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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
6x-13x+6x=0 |
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Answer» 6x - 13x + 6x = 0 12x - 13x = 0 -x = 0 x = 0 |
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| 2. |
Only for geniusDid you know? |
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Answer» shoes=10 man=5durbeen =4 then the answer is 19 is correct answer by using BODMAS rule5+5×2 =5+10=10 shoes:10man:5binoculars:4So,shoes+man+binoculars=10+5+4=19,it is the correct answer. shoes=10, man =5, durbeen=4; answer is 19 shoes=10man=5durbeen=4then,10+10+10=305+5+10=204+4+5=1310+5×4=60 Right answer is 5+((10+5+4)*2)=43 pair of shoe = 10 then one shoe = 5 man = 5pair of durbeen = 4one durbeen = 2 one shoe + one man and 2 durbeen + durbeen = 22 or 16 Shoes=10Man=5Durbin=4All=19 12 is correct answer Shoe 5Man 5Teliscope 2Then a/q to que5+5*2=15 12 is right answer plz like |
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| 3. |
only for Genius20 |
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Answer» 5*5=25Is it correct? 😜 5*2=105*3=155*4=205*5=25 is qustion ka answer 1 hai 5*2=105*3=155*4=205*5=25 is question ka answer hai 25 25 is the answer because 2×5=103×5=154×5=205×5=25 |
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| 4. |
Solve: 6x + x - 2 - 0* *:- 6x + x - 2 - 0 |
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Answer» 6x² + x - 2=6x²-3x+4x-2=3x(2x-1) +2(2x-1) = (2x - 1)(3x + 2) |
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| 5. |
Example 37 Find cos 6x y1 +sin 6x dx |
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| 6. |
1÷3(6x+4x+9)=1÷2 (x+6x+4) |
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Answer» the as answer isx =19/16 |
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| 7. |
Two angles P and Q form a linear pair. If ZP = 144ยบ and ZQ = 5x + 16ยบ find the valueof x and hence the angle Q. |
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| 8. |
The angles of a Quadrilateral are in A . P andgreatest is 1400 . Express the angles in radians. |
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Answer» Let the angles be=a,a+d,a+2d,a+3da+3d=1404a+6d=360On solving we geta=40d=33.33Angles are 40,73.33,106.66,140 |
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| 9. |
) (x + 5) 5) (b) ((6x+4) (6x - 4) (f) (x-7b) (x+7b)2x+y) (2x+ y) |
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| 10. |
If 6x+13x-8 26x +1 5then the value of (2x+1)4x +2is |
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| 11. |
if sinx+cosx=m, then prove that sin^6x+cos^6x=4-3(m^2-1)^2/4 |
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Answer» here in solution, a = m |
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| 12. |
Two wires of the same metal have samelength, but their cross-sections are in the ratio 3 :1 . They are joined in series. The resistance of thicker wire is 10 Ί. The total resistance of the combination will be40 |
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| 13. |
urį ysa d T are points on sides PR and QR ofaPQR such that ZP-4TS, show that Δ RPQ-ARTS |
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| 14. |
Only forgenius ??3-3x6+2=??Answer |
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Answer» 2 is the answeror 0 3-3×6+2=17 is the right answer 3-3×6+2=-17 is the right answer sorry for the upper ANS. -13 is the right answer 3-3×6+2=0×6+2=0+2= 2 2 is a correct answer -13 is the correctly answer. bro correct answer is 0 3-3×6+2=3-18+2=3-20==-17 3-3×6+2=8 is the answer 3-3×6+2=3-3=0×6=0+2=2 17 is the current answer -17 is the correct answer 3-3x6+2= 17 is the right answer sorry.! 3-3x6+2 = -13 is the right answer. 17 is correct answer because we can use VBODMAS rule bro is the best answer is 0 -17 answer of this question -17 is the best answer me -17 is the best answer -13 is the correct answer -13 is correct answer. -13 is the right answer 3-3×6+2=3-18+2= -13 is the right answer -13 is the correct answer -13 answer carect hai to like kardo please |
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| 15. |
In Fig 6.17, POQ is a line. Ray OR is perpento line PO. OS is another ray lying betweeOP and OR. Prove thatIt is given that ZXYZ 64° and XY is prto point P. Draw a figure from theinformation. Ifray YQ bisects ZZYP, findand reflex ZOYP |
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| 16. |
८०5 #-प्म्ल ८्ठ-ऊत्ठें इ . . 0 — 91 NG = NG, 1nc2N e : |
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| 17. |
downIn the given figure, AC is a diameter of the circle with centre O. Chord BD is perpenangles p, q and rin terms of x.19. |
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| 18. |
3 7(d)305cm4cm2.5cmFind the perimeter of the following figure1cmAcm2.5cm(a) 15cm (b) 15cm2 (c) 16cm (d) 25cm0.5cm |
