7. The shape of solid iron rod is a cylinderical. Its height is 11 cm.

1.	7. The shape of solid iron rod is a cylinderical. Its height is 11 cm. and base diameter is 7cm.Then find the total volume of 50 such rods?
Answer» Height of rod = 11 cm Diameter = 7 cm Radius = 7/2 cm Volume of 1 rod = pi × r² × h = (22/7) × (7/2)² × 11 = 11×11×7/2 = 121 × 7/2 = 847/2 cm³ Volume of 50 rods = 847 × (50/2) = 25×847 = 21175 cm³

7. The shape of solid iron rod is a cylinderical. Its height is 11 cm. and base diameter is 7cm.Then find the total volume of 50 such rods?

Answer»

Height of rod = 11 cm

Diameter = 7 cm

Radius = 7/2 cm

Volume of 1 rod = pi × r² × h

= (22/7) × (7/2)² × 11

= 11×11×7/2

= 121 × 7/2

= 847/2 cm³

Volume of 50 rods = 847 × (50/2)

= 25×847

= 21175 cm³