This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
zind thi square heat of th2.12 |
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| 2. |
| क्या74. निम्नलिखित का मान ज्ञात कीजिए16/15]7 | ND7 | NDहै, तोकतनीरहे?(d) इनमें से कोई नहीं |
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| 3. |
nd16. If 2x4ind:2xnd8xnd |
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Answer» 2x – 1/2x = 4Cubing on both sides(2x – 1/2x)³ = 4³8x³ – 1/8x³ –3×2x×1/2x×(2x–1/2x) = 648x³ – 1/8x³ –3×4 = 648x³–1/8x³ = 64+128x³ – 1/8x³ = 76 |
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| 4. |
nddy |
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Answer» chl thik h bsdk sale 8 class ka student 12 k problem solve kraa h ranchodas |
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| 5. |
nd thev |
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Answer» sin(105) = sin(60+45) = sin60cos45+cos60sin45= √3/2*(1/√2)+1/2*(1/√2)= (√3+1)/2√2 similarly cos(105) = cos(60+45) = cos60cos45-sin60sin45= 1/2*(1/√2) -(√3/2)(1/√2)= (1-√3)/2√2 tan105 = sin105/cos105 = √3-1/1-√3 strcature |
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| 6. |
0 प्य5 68०3 +1SO Tt S e .6 DT 950 I o+ g Ui उष्पा ००णत g |
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| 7. |
9 9_ soo+— UiT x*e ev 9 £5 ey — : ०8% o 5096 |
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Answer» Do like this |
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| 8. |
40o cundnd |
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Answer» CP of article = 400SP of article = 350 Loss% = (CP - SP/CP)*100 = [(400 - 350)/400]*100 = (50/400)*100 = 12.5 % thanks.... |
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| 9. |
B vd e TS Y |
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Answer» dono triangle ko similar Karke prove kar bhai |
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| 10. |
Ui Fhom the o o 7 m Aigh Budklivg A1 रूपi न the bop efotorseh 4 6o andthe व. थ्फू 3/oot e the Forset s 30. Favel the hoaghs e |
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| 11. |
will be a white ballto each other at an angle UI 0e put into the bag, 28. The angle of elevation of the jet fighter trom agthe white ball willFind xowing distribution:point A on the ground is 60°. After flying for10 seconds, the angle changes to 30°. If thejet is flying at a speed of 648 km/hr, find theconstant height at which jet plane is flying.Frequency |
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Answer» let A be the observation point. and let B and C be the two positions of jet fighter. it takes 15 sec. to reach the point C from B. let the height of the jet fighter from the ground be BE = CD = h km the speed of the jet = 648 km/hr =648000m/hr distance = speed*time therefore BC =648000*15/60*60=2700m in the right angled triangle BEA, tan60=BE/AE√3=h/AEAE=h/√3km....1 in the right angled triangle CDA, tan30=CD/ADAD=√3hkm.....2 AD = AE+ED = AE+BC √3h=h/√3+2.72h/√3=2.7h=2.7/2√3km=2.33km thus the height of the jet fighter is 2.598 km . |
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| 12. |
5. Find m so that PoUlS UI6. Show that the roots of the equation x2+2(3a+5) x + 2 (9 a2 + 25) -0 are complex unlessroots 0 |
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Answer» For roots to be complex or real, we have to find the discriminant of the equation so, D = [2(3a+5)]²- 4*(1)*(18a²+50) = 4[ 9a²+30a+25-18a²-50] = 4[-9a²+30a-25] so, so, the value -9a²+30a-25 = -(9a²+25-30a) = -(3a-5)² = -ve of (sqaure) = always -ve so, this value will be always -ve.. but 0 only at a = 5/3. so D will always be -ve.. and hence complex solution.. unless D = 0 at a = 5/3. |
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| 13. |
79 a/ o b - Z? P1(, (0 a Iy { w0y V):)’"’J & V({“’OT'/ q |5... oy 9 et wp wnw |Ui Uy |
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Answer» Speed of man in still water= 6km / h speed of stream( Ss) = 1.2 km /h speed downstream(Sd) = speed of man in still water + speed of stream =6 + 1.2 = 7.2 km /h speed upstream(Su)= speed of man in still water - speed of stream =6 - 1.2 = 4.8 km /h let T = time taken time downstream + time upstream = 1 h Td + Tu = 1 h since ,we know Time = distance/speed , D / Sd + D/Su = 1 D /7.2 + D /4.8 = 1 4.8D + 7.2D = 1 × 7.2 × 4.8 12D = 34.56 D = 34.56 / 12 D= 2.88 km therefore , distance(D) = 2.88 km |
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| 14. |
if exactly half the square is counted , take its area as_______________ |
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Answer» If exactly half the square is counted. the area will be (side)^2/2 |
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| 15. |
xternal diameter of a lead pipe is 2.4 cm and the thickThe emm. Find the weight of a pipe of length 7 m, it being givenbeing gwenthat 1 cu cm of lead weighs 10th of the pipe, h = (7 Ă 100) cm-700 |
