This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
(a) 17(b) 16(c) 1(d) 2 |
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Answer» 2 is answer for the following questions |
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| 2. |
( \text { iii) } ( 12 a + 17 b ) \times 4 c |
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Answer» (12a+7b)*4c=12a*4c+7b*4c=58ac+28bc |
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| 3. |
gygroundtiheplainm2lar is 50 cm in diameter and 3.5 m in height. Find the cost of paintingcuyed surface of the pillar at the rate of ?12.50 per m2 |
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| 4. |
उदाहरण 17.X तथा ज्ञात कीजिए यदि2x +3y =[33] तथा 3x +2x = [] |
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| 5. |
2x+2y/2x-2y=17/8 find x and y |
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Answer» thanks bhai |
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| 6. |
17If 2x +y-17 and xy35, evaluate 8x3-ัะท, here?x>y.fi 3 |
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Answer» 2x+y=17----------(1)xy=35=>x=35/y----------(2) Substitute equation (2) in (1);70/y +y=17=>y²-17y+70=0=>y²-10y-7y+70=0=>y(y-10)-7(y-10)=0=>(y-10)(y-7)=0=>y=10 or 7 Now from equation (2);x=3.5 or 5 ∴8x³-y³=8(3.5)³-10³ or 8(5)³-7³=-657 or 657 thanks |
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| 7. |
ple4: Solve the equation 4x +5 17-2x and check the result. |
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Answer» 4x + 5 = 17 - 2x 4x + 2x = 17 - 5 6x = 12 x = 2 If you find this answer helpful then like it. |
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| 8. |
Find an anti derivative (or integral) of the following functi1. sin 2x2. cos 3x4. (ax + b)25. sin 2x - 4 e3xFind the following integrals in Exercises 6 to 20:6. S14 e ² + 1) dr 7. fx² (1 - 1 2 3 dx9. S(2x² + e*) dx 10. Sve - 1/2 dax12. fr +3 13. Pr - x² + x - 1 de15. SJ (3.17. ((2x² -X-1-dx |
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Answer» the correct answer is C Draw an angel of45 using a pair of compasses my answer is good ok bro |
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| 9. |
difference between simple interest and compound interest on a certain sum of money for 2 years at a rate of 4% per annum is 20₹ .Find the sum |
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| 10. |
x^{4}-8 x^{3}+21 x^{2}-20 x+5=0, the sum of two of the roots beingequal to the sum of the other two. |
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| 11. |
12 1ยง+ X =L - XS T LAR |
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| 12. |
“Boh Ll LS9 LaR 90€ 2o LipK L bk Wbiiie) sks |
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Answer» we know by euclide division lemma-: a=bq+r 657=306*2+45 306=45*6+36 45=36*1+9 36=9*4+0 here r=0 so b=hcf hence the hcf of 306,657 is 9 answer |
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| 13. |
2x+17=80 |
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Answer» 2x + 17 = 802x = 87 - 17 2x = 70x = 70/2x = 35 |
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| 14. |
Write the vector equation of the line passing through (1, 2, 3) and perpendicplane r i +2j-5k) +9 0 |
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| 15. |
NIkhl Lar |
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Answer» is not i no that answer is but is nakhilam sutar in vedoc maths |
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| 16. |
3:1 Find the value of n.Find 14 A.M's between 5 and 8 and hence show that their sum is 14 times the A.M.between 5 and 8. |
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| 17. |
in5, ABCD is a square with side 22cmanddthe area of the shaded region-U…314) |
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Answer» it's board questions |
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| 18. |
Show that the equation x2 + 6x + 6 = 0 has real roots and solve it. |
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| 19. |
dthe distance of the point (1line2, 3) from the plane x-y + z-5 measured parallel tothe |
