0,0) 5. for point at y-axis x = 0 => 7-2×0 +4y = 0 => 4y = 7 => y = 7/4 |
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| 24. |
Over a tower AB of height H metres there is a flagstaff BC ab and BC are making equal angles ata point distant d metres from what a of Tower the height of flagstaff is |
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| 25. |
2.Solve the following examples.(1) Find the height of an equilateral triangle having side 2a. |
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Answer» (h)^2=(2a)^2-(a)^2=3a^2Then height h =√3a |
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| 26. |
आकृति (i)हे गये आकृति (iii) में 30 का मान निकालेंहाँ LP || MR और ZLPQ= 409 और 2QRM= 300Mआकति (i) |
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Answer» in triangle bQP angle QbP =30 (alternate of QRM soangle bQP =180-(30+40) =180-70=110 now by liner pair pro.angle x=180-110 =70 |
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| 27. |
bxerciseh, breadth and height of a wooden box is 1 m, 60 m and 40 cm respectivelye outer surface area of the wooden box.The lengtThe measures of a box aro 40 |
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Answer» length= l= 1 m = 100 cmbreadth= 60 m = 600 cmheight = 40 cm total surface area = 2(lb + bh + lh)= 2(60000 + 24000 + 4000)= 2(88000)= 176000 cm2= 17.6 m2 |
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| 28. |
खवूवाला 70 लाटर दूध 30 रूपये में खरीदताहै। फिर Sute पारी सदरा में मिलाअगर न १ सपरी तीर की दर से Muciजल तारा लाभलार।(६) (6) G) 83 (4) 71% |
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| 29. |
Volume and Surface Areas of Solids6. The slant height of a conical mountain is 2.5 km and the area of its baseis 1.54km . Find the height of the mountain.l ight of a solid cylinder is |
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| 30. |
Q. Find interest and amount to be paid on Rs 15000 at 5% perannum after 2 years. |
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Answer» I = 15000×5×2/100 = 1500 A = 15000 + 1500 = 16500 |
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| 31. |
A T.V purchased at Rs 20,000 and soldat Rs. 15000. Then the the loss percent is |
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Answer» CP=20000SP=15000so loss=(20000-15000)/20000*100 =5000/20000*100=25% |
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| 32. |
7. The shape of solid iron rod is a cylinderical. Its height is 11 cm. and base diameter is 7cm.Then find the total volume of 50 such rods? |
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Answer» Height of rod = 11 cm Diameter = 7 cm Radius = 7/2 cm Volume of 1 rod = pi × r² × h = (22/7) × (7/2)² × 11 = 11×11×7/2 = 121 × 7/2 = 847/2 cm³ Volume of 50 rods = 847 × (50/2) = 25×847 = 21175 cm³ |
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| 33. |
The slant height of a frustum of a cone is 4 cm and" the perimeters (circumference) of its circular endsare 18 cm and 6 cm. Find the curved surface area ofthe frustum. |
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| 34. |
The radius and height of a right circular cone are in the ratio 4:3 and its volume is 2156 csurface area and the total surface area of the cone.u. cm. Find the curved |
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| 35. |
28000 cu. mm. into cu. cm.A4 "N Âť |
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| 36. |
n(U)-125In the adjacent diagram, if n(U) 125, y is two times of zand z is 10 more than a, then find the value of x, y and z.3617 |
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Answer» y=2x and z=x+10so x+y+z+4+3+6+17+5=125so x+2x+x+10+31=125so 4x=84so x=21so y=42so z=31 but the answer given in the book back is 20 ,40 ,30 |
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| 37. |
transaction?A shopkeeper solda wrist watch forき990 gainingwatch and his profit percent.ofits cost price. Find the cost price ofthe wrist12.&fnd the nrofit nercent. |
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| 38. |
62. A car which cost Rs 2,20,000was the S.P? [ Ans : Rs 1,43,000]Amod sold a plot of land to binoy at 15% profit and Binoy sold it to carolin at 15% loss. If the costprice of the land for Amod was Rs 50000, How much did carolin pay to buy the land? If amod was63,to sell the land directly to carolin, what would have been his profit or loss percent?profit of30% on one and suffers a loss of 30%nercent? |
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| 39. |
sin(150+x)+sin(150-x) |
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| 40. |
