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9. For what value of k will the consecutiveterms 2k 1, 3k + 3 and 5k - 1 form anK 6 [CBSE 2016]A.P.?

Answer»

We know when a, b, c are in AP then2b = a + c So, here

2(3k + 3) = 2k + 1 + 5k - 1

6k + 6 = 7k

k = 6



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