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Ratio of areas = Ratio of sides. 360/250 =8/x36x=8×25x=25×2/9x=50/9 x=5.55 cmThe corresponding side is 5.55 cm

After 12 yrs age of son = xAfter 12 yrs age of father = 3x

Son present age = x - 12Father present age = 3x - 12

Difference of present age= (3x - 12) - (x - 12)= 2x

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Almirah=6590Bed=2624Total=6590+2624=9214

B. 270 may be it is the right answer

360m race because 30+60+84=174174+174= 348so the race.will be 360m

Almirah=6590Bed=2624Total=6590+2624=rs 9214

Suppose shyam has initially x Rs. Now 30% left so 70% spent 70% of x = 280 70×x/100 = 280 x = 400 Shyam initially has 400 Rs.

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Let money he had first was xRsMoney left=30%=30x/100Money spent=280Rs

280+30x/100=x280=x-30x/100=280=100x-30x/100=70x/1004=x/100x=400

He had 400 Rs first

Hari walked more distance.

The difference is

= 4 2/3 - 2 1/4

= 14/3 - 9/4

= 56-27/12

= 29/12

= 2 5/12

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Given, total number of person = 450

and, Number of vegetarians = 175

So, Number of non-vegetarians = 450 - 175 = 275

Therefore,

Probability of the person being non-vegetarian = (Number of non-vegetarians)/(Total number of person)

= 275/450

= 0.611

Hence, Probability of the person being non-vegetarian is 0.611.

(2)2×3×5=is the best Answer

420 is the best Answer

Given, total number of person = 450

and, Number of vegetarians = 175

So, Number of non-vegetarians = 450 - 175 = 275

Therefore,

Probability of the person being non-vegetarian = (Number of non-vegetarians)/(Total number of person)

= 275/450

= 0.611

Hence, Probability of the person being non-vegetarian is 0.611.

GIVEN,THE TOTAL NO OF PEOPLES = 450NO OF PURE VEGETARIAN=175NO OF NON VEGETARIAN =450-175=275PROBABILITY =NO OF FAVOURABLE OUTCOMES/TOTAL NO OG OUTCOMESSO,PROBABILITY =275/450=O.611

0.611

104 × 96=(100+4)×(100-4)=(100)^2 - (4)^2=10000 - 16= 9984

Solving using the determinant property,1(-cos²α-sin²α)-0+0=-1(cos²α+sin²α)=-1(1)=-1

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Let the unit digit be y & tens digit be x.

Original number = (10x+y)

After interchanging the digits

New number = (10y+x)

(10x+y) + (10y+x) = 110

11x +11y = 110

11(x+y)= 110

x+y = 110/11

x+y= 10…………...(1)

x= 10-y……………(2)

(10x+y) - 10 = 4+ 5(x+y)

(10x+y) - 10 = 4+ 5(10)

(10x+y) = 4+ 50+10

(10x+y) = 64

10(10-y) +y = 64

100-10y +y= 64

100 -9y = 64

-9y = 64-100

-9y = -36

y= 36/9= 4

y= 4

putting the value of y in eqn 2

x= 10-y

x= 10-4

x= 6

Hence , the first number is 6 & second number is 4.

Original Number is 10x+y = 10× 6+4= 60+4= 64

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change sin value in cos and cos into sin and cut them you get 1

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The price of the toy car including GST = 1770

Now this price includes 18% GST, so

Let taxable value of toy be P, so

P + 18% of P = 1770

118% of P = 1770

118/100 * P = 1770

P = 1770 * 100 / 118

P = 1500

So, total GST amount = 1770 - 1500

Total GST = 270

For this 18% GST, CGST and SGST are 9% each

or, they are 2 equal halves of total GST

So, CGST = SGST = 270/2 = 135

the least positive integral value of k is 7.

(Cos^3 21°+ Cos^3 39°)/( cos 21 + cos 39°)=(cos 21° + cos 39°)(Cos^2 21° + Cos^2 39° -Cos 21 Cos 39°)/(Cos 21° + Cos 39°)=Cos²21°+Cos²39°-Cos21°Cos39°=1/2(2cos²21°+2cos²39°-2cos21°cos39°)=1/2[1+cos42°+1+cos78°-{cos(21°+39°)+cos(21°-39°)}][∵, 2cos²Ф=1+cos2Ф and 2cosAcosB=cos(A+B)+cos(A-B)]=1/2[2+cos42°+cos78°-cos60°-cos18°]=1/2[(2-1/2)+cos42°-cos18°+cos78°] ; [∵, cos60°=1/2]=1/2[3/2+{2sin(42°+18°)/2sin(18°-42°)}+cos78°] [∵, cosC-cosD=2sin(C+D)/2sin(D-C)/2]=1/2[3/2+2sin30°sin(-12°)+cos(90°-12°)]=1/2[3/2+2.1/2.(-sin12°)+sin12°] ; [∵, sin30°=1/2 and cos(90°-Ф)=sinФ]=1/2[3/2-sin12°+sin12°]=1/2×3/2=3/4

let no.be xthen 5x+8=20-x5x+x=20-86x=12x=2

38220>196 we always divide greater number with smaller one.

Divide 38220 by 196 then we get quotient 195 and no remainder so we can write it as

38220 = 196 * 195 + 0

As there is no remainder so deviser 196 is our HCF

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