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I sum of the square of zeros of the quadratic polynomial f(x)=x2- 8x + kis 40. find the value of k |
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Answer» For equation x^2 - 8x + k let a and b are zeroes Then, a + b = - (-8)/1 = 8ab = k/1 = k Given, a^2 + b^2 = 40 (a + b)^2 = a^2 + b^2 + 2ab64 = 40 + 2k2k = 64 - 40 = 24k = 24/2 = 12 |
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