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Answer» External diameter = 2.4 cm so external radius of 2.4 cm /2 = 1.2 cm. Since thickness is 2 mm hence inner radius = external radius - thickness = 1.2 cm - 0.2 cm = 1 cm. Height = 700 cm Now the Volume of the Metal = π * h ( externa radius square - internal radius square ) π*700( 1.2² - 1²) or 22*700/7 ( 1.44 - 1 ) = 2200 * .44 = 968 cubic centimeter. Now the weight of the lead = 986 * 10 gram = 9680 gram or 9.680 kilogram. |
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| 16. |
Express the number appearing in the following statements in standard form0) Thickness of a thick paper is 0.07 mm (i) Size of a bacteria is 0.0000005 m (i) 1 micron is epe II.qual to 1000000 |
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| 17. |
(i) 25 mm into cm |
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Answer» 25mm=25/10cm(because 1cm is equal to 10mm)so,25mm=2.5cmis correct answer 2.5 is the correct answer 25mm=25/10cm=2.5cm answer 2.5 Cm is the correct answer. 2.5cm is the right answer 2.5 cm is the right answer 25mm=2.5cm because 1cm=10mm 2.5cm is the correct answer 2.5 is the correct answer |
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| 18. |
Find the principal if the compound interest payable annually at 10% per annum for3 years is 1331. |
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| 19. |
504.Grass in a lawn grows equally thick and at a uniformrate. It takes 24 days for 70 cows and 60 days for30 cows to eat the whole of the grass. How manycows are needed to eat the grass in 96 days?(a) 18(c) 24(e) of these(b) 20(d) 36 |
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Answer» 24 days 70 cows ==total work done=24*70=1680 60 days 30 cows === total work done= 60*30= 1800 Now see here that total work done must be the same but there is a difference . that difference corresponds to the increasing grass/day ie. work done by grass work done by grass =1800-1680 =120 (this work is done in (60-24=36 days). work done by grass per day =120/36= 10/3 now work done by grass in 24 days= (10/3)*24=80 actual work = 1680 -80 = 1600 now work done by grass for 96 days = (10/3)*96== 320 total work required to be done = 1600 + 320 = 1920 cows required = 1920/96 == 20 |
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| 20. |
26. A boy is now one-third as old as his father.After 12 years, he will be half as old as hisfather. Find their present ages. |
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Answer» where did ranga go to study |
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| 21. |
here was a 12-00 increase in the numberof new admissions to a school in 2012 comparedto the year 2011. If the number of new2. T2admissions in 2011 was 112, find the number ofnew admissions in 2012 |
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Answer» 12.5% incrementin 2011 students are=112so in 2012 students are=112*(1.125)=126 |
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| 22. |
Ram had 14 mangoes and Raj had only 4,Ram gave some mangoes to Raj and then Raad exactly half the number of mangoes aRaj left with. Find the number of mangoeswhich Ram gave to Raj |
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Answer» If Ram gives 1 mango (leaving 13 mangoes with him), Raj has 5 mangos. 5 is not the half of 13. If Ram gives 2 mangoes (leaving `12 with him), Raj has 6 mangoes. 6 is the half of 12, therefore 2 is the answer |
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| 23. |
Ram's father is 3 times as old as Ram. 5 years ago, Ram's father was 4 times as old asRam. What are their ages now? |
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Answer» Let Ram's present age be xHis father's present age will be 3x 5 yrs ago,3x-5 =4(x-5)3x-5 =4x-2020-5 =4x-3xx=15 Thus,Ram's present age us 15 yrs and his father's age is 45 yrs.. |
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| 24. |
7. Ram has 60 more one rupee coins than five-rupee coins. The total value of the money is 2 360How many five rupee coins Ram has? |
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| 25. |
3500 is divided among Ram, Juhi and Ron such that Ram gets 300 more than Juhi" and Ron gets double of Ram's share. How much did each person get? |
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| 26. |
to16,000 to Ram at the rate of 12 9 % per annum compound interesount payable by Ram to Raheem after 3 years.9. Raheem lent FFind the |
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| 27. |
(3) 4 km 9 cm 25 mm into m |
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| 28. |
equally distributed as a New Year bonus for 25 employees of a compaHow much did each receive? |
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Answer» 2,500will be distributed to each one 2500 is the correct answer of the given question 2,500 will be distributed to each each employee recieve Rs 2500 each employee get 2500 |
