Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

(a) 17(b) 16(c) 1(d) 2

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2 is answer for the following questions

2.

( \text { iii) } ( 12 a + 17 b ) \times 4 c

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(12a+7b)*4c=12a*4c+7b*4c=58ac+28bc

3.

gygroundtiheplainm2lar is 50 cm in diameter and 3.5 m in height. Find the cost of paintingcuyed surface of the pillar at the rate of ?12.50 per m2

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4.

उदाहरण 17.X तथा ज्ञात कीजिए यदि2x +3y =[33] तथा 3x +2x = []

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5.

2x+2y/2x-2y=17/8 find x and y

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thanks bhai

6.

17If 2x +y-17 and xy35, evaluate 8x3-ัƒะท, here?x>y.fi 3

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2x+y=17----------(1)xy=35=>x=35/y----------(2)

Substitute equation (2) in (1);70/y +y=17=>y²-17y+70=0=>y²-10y-7y+70=0=>y(y-10)-7(y-10)=0=>(y-10)(y-7)=0=>y=10 or 7

Now from equation (2);x=3.5 or 5

∴8x³-y³=8(3.5)³-10³ or 8(5)³-7³=-657 or 657

thanks

7.

ple4: Solve the equation 4x +5 17-2x and check the result.

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4x + 5 = 17 - 2x 4x + 2x = 17 - 5 6x = 12 x = 2

If you find this answer helpful then like it.

8.

Find an anti derivative (or integral) of the following functi1. sin 2x2. cos 3x4. (ax + b)25. sin 2x - 4 e3xFind the following integrals in Exercises 6 to 20:6. S14 e ² + 1) dr 7. fx² (1 - 1 2 3 dx9. S(2x² + e*) dx 10. Sve - 1/2 dax12. fr +3 13. Pr - x² + x - 1 de15. SJ (3.17. ((2x² -X-1-dx

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the correct answer is C

Draw an angel of45 using a pair of compasses

my answer is good ok bro

9.

difference between simple interest and compound interest on a certain sum of money for 2 years at a rate of 4% per annum is 20₹ .Find the sum

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10.

x^{4}-8 x^{3}+21 x^{2}-20 x+5=0, the sum of two of the roots beingequal to the sum of the other two.

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11.

12 1ยง+ X =L - XS T LAR

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12.

“Boh Ll LS9 LaR 90€ 2o LipK L bk Wbiiie) sks

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we know by euclide division lemma-: a=bq+r 657=306*2+45 306=45*6+36 45=36*1+9 36=9*4+0 here r=0 so b=hcf hence the hcf of 306,657 is 9 answer

13.

2x+17=80

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2x + 17 = 802x = 87 - 17 2x = 70x = 70/2x = 35

14.

Write the vector equation of the line passing through (1, 2, 3) and perpendicplane r i +2j-5k) +9 0

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15.

NIkhl Lar

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is not i no that answer is but is nakhilam sutar in vedoc maths

16.

3:1 Find the value of n.Find 14 A.M's between 5 and 8 and hence show that their sum is 14 times the A.M.between 5 and 8.

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17.

in5, ABCD is a square with side 22cmanddthe area of the shaded region-U…314)

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it's board questions

18.

Show that the equation x2 + 6x + 6 = 0 has real roots and solve it.

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19.

dthe distance of the point (1line2, 3) from the plane x-y + z-5 measured parallel tothe

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20.

60+5x(16—-8+2)+3 =

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21.

If (3+1,y-)(,), find the values o#x an3) (3 3)dthe set B = 13.4.

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comparing both coordinate givesx/3 + 1 = 5/3x/3 = 5/3 - 1x/3 = 2/3x = 2

y- 2/3 = 1/3y = 1/3 + 2/3 = 1

22.

1. Ajoker's cap is in the form of right circular cone whose base radius is 7cm and height is 24cm. dthe ara of hesthet neqr to10 such caps

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23.

(1) p(x)= x - 3x + 5x - 3, 8(x) = x? - 2

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the answer of this problem remaider is 3

see the answer of this question will be:

24.

Find the sum2,-20, -89,12,184,-37

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The sum of the above given numbers is -542

-542 is the correct answer to this question.

25.

37s37 days4)Nthese38. If 812 2431then find the value of x.1) x =-12) x =-23) x =-34) x =-4.39. Perimeter of a right angled triandle in 00 m Iflu

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81=3^4243=3^5Hence(3^4)^x-2=(3^5)^x-1henceequate the powers4(x-2)=5(x-1)4x-8=5x-54x-5x=-5+8-x=3x=-3

26.

6. Find the value of:i) - 37 -( - 15) - 2

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-37-(-15)-2= -37+15-2=-37+13=-24

27.

Infigure, if DE||BC, then x equals (यदि चित्र में DE||BC है तो ५ बराबर होगा )2cm3cm--- 4cmBE(A) 6 cm(B) 8 cm(C) 10 cm(D) 12.5

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28.

2The difference between the two acute angles of a right angled triangle isradians. Thenthe angles are11 80.1081°, 9。3) 70°,204) 609,30°

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Use sum of the two acute angles in rt tr is 90 deg i.e. pi/2

so if the two angles are 'x' and 'y' then

x + y = pi/2 ( = 90 deg)and

x - y = 2 pi/5 (= 72 deg)

Now solve them and get that x = 81 deg and y = 9 deg

cannot understand answer

y 72deg

29.

4(3-2) + 5x = 6(2x + 8)-12.