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Answer» Perimeter = 1 + 4 + 4 + 0.5 + 0.5 + 2.5+2.5= 15 cm |
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| 19. |
the following figures1. Find the perimeter of each of the fo2cm4cm1cm23 cm15 cm5cm |
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Answer» 12 12 CM is the answer because 2 multiply (l+b) so answer is 12 a) 4+2+1+5 = 12 cm b |
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| 20. |
and aNBC are similar Justily('0AΔABC is an equilateral triangle having each side 4cm. Then findarea of Δ ABC?II. Answer the following questions |
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| 21. |
Q8.Two cubes each of side 4cm are joined end to end. Find the surface areaof the resulting cubiod. |
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| 22. |
6 Find the area of an equilaterai triangle of side 4cm. |
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Answer» Area=√3*side/4=√3*4/4=√3cm^2 Area=√3*side/4=√3*4/4=√3cm^2 |
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| 23. |
33 Find total surface area of a cube of side 4cm |
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Answer» Total surface area of cube = 6a^2=6 (4)^2=16×6=96 cm^2 Hit like if you find it useful! |
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| 24. |
2)AB = 5cm , BC : 4cm , AC- 6cm State with reason whether it is possible to drawÎ ABC or not |
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| 25. |
3x6ind h and32. in the given figure, CDILA&DEIAC. Find the length of CL if, BE=4cm & EC=2cm. |
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| 26. |
: In a right APQR, right angled at Q, PQ- 4cm andLPRQ 300. Find the length of sides PR and QR |
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| 27. |
construct a parallelogram EASY in which EA=6cm,EY=4cm and AY=3cm |
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Answer» steps for construction1. as parallelogram have equal side take ruler draw YS of length 6 cm.2. use compass scale it to 4 cm point at S and draw an arc of 4 cm do the same from point Y.3. Again use compass scale it to 3 cm and cut an arc from Y to above of S the intersection of previous arc and new is point A join all the points.4. draw line segment that cuts arc opposite from A to E .5. We have requried parallelogram EASY. |
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| 28. |
8. A cuboid of dimensions 10 cm by 2 cm by 2 cm is divided into 5 cubes of edge 2 cm.F ind the ratio ofthe total surface area of the cuboid and that of the cubes |
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Answer» Total surface area of cuboid = 2(10x2 + 10x2 + 2x2)= 2(20+20+4)= 2(44)= 88 cm^3 Total surface area of one cube= 6x(2x2)= 6x4= 24 cm ^3 For 5 cubes total surface area = 5x24 = 120 Ratio = surface area of cuboid / surface area of 5 cubesRatio = 88/120= 11/15 |
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| 29. |
17.Find the perimeter of the figure.2cm寸4cm4cm4cm4cmm2cm |
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Answer» Perimeter of whole figure=4×(4+2+4) cm=4×10 cm=40 cm |
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| 30. |
08. Find the perimeter of the figure. I fez šrafa cruzamera14cm4cm |
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Answer» Its 3/4 th of a circlesowe knowव्रत का परिमाप होता है= 2πrक्योंकि यह 3 बटा 4 भाग हैso3/4*2πr3/4*4*2*π6π thanks |
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| 31. |
17 Find the perimeter of the figure.20m4cm4crm4cm4cm2cm |
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Answer» Perimeter of whole figure=4×(4+2+4) cm=4×10 cm=40 cm |
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| 32. |
6. M and N are points on the sides PQ and PR respectively of a Δ PQR. For each of thefollowing cases, state whether MN II QR() PM-4cm, QM-4.5 cm, PN 4cm, NR 4.5cm(ii) PQ 1.28 cm, PR-2.56 cm, PM 0.16 cm, PN 0.32 cm |
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| 33. |
O11 Salve by factorisation120 OR 3012 ls the fig DE BC If AD-4cm DB-on andAD# 4cm D8-8cm |
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| 34. |
find area side 4cm |
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Answer» 16 cm^2 is the correct answer of the given question given side of the square = 4 cmArea of the square = side ^2 =(4)^2 =16cm^2 16 cm^2 is the answer |
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| 35. |
Ler, A, B, C D be four non-empty sellIfAgC,Show that A Ă Bcc-8 |
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Answer» Simple answer you have take it |
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| 36. |
Three cubes of length 4cm arejoined end toend Findh |
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| 37. |
