person invested some amount at 12% interest and some other amount at 1

1.	person invested some amount at 12% interest and some other amount at 10%nterest. He received yearly interest of Rs. 130. But if he had interchanged the amohave received Rs. 4 more as interest. How much amount did he invest on differenould
Answer» ●Let the amount invested Rs x at the rate of 12% and Rs. y at the rate of 10% According to the question:- ●simple intrest on Rs x at 12% + simple intrest on Rs. y at 10% = 130 we know simple intrest = (principle × rate × time )/100 and apply the formula (x × 12 × 1)/100 + ( y × 10 × 1)/100 = 130 => 12x + 10y = 13000 ......................( equation 1) ●If he interchanged the amount invested , he would have received 4 more on intrest then , simple intrest on Rs x at 10% + simple intrest on Rs. y at 12 % = 130 + 4 ( x × 10 × 1)/100 + ( y × 12 × 1)/100 = 134 => 10x + 12y = 13400 ................................( equation 2) ●solving both equation we will multiply by 12 in (equation 1) and multiply by 10 in (equation 2) 144x + 120y = 156000 100x + 120y = 134000 - - - ( subtracting the equation) 44x = 22000 x = 500 ● put the value of x = 500 in equation 1 12 × 500 + 10y = 13000 6000 +10y = 13000 10y = 13000 -6000 10y = 7000 y = 7000/10 y = 700 ●the amount invested at 12 % is 500 Rs and 10 % is 700 ●we use simple intrest formula SI = (P × R ×T) /100 ●and the value is x = 500 Rs y = 700 Rs.

person invested some amount at 12% interest and some other amount at 10%nterest. He received yearly interest of Rs. 130. But if he had interchanged the amohave received Rs. 4 more as interest. How much amount did he invest on differenould

Answer»

●Let the amount invested Rs x at the rate of 12% and Rs. y at the rate of 10%

According to the question:-

●simple intrest on Rs x at 12% + simple intrest on Rs. y at 10% = 130

we know simple intrest = (principle × rate × time )/100 and apply the formula

(x × 12 × 1)/100 + ( y × 10 × 1)/100 = 130

=> 12x + 10y = 13000 ......................( equation 1)

●If he interchanged the amount invested , he would have received 4 more on intrest

then ,

simple intrest on Rs x at 10% + simple intrest on Rs. y at 12 % = 130 + 4

( x × 10 × 1)/100 + ( y × 12 × 1)/100 = 134

=> 10x + 12y = 13400 ................................( equation 2)

●solving both equation we will multiply by 12 in (equation 1) and multiply by 10 in (equation 2)

144x + 120y = 156000

100x + 120y = 134000

- - - ( subtracting the equation)

44x = 22000

x = 500

● put the value of x = 500 in equation 1

12 × 500 + 10y = 13000

6000 +10y = 13000

10y = 13000 -6000

10y = 7000

y = 7000/10

y = 700

●the amount invested at 12 % is 500 Rs and 10 % is 700

●we use simple intrest formula SI = (P × R ×T) /100

●and the value is x = 500 Rs

y = 700 Rs.