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3c0s55° 4(cos 70°cosec 20°)" 7sin 35° 7(tan 5°tan 25°tan 45°tan 65°tan 85/°) |
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Answer» GIVEN3cos55 / 7sin35 - 4/7(cos 70 cosec 20 ) / (tan5 tan25 tan45 tan65 tan85 ) USEtan x = cot (90-x)cot x = tan (90-x)sin x = cos (90-x)cos x = sin (90-x) = [3 (cos55 / 7cos55)] - 4[(cos70 / sin20)] / 7 [tan5 tan25 tan45 tan65 tan85]= (3 / 7) - 4 / 7(tan5 cot5 tan25 cot25 tan45)= 3/7 - 4/7-1/7 please like the solution 👍 ✔️👍 |
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