This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
7. The sale receipt of a company during a year was6709570. What was the total sale receipt of the company during these two years?.-07E0204 If the number of males is 16987059, find the |
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| 2. |
fe CJU? 9 रि0 51 कर. न! 02८80 -+ha 4te divisible ba & |
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Answer» Suppose n is 3 which is oddthen according to the questionn^2-1= 9-1= 8which is divisible by 8another exampletake n = 5then 25-1= 2424/8= 3so it's proved thanks |
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| 3. |
A company manufacture cars, in year 2006 company manufactured 2000 cars and in next yearcompany manufactured 2200 cars. What is the percentage of increase of cars? |
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Answer» In year 2006 cars manufactured = 2000 In year 2007 cars manufactured = 2200 Therefore, Percentage increase of cars= [(2200 - 2000)/2000]*100= (200/2000)*100= 100/10= 10% |
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| 4. |
d)8,000forlyear at 9% per annum compounded haIf yearly.(You could use the year by year calculation using SUformulatveritiv |
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Answer» P=8000R=9%compounded half yearlyso A=P(1+R/200)^2=8000(1+9/200)^2 =8000×1.045×1.045=8736.2so interest=8736.2-8000=736.2 |
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| 5. |
what will be the eugt lA cylinder and a cone have equal radi of their bases and equal heicurved surface areas are in the ratio 8 :5, show that the radius of each is to theof each as 3:4LEVEL.2 |
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| 6. |
. In an isosceles triangle, the vertex angle is 50°. What are the base angles of the triangle? |
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Answer» Every triangle has180 degrees. An isosceles triangle has one vertex angle and two congruent base angles. Thus, 65 is the base angle and 50 is the vertex angle. |
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| 7. |
q theghthei hhen |
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| 8. |
3. In an isosceles triangle, the vertex angle is 50°. What are the base angles of the triangle? |
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| 9. |
Vol DI Btb ‘g X= ( % e |
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Answer» Given,cot^-1(4/3) = xCot x = 4/3 tan x = 1/cot x = 3/4 We know,cos 2x = (1 - tan^2 x)/ (1 + tan^2 x) = (1 - (3/4)^2)/ (1 + (3/4)^2) = (1 - 9/16)/(1 + 9/16) = (7/16)/(25/16) = 7/25 |
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| 10. |
(vol The cogne, op. constant, bn丿 |
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Answer» In the context of a polynomial in one variable x, the non-zeroconstant functionis a polynomial ofdegree0 and its general form is . Thisfunctionhas no intersection point with the x-axis, that is, it has no root (zero). ... It is the (trivial)constant functionand every x is a root. |
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| 11. |
vol a delex.cosloart |
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Answer» because 6666uwuwgwiw7s9wyhwgw D=2(6*1-9*7)-3(5*1-7*8)+4(5*9-6*8) =2(6-63)-3(5-56)+4(45-48) =-114+153-12 =27 |
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| 12. |
21.The vertex A of △ABC is joined to a point D onthe side BC. The midpoint of AD is E.Prove thatar(ABEC)--ar(AABC) |
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| 13. |
What is Sunset Law? (2) |
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Answer» In public policy, asunsetprovision or clause is a measure within a statute, regulation or otherlawthat provides that thelawshall cease to have effect after a specific date, unless further legislative action is taken to extend thelaw. A law that is passed with a specified date upon which it will expire. Sunset laws are favored by people who disapprove of government intervention and regulation and believe it is a good idea to periodically review whether laws and regulations are still needed. Sunset provisions gained in popularity in the 1970s and 1980s. |
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| 14. |
Preeti is going on her moped at a speed of 24 km/hr. How much time will she take to cover 720 metres. |
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| 15. |
angle abc and angle bde are two equilateral triangle such that d Is midpoint of bc then prove that area (angle abc)=1÷4 area (angle abc) |
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| 16. |
Preeti is going on her moped at a speed of 24 km/hr . how much time will she take to cover 720 meters |