daily wages (in ) of 15 workers in a factory are given below180, 150, 150, 130, 180, 180, 200, 150, 130, 180, 180, 200, 150, 180.nge the above data in ascending order and prepare the frequency table.and prepare the frequency table: |
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Answer» Thank you Thank you |
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| 41. |
14. ĐEXERCISE1. What will the amount Rs. 2500 at compound interest 10% per annum for3years?(1) Rs 3327.50 (2) Rs 3250 (3) Rs 2850 (4) Rs 29002. What will the amount o 900 ton15.1 |
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| 42. |
10. The difference in compound interest and simpleinterest on a certain amount at 10% pa. at theend of the third year is Rs.620. What is theprincipal amount?(a) Rs. 40000(c) Rs. 100006(b) Rs. 120000(d) Rs. 20000 |
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Answer» (c)10000 620÷10=100 (c) 10000620÷10=100 (c) 10000620\10%=100 (c) 10000620/10=100 10000is right answer Ans ( a) 40000 is right answers Answer of this question is 20000 ( c ) 10000620*10= 100 10000lllllllllllllllllllll 10000 is right answer is question ka answer 10,000 hi second option is correct answer (b) is correct answer (c) 10000620%10=100 (c) 10000 620/10=100 1000is ansr 620-:10 hs ok the answer of the questions is 10000 620/10 =100 C =10,000 (c) 10000 620÷10= 100 (c) 10000 620 ÷10=100 principal amount (d) Rs. 20000 RS. 20000 is the correct answer |
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| 43. |
1. Amit Kumar invested an amount f Rs 15000 at compound interest rate of 10 pcpa for aperiod of 2 years. What amount will he receive at the end of two years?a) Rs 18000 b) Rs 18500 C)Rs 17000 d) Rs 18150 |
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Answer» (d) Rs 18150 is the correct answer |
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| 44. |
person invested some amount at 12% interest and some other amount at 10%nterest. He received yearly interest of Rs. 130. But if he had interchanged the amohave received Rs. 4 more as interest. How much amount did he invest on differenould |
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Answer» ●Let the amount invested Rs x at the rate of 12% and Rs. y at the rate of 10% According to the question:- ●simple intrest on Rs x at 12% + simple intrest on Rs. y at 10% = 130 we know simple intrest = (principle × rate × time )/100 and apply the formula (x × 12 × 1)/100 + ( y × 10 × 1)/100 = 130 => 12x + 10y = 13000 ......................( equation 1) ●If he interchanged the amount invested , he would have received 4 more on intrest then , simple intrest on Rs x at 10% + simple intrest on Rs. y at 12 % = 130 + 4 ( x × 10 × 1)/100 + ( y × 12 × 1)/100 = 134 => 10x + 12y = 13400 ................................( equation 2) ●solving both equation we will multiply by 12 in (equation 1) and multiply by 10 in (equation 2) 144x + 120y = 156000 100x + 120y = 134000 - - - ( subtracting the equation) 44x = 22000 x = 500 ● put the value of x = 500 in equation 1 12 × 500 + 10y = 13000 6000 +10y = 13000 10y = 13000 -6000 10y = 7000 y = 7000/10 y = 700 ●the amount invested at 12 % is 500 Rs and 10 % is 700 ●we use simple intrest formula SI = (P × R ×T) /100 ●and the value is x = 500 Rs y = 700 Rs. |
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| 45. |
Amount - Rs. 3.37,900Monthly- Rs. 3500What is the interest percent? |
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| 46. |
If Rs 460 amounts to Rs 632.80 in 3 years, what will Rs 800 amount to in 5years?2 |
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| 47. |
If y = (tanx) tans thenlaat X=at x =is00 |
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Answer» the answer will be 2 obviously. 2 is the right answer of the following 0 is the correct answer 2 is the correct answero |
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| 48. |
Find the value oftan(tans)\tan ^{-1}\left(\tan \frac{9 \pi}{8}\right) |
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Answer» First Break 9 pi/8 into pi+ pi/8 tan inv(tan9π/8) =+ 9π/8- π= π/8. see the graph after π. at π . the value is o. so 9π/8 is greater than π with. π/8 as anwer. |
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| 49. |
value102. The20 30 42 56 72 90(A) 10(C) 20(B) 520 |
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Answer» Answer:C)3/20Explanation |
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| 50. |
4. Draw a histogram for the following frequency distribution10-15 15- 20 20-so 30-40 40-60 60-1005201620 |
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