will be a white ballto each other at an angle UI 0e put into the bag,

1.	will be a white ballto each other at an angle UI 0e put into the bag, 28. The angle of elevation of the jet fighter trom agthe white ball willFind xowing distribution:point A on the ground is 60°. After flying for10 seconds, the angle changes to 30°. If thejet is flying at a speed of 648 km/hr, find theconstant height at which jet plane is flying.Frequency
Answer» let A be the observation point. and let B and C be the two positions of jet fighter. it takes 15 sec. to reach the point C from B. let the height of the jet fighter from the ground be BE = CD = h km the speed of the jet = 648 km/hr =648000m/hr distance = speedtime therefore BC =64800015/60*60=2700m in the right angled triangle BEA, tan60=BE/AE√3=h/AEAE=h/√3km....1 in the right angled triangle CDA, tan30=CD/ADAD=√3hkm.....2 AD = AE+ED = AE+BC √3h=h/√3+2.72h/√3=2.7h=2.7/2√3km=2.33km thus the height of the jet fighter is 2.598 km .

will be a white ballto each other at an angle UI 0e put into the bag, 28. The angle of elevation of the jet fighter trom agthe white ball willFind xowing distribution:point A on the ground is 60°. After flying for10 seconds, the angle changes to 30°. If thejet is flying at a speed of 648 km/hr, find theconstant height at which jet plane is flying.Frequency

Answer»

let A be the observation point. and

let B and C be the two positions of jet fighter. it takes 15 sec. to reach the point C from B.

let the height of the jet fighter from the ground be BE = CD = h km

the speed of the jet = 648 km/hr =648000m/hr

distance = speed*time

therefore BC =648000*15/60*60=2700m

in the right angled triangle BEA,

tan60=BE/AE√3=h/AEAE=h/√3km....1

in the right angled triangle CDA,

tan30=CD/ADAD=√3hkm.....2

AD = AE+ED = AE+BC

√3h=h/√3+2.72h/√3=2.7h=2.7/2√3km=2.33km

thus the height of the jet fighter is 2.598 km .