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| 20. |
60+5x(16â-8+2)+3 = |
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| 21. |
If (3+1,y-)(,), find the values o#x an3) (3 3)dthe set B = 13.4. |
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Answer» comparing both coordinate givesx/3 + 1 = 5/3x/3 = 5/3 - 1x/3 = 2/3x = 2 y- 2/3 = 1/3y = 1/3 + 2/3 = 1 |
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| 22. |
1. Ajoker's cap is in the form of right circular cone whose base radius is 7cm and height is 24cm. dthe ara of hesthet neqr to10 such caps |
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| 23. |
(1) p(x)= x - 3x + 5x - 3, 8(x) = x? - 2 |
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Answer» the answer of this problem remaider is 3 see the answer of this question will be: |
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| 24. |
Find the sum2,-20, -89,12,184,-37 |
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Answer» The sum of the above given numbers is -542 -542 is the correct answer to this question. |
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| 25. |
37s37 days4)Nthese38. If 812 2431then find the value of x.1) x =-12) x =-23) x =-34) x =-4.39. Perimeter of a right angled triandle in 00 m Iflu |
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Answer» 81=3^4243=3^5Hence(3^4)^x-2=(3^5)^x-1henceequate the powers4(x-2)=5(x-1)4x-8=5x-54x-5x=-5+8-x=3x=-3 |
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| 26. |
6. Find the value of:i) - 37 -( - 15) - 2 |
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Answer» -37-(-15)-2= -37+15-2=-37+13=-24 |
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| 27. |
Infigure, if DE||BC, then x equals (यदि चित्र में DE||BC है तो ५ बराबर होगा )2cm3cm--- 4cmBE(A) 6 cm(B) 8 cm(C) 10 cm(D) 12.5 |
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| 28. |
2The difference between the two acute angles of a right angled triangle isradians. Thenthe angles are11 80.1081°, 9。3) 70°,204) 609,30° |
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Answer» Use sum of the two acute angles in rt tr is 90 deg i.e. pi/2 so if the two angles are 'x' and 'y' then x + y = pi/2 ( = 90 deg)and x - y = 2 pi/5 (= 72 deg) Now solve them and get that x = 81 deg and y = 9 deg cannot understand answer y 72deg |
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| 29. |
4(3-2) + 5x = 6(2x + 8)-12. |
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Answer» 4(3x-2)+5x = 6(2x+8)-12 12x - 8 + 5x = 12x + 48 - 12 5x = 44 x = 44/5 |
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| 30. |
2(x-y) = 35x + 8=14 |
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| 31. |
22. Whose area is greater? A square of side 4cm or of rectangle, 5cm x 3cm. |
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Answer» Area of square = side² = 4² = 16 cm² Area of recatngle = L × B = 5 × 3 = 15 cm² Area of sqaure is greater thank you |
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| 32. |
Example 1: Find the perimeter of each(b) P5cms (c)4cm5cm 3.5cm2cm3cm5cm3cm3.5cmQ5cm3cmIrm t 3 cm + 3 cm 8 cm Ans |
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Answer» 2+3+3=8cm5+5+5+5=20cm4+3+3.5+3.5=14cm |
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| 33. |
2The equation is x +14=6x+ |
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Answer» So, the equation can be written as x/2-1/5 = x/3 +1/4 => x/2 -x/3 = 1/5+1/4=> x/6 = 9/20 => x = 54/20 = 27/10. |
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| 34. |
find the differentiation equation of y=5x*4+6x*3/2+9x |
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| 35. |
Solve thequadratic equation x2 + 6x = 0by perfect square method.Q.7. |
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Answer» Givenx^2 + 6x=0 Ifx^2and6xare the first two terms of a squared binomial:(x+a)^2=(x^2+2ax+a^2) Then (since2ax=6ax)=> a=3and the third term must bea^2=9 So we need to add9(to both sides) to "complete the square"x^2+6x+9=9 Rewriting as a squared binomial(x+3)^2=9 Taking the square root of both sidesx+3=±√9=±3 x=6orx=0 (Note that, in this case, the solution would be simpler to determine by factoring). but ye question me yhiii formula uss krrke bnaynge yaa firre factorize krrkke bnaa sakte haiii i am confused pllzz??? |