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| 29. |
Srijith decided to spend 45% of his salary on traveling forleisure. Last year he spent 1,35,000. This year he got a raiseof 15%. Calculate Srijith's new salary. |
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| 30. |
In what ratio must rice at9.30 per kg be mixed with rice atR10.80 perkg so that the mixture bworth ? 10 per kg ? |
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| 31. |
The average age of25 boys in a class decreases by 6 months when a new boy takes the place of a 20year old boy. Find out the age of new boy? |
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Answer» Let age of the new boy was X. Age decreased = 6 months = 6/12 = 1/2 years Now, we have formula for this type of questions, Number of members in the Group * age decreased = difference in ages of boy in and boy out. 24 * (1/2) = 20 -X X = 8 years. Thought process method: Total age decreased = 6 *24 = 145 months = 12 years. It means the difference of the ages between boy in and out would be = 20 - 12= 8 years answer is not correct from given options:a. 7b. 6c. 6.5d. 7.5 |
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| 32. |
8 FHow many kilograms of tea, worth 300 per kg should be mixed with 10 kg of tea worth tg to produce a mixture to cost 260 per kg?per |
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| 33. |
500500 =10x + 25 |
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Answer» -12490 is the correct answer -12490 is a right answer -12490 is correct answer -12490 is a great answer pls chak may question -12490 is correct answer of this question -12490.................. -12490 is correct answer -12490 is the answer for your question -12490 is the correct answer -12490 is the correct answer _12490 is the correct answer -12490 is your answer -12490 is a right answer -12490 is the correct answer of this question 25 is right ans of this question -12490 is correct answer office this question -12490 is correct answer yes -12490 is the correct answer -12490 is right answer -12490 is the right answer -12490 is the correct answer of this question 500/x-500/x+25=10The answer is - 12490. x = -12490 is the best answer. x=25 or x=-50 is correct -12490 is awesome answer -12490 is the best answer x=12,-50 are the solutions (x+25)500 - 500x/x^2+25x =10=> 500x+12500-500x =10x^2+250x=> 10x^2 + 250x + 12500 = 0=> x^2 +25x +1250 = 0x(x+25) x(x+50)-25(x+50)(x+50) (x-25) so that,x = -50 andx = 25 is the ans -12490 is a answers so friends next time I will be better -12490 is the right answer x= -12490 is right answer x= 25 is the answer of this question -12490 is the final and right answer -12490 is right answer -12490 is right answer for this question- -12490 is the correct answer because its a linear equation -12490 is the correct answer ok -12490 is the best anawer -12490 -12490 is correct answer according to your question X=12490 is the right answer 30 is the correct answe -12490 ,this is correct answer -12490 is the correct answer -12490 is correct answer. -12490is the correct answer -12490 is the correct answer of your question -12490 is the answer -12490 is the best answer me -12490 is the right answer The answer is -12490. -12940 is correct answer according to your question 500(x+25)-500x/x(x+25)500x+500*25-500x/x²+25x12500/x²+25x12500/x(x+25) -12490 correct hai bha -12490 is exact answer -12490 is crt answer - 12490 correct answer answer of this question is -12490 |
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| 34. |
How much chicory at Rs. 4 a kg should be added to 15 kg of tea at Rs. 10 a kg so that themixture be worth Rs. 6.50 per kg?(A) 15 kg(B) 18 kg(C) 12 kg(D) 21 kg0000 |
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Answer» answer is the (D) 21kg 21kg is the correct answer the correct answer is options D (21kg) option d is the correct answer of the given question answer D is right 21kg |
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| 35. |
the selling price, when:-7 360 and gain%-2%(a)ICP |
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Answer» Selling price = (100+2)/100 * 360= (102/100)*360= ₹ 367.2 Please hit the like button if this helped you |
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| 36. |
5 Anthony saved $500 to redecorate hisapartment. He purchased a chair for $278and a lamp for $89. He also wants topurchase a rug. Which equation can beused to find how much money Anthonyhas left to spend on a rug? $500 + $278 + $89 = $867® $500 + $278 - $89 = $689© $500 - $278 - $89 = $133o $500 + $89 - $278 = $311LEGAL TO COPY |
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Answer» the answer is c 500-278-89=133 option c because in this question he save 500 at first time and he bought |