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Answer» the time will she takes to cover 720 meters 30 minutes |
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| 17. |
21. The vertex A of AABC is joined to a point D one sidesw thatthe side BC. The midpoint of AD is EProve that ar(ABEC) = 2ar(AABC).8 |
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| 18. |
The angle between the two altitudes of a parallelogram through the vertex of anobtuse angle is 50°. Find the angles of a parallelogram. |
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| 19. |
The angle between the two altitudes of a parallelogram through the vertex of anobtuse angle is 50°, Find the angles of the parallelogram |
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Answer» thank you |
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| 20. |
isosceles triangle, the base angle is twice as large as vertex angle. Find theangles of the triangle. |
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Answer» In an isosceles triangle , base angles are equal LET vertex angles be xThen, Base angles will be 2x and 2x SUM OF ANGLES OF TRIANGLE IS 180°. Therefore,2x + 2x + x = 180°5x = 180°=> x = 36° ANSWER = VERTEX ANGLE = 36°BASE ANGLES ARE EQUAL TO = 36° × 2 = 72° & 72° |
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| 21. |
vertexangleof an isosceles triangle is 50°, find the otangles. |
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| 22. |
DE is a midsegment of âłABC. Find the value of n.25.n+ 7B 3n+ 12 C Work:n a |
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| 23. |
)In an isosceles triangle, the vertex angle is twice either base angle. (Let the btangle be b in degrees. Remember that the sum of angles of a triangle is 18degrees). |
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| 24. |
the sail camtounigure shows tuo cicies aith the Same centreTRe rad inot largeÎł Civele is 12cm qnd the raelimo smatlarCirtle , s 70m find theomta |
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| 25. |
SRS e e(1) 21m° ता |
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Answer» 21(m)(m) ÷ 7(m) = 3(m) |
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| 26. |
3.Find the area of the shaded region in each of the following figures.10.5m42cmHint: +d42d 21.:. side of the square 21 cm21m |
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| 27. |
12" If sin θ끊 , O < θ < 90°, find the value of13sin20-cos2012 sin θ cos θ , tan20[CBSE 2016 |
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| 28. |
39, A right circular cone of radius 3 cm, hasa curved surface area of 47.1 cm2. Findthe volume of the cone. (Use Ď3.14)(24¡60cm"CBSE 2016] |
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Answer» GIVEN: Radius of cone ( r ) = 3 cm, Curved surface area of a cone= 47.1 cm²Curved surface area of a cone= πrl 47.1 = πrl47.1 = 3.14 × 3 × ll = 47.1 / (3.14 × 3)l = 15.7 / 3.14= 1570/314= 5 cm slant height (l) = 5 cm Height of a cone (h) = √(l²) - (r²)h = √ 5² -3²h = √ 25 - 9 = √ 16 = 4 cmh = 4 cm Volume of cone= ⅓(πr²h)= ⅓(3.14 × 3 × 3 × 4)= 3.14 × 12= 37.68 cm³ Hence, the volume of a cone is 37.68 cm³. |
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1. Divide. Write the quotient and the remainder(2) 4(1) 21m+ 7m |
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| 30. |
9. For what value of k will the consecutiveterms 2k 1, 3k + 3 and 5k - 1 form anK 6 [CBSE 2016]A.P.? |
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Answer» We know when a, b, c are in AP then2b = a + c So, here 2(3k + 3) = 2k + 1 + 5k - 1 6k + 6 = 7k k = 6 |
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| 31. |
findliverational numbers between1 and 8 |
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Answer» 43/644/645/6 46/647/6 n =5+1 = 67*6/1*6. 8*6/1*642/6. 48/6 43/6,44/6,45/6,46/6,47/6 |
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| 32. |
1. A bus is moving at a speed of 84 km/hr. How much distance will it cover lI2. Preeti is going on her moped at a speed of 24 km/hr. How much time will she take tacover 720 metres?At what |
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| 33. |
5Findliverational numbers betweenal 2 and35 |
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Answer» answer:-2*15/3*15=30/454*9/5*9=36/4530/40, 31/40, 32/40, 33/40, 34/40, 35/40, 36/40.What have we done? In this sum we make the denominator same, of both the numbers given in the question. If we want more number like more than five then we will have to make the denominator bigger by multiply big numbers. |
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| 34. |
Example 1. The angles of a quadrilateral arein the ratio 3:5:9: 13. Find all the angles of the[CBSE 2012, 2016]quadrilateral. |
