3 cos 55° __ﬁ_______i‘ 4 (cos 70° . cosec 20°)___________'_.___

1.	3 cos 55° __ﬁ_______i‘ 4 (cos 70° . cosec 20°)___________'_._______.________________.___________,..,._______ .7sin 35° 7 (tan5° an25° tan 45°. tan 65°. tan 85°
Answer» 3cos55 / 7sin35 - 4/7(cos 70 cosec 20 ) / (tan5 tan25 tan45 tan65 tan85 ) USEtan x = cot (90-x)cot x = tan (90-x)sin x = cos (90-x)cos x = sin (90-x) = [3 (cos55 / 7cos55)] - 4[(cos70 / sin20)] / 7 [tan5 tan25 tan45 tan65 tan85]= (3 / 7) - 4 / 7(tan5 cot5 tan25 cot25 tan45)= 3/7 - 4/7= - 1 / 7 thank you

3 cos 55° ﬁ_i‘ 4 (cos 70° . cosec 20°)_______'_._.____._,..,.___ .7sin 35° 7 (tan5° an25° tan 45°. tan 65°. tan 85°

Answer»

3cos55 / 7sin35 - 4/7(cos 70 cosec 20 ) / (tan5 tan25 tan45 tan65 tan85 )

USEtan x = cot (90-x)cot x = tan (90-x)sin x = cos (90-x)cos x = sin (90-x)

= [3 (cos55 / 7cos55)] - 4[(cos70 / sin20)] / 7 [tan5 tan25 tan45 tan65 tan85]= (3 / 7) - 4 / 7(tan5 cot5 tan25 cot25 tan45)= 3/7 - 4/7= - 1 / 7

thank you