1.

Find the value oftan(tans)\tan ^{-1}\left(\tan \frac{9 \pi}{8}\right)

Answer»

First Break 9 pi/8 into pi+ pi/8

tan inv(tan9π/8) =+ 9π/8- π= π/8. see the graph after π. at π . the value is o. so 9π/8 is greater than π with. π/8 as anwer.



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