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| 35. |
7+345 7-3/53+15 3-5Find the value of a and b if: |
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| 36. |
A horse is placed for grazing inside a rectangular field 70 m by 52 m and is tethered to onecorner by a rope 21 m long. How much area can it graze?52mm2121m P70m |
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| 37. |
S1. S2, S respectively. Prove that:26. The sum of n, 2n, 3n terms of an A.P:, are27 A train travels a distance of 480 km at a uniform speed. If the speed had been 8 km/h less, thenS3 3(82-S1). |
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Answer» Sol:Let ‘a’ be the first term of the AP and ‘d’ be the common differenceS1= (n/2)[2a + (n – 1)d] --- (1)S2= (2n/2)[2a + (2n – 1)d] = n[2a + (n – 1)d] --- (2)S3= (3n/2)[2a + (3n – 1)d] --- (3)Consider the RHS: 3(S2– S1)= S3= L.H.S∴ S3= 3(S2- S1) . |
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| 38. |
9. A rail journey of 75 km costs Rs 215. How much will a journey of 120 km cost? |
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Answer» 75 km --- 215Rs120 km ----xx= (120×215)/75x=344 Rsie for 120 km he need to pay 344 Rs the best answer is 344 Rs cost of 75km. journey=215rs.cost of 1 km. journey=215÷75 rs.cost of 120km. journey=(215×120)÷75=25800÷75=344 rs. ans. 344 rupees is the right answer. 344 is the correct answer of the given question journey 75 km cost = Rs. 215: cost of 1 km = 215÷75rs=2.86. cost of 120 km= (215×120)÷75=25800 ÷ 75=344 rs. Solution :-Cost of 75km of journey =₹215Cost of 1 km = ₹215/75Cost of120km. =( 215×120)/75 = ₹344 Ans. 344rs is the right answer 344rs is the right answer cost of 75km.=215cost of 1km.=215/75cost of 120km.=(215×120)/75=25800/75=344 rs. ans. |
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| 39. |
3. Zind Live rational numbers between 3 end |
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| 40. |
75 km. How14. A motorcyclist travels at 30 km/h and stops for half an hour at the end of everylong will it take him to cover 375 km?15. 4 |
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Answer» Speed =30 km per hour Time taken to cover 375 km =12 hrs 30 mins(12hrs for 360 km and 30 min for 15 kms) Time he stopped = 2hrs (75km , 150 km, 225km,300km = 4 times ) 30 min *4 =120 min =2 hrs Total time taken to complete the journey = 12hrs 30 min +2 hrs = 14 hrs 30 mins |
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| 41. |
25. Four cows are tethered at the four corners of a square field of side 50 mし/ such that each can graze the maximum unshared area. What area willbe left ungrazed? [Take π = 3.14] |
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| 42. |
Four cows are tethered at four corners of a square field of 70 m side as shown in givenfigure so that they can reach each other. What area of the field will remain ungrazed? |
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| 43. |
७,७७४, . Cannot b लक &कि O Sma3 PY e BTS \nl-%_rm - - |
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Answer» Number divisible by 5 can be of the form:- d = 5p + r, where 0 ≤ r <5 If d = 5p, d² = 5m, where m is some integer and m = 5p² If d = 5p + 1, d² = 5m + 1 If d = 5p + 2, d² = 5m + 4 If d = 5p + 3, d² = 5m + 4 If d = 5p + 4, d² = 5m + 1 Therefore, the square of any positive integer cannot be in the form of 5m + 2 or 5m + 3 for any integer "m". |
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| 44. |
oc Katnary' se plot is 20 m. He used half of his plot for keeping hensWhat ares of his plo! is vacarl? |
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| 45. |
23. A horse is placed for grazing inside a rectangular field 70 m by 52It is tethered to one corner by a rope 21 m long. On how much area caaitgraze? How much area is left ungrazed? |
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Answer» nice |
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| 46. |
13. Given that x 5 is a factor of the cubic polynomial plo) -3513x-3,/5Find all the zeroes of the polynomial pix). |
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| 47. |
15+yS+D+then among the following thi13.If mand n#V5yS/5between m &n holds is(A) m+n-1=0(B) m-n-1=0(C) m-n+1=0(D) m+n+1 |
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Answer» good job tell me some more good question |
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| 48. |
3). Eind thi. hunts |
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| 49. |
thi Padi tion ecoloudistiatrana , |
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| 50. |
af the hamgnd the area of ЛАВС, right angled at B in which base is 24 cm and hypotenuse is 25 crn lfBD LACC nd BI |
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