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| 36. |
12.Find the area of the following figure3cm3cm4cm |
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| 37. |
3c0s55° 4(cos 70°cosec 20°)" 7sin 35° 7(tan 5°tan 25°tan 45°tan 65°tan 85/°) |
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Answer» GIVEN3cos55 / 7sin35 - 4/7(cos 70 cosec 20 ) / (tan5 tan25 tan45 tan65 tan85 ) USEtan x = cot (90-x)cot x = tan (90-x)sin x = cos (90-x)cos x = sin (90-x) = [3 (cos55 / 7cos55)] - 4[(cos70 / sin20)] / 7 [tan5 tan25 tan45 tan65 tan85]= (3 / 7) - 4 / 7(tan5 cot5 tan25 cot25 tan45)= 3/7 - 4/7-1/7 please like the solution 👍 ✔️👍 |
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| 38. |
(i) 90° into radians |
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| 39. |
Example 11.1. Find 37,% of 240 |
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Answer» 37.5 percentage of 24037.5*240/100= 90please like the solution 👍 ✔️ |
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| 40. |
6x-8 25x 3 |
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Answer» Solving the above equation,3(6x-8)=2(5x) 18x-24=10x 8x=24x=24/8 =3 |
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| 41. |
Q.1. The angles of a triangle are in A.P and the ratio of the number of degreein the least to the number of radians in the greatest is 60:T .Find theangles of the triangle in degrees and radians. |
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| 42. |
If two tangents drawn from a point P to the parabola y2 4x are at right angles, then the locus of P is(A) 2x + 1=0(B) x =-1(C) 2x-1(D) x = 1 |
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| 43. |
3. A trapezium PQRS has two right angles at P and S.Measurement in centimeters are given as shown inthe figure. Find the area of the trapezium.. 20 cmP29cm |
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| 44. |
3 cos 55° __fi_______i‘ 4 (cos 70° . cosec 20°)___________'_._______.________________.___________,..,._______ .7sin 35° 7 (tan5° an25° tan 45°. tan 65°. tan 85° |
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Answer» 3cos55 / 7sin35 - 4/7(cos 70 cosec 20 ) / (tan5 tan25 tan45 tan65 tan85 ) USEtan x = cot (90-x)cot x = tan (90-x)sin x = cos (90-x)cos x = sin (90-x) = [3 (cos55 / 7cos55)] - 4[(cos70 / sin20)] / 7 [tan5 tan25 tan45 tan65 tan85]= (3 / 7) - 4 / 7(tan5 cot5 tan25 cot25 tan45)= 3/7 - 4/7= - 1 / 7 thank you |
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| 45. |
convert -4 radians into degrees |
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Answer» -(4radians) =-229.183118 degree procedure this is easy to find from internet..... I need procedure |
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| 46. |
||5sin 28°2cos51° 7sin 40°का मान क्या होगा?cos62° sin39° cos50°(a) 0(b) 1(c) -1(d) इनमें से कोई नहीं |
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Answer» 5×1+2×1-7×15+2-77-7 =0 Nahi |
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| 47. |
8. If allare the zeroes of the equation 6x +X-2, find |
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Answer» 6x^2+3x-2x-2=3x(2x-1)-1(2 x-1)=(3x-1)(2x+1); x=-1/3; x=1/2; 1/2/1/3+ 1/3/1/2=3/2×2/3=6/6=1 |
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| 48. |
given n( A) =285 ,n(B) = 195,n(U) = 500,n(AUB) = 410, find n( A' U B' ). |
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Answer» n(A) = 285n(B) = 195n(AUB) = 410n(A'UB') = ?n(AUB) = n(A) + n(B) - n(AᑎB)410 = 285 + 195 - n(AᑎB)n(AᑎB) = 480 - 410 = 70n(A'UB') = n(AᑎB)' = n(U) - n(AᑎB) = 500 - 70n(A'UB') = 430 |
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| 49. |
Show that for any sets A and B,A (An B) U (A- B) and AU (B- A)-(AUB) |
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| 50. |
Show that for any sets A and BA (An B) U (A-B) and AU(B-A) (AuB) |
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