1. Deepankar purchased an old scooter for? 12000 and spent2850 on its over-hauling. Then, he sold it tohis friend Ankit for R 13860. How much percent did he gain or lose?ă56 and sold them at 35 per dozen. Find his gain or loss percent. |
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Answer» CP = 12000 + 2850 = 14850 SP = 13860 CP > SO LOSS = 14850 - 13860 = 990 LOSS PERCENTAGE = 990*100/14850 = 6.67% |
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| 38. |
11. A buys car for100,000 and sell it to B at a profitof 10%, B sells it back to A at a loss of 10%. Thenin the deal(a) A loses 1000 A makes 11.0000 |
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Answer» A buys car for Rs 100000 B buy car from A at price =100000(1 + 10/100)= 100000(11/10) = 110000 B sells car to A at price = 110000(1 - 10/100) = 110000*9/10 = 99000 Therefore, A loses = 100000 - 99000= Rs 1000 (a) is correct option |
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| 39. |
eatCeat |
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Answer» By principle of method of mixtures,Assuming that no heat is lost,Heat lost by hot body = Heat gained by cold body. Given, Heat lost by hot body is m x c x (t-t3)(because it is at higher temperature) And Heat gained by cold body is m2 x c2 x (t3-t2) Now,m x c x (t-t3) = m2 x c2 x (t3-t2)mct - mct3 = m2c2t3 - m2c2t2mct + m2c2t2 = m2c2t3 + mct3t3(m2c2 + mc) = mct + m2c2t2t3 = (mct + m2c2t2)/(mc + m2c2) |
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| 40. |
6. A certain sum amounts to R 3,825 in 4 Vand to4,050 in 6 years. Find the rate percent |
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Answer» Simple interest for 2 years = Rs. 4050 - Rs. 3825 = Rs. 225And simple interest for 4 years = Rs. 225*2 = 450 Rs.So, Principal = Rs. 3825 - Rs.450 = Rs. 3375Now,Simple interest = (P*R*T)/100450 = (3375*R*4)/10013500R = 45000R = 45000/13500Rate of interest = 10/3 %Therefore, Rate of interest is 10/3 % and Principal is Rs. 3375 |
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| 41. |
price. A shopkeeper marked a dinner set for1,000. He sold it at 900. What percentdiscount did he give? |
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Answer» Marked price of dinner set=₹1000Selling price of dinner set=₹900Discount=₹1000-₹900=₹100 Discount percent= (100/1000)*100%=10% |
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| 42. |
In the given figure, AB is height of the boy. CD is height of the tree. BE is shadoboy. DE is shadow of tree. Find height of the tree.279h1.5 cm-9 cm83cm |
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Answer» These two triangles will be congruentso corrosponding part will be in equal proportion |
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| 43. |
13. In the given figure, AB is height of the boy, CD is height of the tree. BE is shadow of thebov. DE is shadow of tree. Find height of the tree.h1.5 cm9 cmB3cmE |
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Answer» thanks |
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| 44. |
uhc leligth oT36 cmO 13 cmD 9 cmcFig 11.25Fig 11.26& AABC is isosceles with AB -AC7.5 cm and BC-9 cm (Fig 11.26). The heightAD from A to BC, is 6 em. Find the area of AABC. What will be the height from Cto AB i.e., CE? |
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Answer» the area of the triangle will be 1/2* base * heightConsidering BC as base , and AD as height, area = 1/2*6*9 = 27 cm²Considering AB as base and CE as height ,area = 1/2 * 7.5 * CESo, 1/2* 7.5 * CE = 27this gives, CE = 7.2 cm |
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| 45. |
. Find the CSA, TSA and volume of a cylinder whose dimensions are(a) Radius of the base(b) D21 cm and height-9 cm60 cmameter of the base = 7 cm and height |
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| 46. |
64y8 is exactly divisible by 3, then the least value of y is |
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Answer» If a number is divisible by 3, then the sum of the digits is also divisible by 3. 6+4+y+8=18+y This is divisible by 3 asyis equal to 0. |
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| 47. |
If 5x6 is exactly divisible by 3,then the least value of x is? |
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| 48. |
Least value of $\left|z+\frac{1}{z}\right|$ if $|z| \geq 3$ is |
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| 49. |
If 5x6 is exactly divisible by 3, then the least value of x is |
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Answer» A number is only divisible by 3 if the sum of all its digits is devided by 3.So 5x6 = 5 + x + 6 = 11 + xLeast nunber devided by 3 is 12So 11 + × = 12Or, x = 12 - 11 = 1So least value of x is 1. |
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| 50. |
YR Y R T i T NG SO, । ने रा18. यदि sec A = cosec B = : 2—3 » 'तब (4 + 8) का मान है |
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