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4(3x-2)+5x = 6(2x+8)-12 12x - 8 + 5x = 12x + 48 - 12 5x = 44 x = 44/5

30.

2(x-y) = 35x + 8=14

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31.

22. Whose area is greater? A square of side 4cm or of rectangle, 5cm x 3cm.

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Area of square = side² = 4² = 16 cm²

Area of recatngle = L × B = 5 × 3 = 15 cm²

Area of sqaure is greater

thank you

32.

Example 1: Find the perimeter of each(b) P5cms (c)4cm5cm 3.5cm2cm3cm5cm3cm3.5cmQ5cm3cmIrm t 3 cm + 3 cm 8 cm Ans

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2+3+3=8cm5+5+5+5=20cm4+3+3.5+3.5=14cm

33.

2The equation is x +14=6x+

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So, the equation can be written as x/2-1/5 = x/3 +1/4 => x/2 -x/3 = 1/5+1/4=> x/6 = 9/20 => x = 54/20 = 27/10.

34.

find the differentiation equation of y=5x*4+6x*3/2+9x

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35.

Solve thequadratic equation x2 + 6x = 0by perfect square method.Q.7.

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Givenx^2 + 6x=0

Ifx^2and6xare the first two terms of a squared binomial:(x+a)^2=(x^2+2ax+a^2)

Then (since2ax=6ax)=> a=3and the third term must bea^2=9

So we need to add9(to both sides) to "complete the square"x^2+6x+9=9

Rewriting as a squared binomial(x+3)^2=9

Taking the square root of both sidesx+3=±√9=±3

x=6orx=0

(Note that, in this case, the solution would be simpler to determine by factoring).

but ye question me yhiii formula uss krrke bnaynge yaa firre factorize krrkke bnaa sakte haiii i am confused pllzz???

36.

12.Find the area of the following figure3cm3cm4cm

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37.

3c0s55° 4(cos 70°cosec 20°)" 7sin 35° 7(tan 5°tan 25°tan 45°tan 65°tan 85/°)

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GIVEN3cos55 / 7sin35 - 4/7(cos 70 cosec 20 ) / (tan5 tan25 tan45 tan65 tan85 )

USEtan x = cot (90-x)cot x = tan (90-x)sin x = cos (90-x)cos x = sin (90-x)

= [3 (cos55 / 7cos55)] - 4[(cos70 / sin20)] / 7 [tan5 tan25 tan45 tan65 tan85]= (3 / 7) - 4 / 7(tan5 cot5 tan25 cot25 tan45)= 3/7 - 4/7-1/7

please like the solution 👍 ✔️👍

38.

(i) 90° into radians

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39.

Example 11.1. Find 37,% of 240

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37.5 percentage of 24037.5*240/100= 90please like the solution 👍 ✔️

40.

6x-8 25x 3

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Solving the above equation,3(6x-8)=2(5x) 18x-24=10x 8x=24x=24/8 =3

41.

Q.1. The angles of a triangle are in A.P and the ratio of the number of degreein the least to the number of radians in the greatest is 60:T .Find theangles of the triangle in degrees and radians.

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42.

If two tangents drawn from a point P to the parabola y2 4x are at right angles, then the locus of P is(A) 2x + 1=0(B) x =-1(C) 2x-1(D) x = 1

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43.

3. A trapezium PQRS has two right angles at P and S.Measurement in centimeters are given as shown inthe figure. Find the area of the trapezium.. 20 cmP29cm

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44.

3 cos 55° __fi_______i‘ 4 (cos 70° . cosec 20°)___________'_._______.________________.___________,..,._______ .7sin 35° 7 (tan5° an25° tan 45°. tan 65°. tan 85°

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3cos55 / 7sin35 - 4/7(cos 70 cosec 20 ) / (tan5 tan25 tan45 tan65 tan85 )

USEtan x = cot (90-x)cot x = tan (90-x)sin x = cos (90-x)cos x = sin (90-x)

= [3 (cos55 / 7cos55)] - 4[(cos70 / sin20)] / 7 [tan5 tan25 tan45 tan65 tan85]= (3 / 7) - 4 / 7(tan5 cot5 tan25 cot25 tan45)= 3/7 - 4/7= - 1 / 7

thank you

45.

convert -4 radians into degrees

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-(4radians) =-229.183118 degree

procedure

this is easy to find from internet..... I need procedure

46.

||5sin 28°2cos51° 7sin 40°का मान क्या होगा?cos62° sin39° cos50°(a) 0(b) 1(c) -1(d) इनमें से कोई नहीं

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5×1+2×1-7×15+2-77-7 =0

Nahi

47.

8. If allare the zeroes of the equation 6x +X-2, find

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6x^2+3x-2x-2=3x(2x-1)-1(2 x-1)=(3x-1)(2x+1); x=-1/3; x=1/2; 1/2/1/3+ 1/3/1/2=3/2×2/3=6/6=1

48.

given n( A) =285 ,n(B) = 195,n(U) = 500,n(AUB) = 410, find n( A' U B' ).

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n(A) = 285n(B) = 195n(AUB) = 410n(A'UB') = ?n(AUB) = n(A) + n(B) - n(AᑎB)410 = 285 + 195 - n(AᑎB)n(AᑎB) = 480 - 410 = 70n(A'UB') = n(AᑎB)' = n(U) - n(AᑎB) = 500 - 70n(A'UB') = 430

49.

Show that for any sets A and B,A (An B) U (A- B) and AU (B- A)-(AUB)

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50.

Show that for any sets A and BA (An B) U (A-B) and AU(B-A) (AuB)

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