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| 37. |
. The unit digit in (795- 358) isb) 6d) 7 |
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Answer» If you see the power of 7 then you will notice a sequence: 7¹=7 7²=49 7³=343 7⁴=2401 7⁵=16807 7⁶=117649 And the unit digits keep on repeating as { 7, 9, 3, 1 } It repeats after every 4 powers , So divide 95 by 4 You will get 3 as the remainder . The third number in the series is 3. This implies the unit digit of 7⁹⁵ is 3 . Similarly, do for 3⁵⁸ 3¹=3 3²=9 3³=27 3⁴=81 3⁵=243 And the unit digits keep on repeating as { 3, 9, 7, 1 } Now divide 58 by 3 and get the remainder as 2 Second number in the series is 9. This implies unit digit of 3⁵⁸ is 9 Unit digit of 7⁹⁵−3⁵⁸ = 3−9 = 13-9 (borrow from the previous digit) = 4 Hope this helps ! Thanks ! Please like the solution 👍 ✔️ |
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| 38. |
\frac{3^{502}-3^{500}+16}{3^{500}+2} |
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| 39. |
i))30% of 200 + 207610% ofă450-12% of500 + 8% of500 |
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Answer» 10% of 450 - 12% of 500 + 8% of 500 = 10×450/100 - 12×500/100 + 8×500/100 = 45 - 60 + 40 = 85 - 60 = 25 If you find this answer helpful then like it. |
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| 40. |
20+358 |
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| 41. |
2+358 en inration)oneve that |
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Answer» 2+3V2 (2-3V2)/2-3V=4-6V3+6V3-9.2=4+18=22 |
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| 42. |
विस संपा को ज्ञात कीजिए।358 12 1.(५)(C)(D) 10 |
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Answer» this question is belongs to reasoning.every two number has a difference of series numbers.as2+1=33+2=55+3=88+4=1212+5=1717+6=23 so the answer is 23 23 is correct answer of following question 23 is the right answer of the following C) 22 is correct answer 23 is right answer plz like my answer |
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| 43. |
1. Find largest and smallest saigist number adivisible by 358 and 12 |
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Answer» largest 12, 8, 5, 3 smallest 3,5,8,12 |
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| 44. |
ind in metres the height of a pile of 25 books if each book is 3 cm 9 mm thi |
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Answer» height of one book=3cm9mm=39mmtherefore height of 25 books= 39×25=975mm=0.975m thanks |
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| 45. |
its an ace or a king b. its a numeric spadècoin is tossed three time then write all possible outcome and find probability of getting aat least 2 heads.all headsb. |
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Answer» Each coin toss has two possible outcomes: Heads (H) and Tails (T). For k tosses, there are 2^k outcomes. Therefore, there are 2^3=8 possible outcomes when a coin is tossed three times. We can list the 8 outcomes as follows: HHH,HHT,HTH,HTT,THH,THT,TTH,TTT i) all heads = 1/8 ii) atleast two heads = HHH,HHT,HTH,THH = 4/8 = 1/2 |
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| 46. |
40. A conical vessel, with base radius 5 crand height 24 cm, is full of water. Thiwater is emptied into a cylindrical vessof base radius 10 cm. Find the height t |
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Answer» Internal radius of conical vessel = 5 cm Height = 24 cm Since the conical vessel is full of water, so volume of water = volume of vessel So, volume of water = 13πr2h = 13×227×52×24 = 44007 cm3 Now, this volume of water is emptied in a cylindrical vessel. So, suppose the height of level of water in the cylindrical vessel is h. and radius of base of cylindrical vessel = 10 cm So, volume of water in cylindrical vessel up to height h = π×102×h = 44007 cm3 ⇒227×100×h = 44007⇒h = 440022×100 = 2 Therefore, height of water level in cylindrical vessel = 2 cm |
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| 47. |
perimeter of each square whose one side is given as(b) T0 cm(e) 100 m 45 cmcm |
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Answer» b) perimeter of square is 4 * side length so answer is 10*4=40 cm |
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| 48. |
A ylindrical pillar is 50 cm in diameter and 3.5 m in height. Find the cost of paintingthi curved surface of the pillar at the rate of Rs 12.50 per m2 |
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| 49. |
rage NDauut |
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Answer» Like if you find it useful |
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| 50. |
rageसनी----का जलेरख रखीविरे । |
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Answer» jay mataje jay mataje jay mataje jay mataje jay mataje |
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