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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Exercise 48Divide:1 3.24 by 0. |
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Answer» Division 3.24/0.6 Change to fraction 3240/100 cancel using 10 324/10 32.4 |
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| 2. |
ing at the top of a temple which is 30 meter in height from a pointof theat certain distance. The angle of elevation from his eye to the top of the crowntemple increases from 30° to 60° as he walks towards the temple. Find the distance hewalked towards the temple. |
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Answer» Boy is at AB. The temple is PQ. Angle of elevation changes from 30 to 60 as boy's head (eyes) move from B to S. We have to find distance x. (= BS) tan B = tan 30⁰ = 1/√3 = RQ / RB = 30 / D => D = 30 √3 meters tan S = tan 60° = √3 = RQ / RS = 30 / (30√3 - x) 30*√3*√3 - x√3 = 30 x = 60/√3 = 20√3 meters. |
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| 3. |
Divide: x2+ x- 6 byx +3Divide: 6x3- 13x2 + 4x + 7 by 2x- 3Divide: r2 +4x + 4 by x + 1 |
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| 4. |
A 1.5 m tall boy is looking at the top of a temple which is 30 meter in height from a pointat certain distance. The angle of elevation from his eye to the top of the crown of thetemple increases from 30° to 60° as he walks towards the temple. Find the distance hewalked towards the temple. |
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Answer» Let AB=CD= EQ = 1.5 mLet dist. covered by boy is BD=xLet BD=AC=xLet DQ=CE=yIn fig. PE=30-1.5=28.5mAngles are 30° and 60°In ∆ PAE tan 30 = PE/AE1/√3=28.5/x+y 28.5√3=x+y –(1) In ∆PCEtan60=PE/CE√3=28.5/yy=28.5/√3 Put in (1)x+28.5/√3=28.5√4x=(28.5×3-28.5)/√3= (85.5-28.5)/√3=57/√3 Rationalize=57/√3×√3/√3=57√3/3=19√3 answer is crct thanks |
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| 5. |
T0. A bridge across a valley is 800 metres lóng. There is a temple in the valley directly belowthe bridge. The angle of depression of the top of the temple from the two ends of thebridge have measure 30 and 6o.Find the height of the bridge above the top of the temple. |
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Answer» by put the values we can find it h= 80 alpha = 30° beeta= 60° |
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| 6. |
13. Deepak is twice as old as his brother Vikas. If the difference of their ages be 11 years, findtheir present ages. |
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Answer» Let the Vikas age be x. Then the age of Deepak will be 2x. Given that difference in their ages be 11 years. 2x - x = 11 x = 11. The age of Deepak will be 2 * 11 = 22 years. Let the Vikas age be x. Then the age of Deepak will be 2x. Given that difference in their ages be 11 years. 2x - x = 11 x = 11. The age of Deepak will be 2 * 11 = 22 years. let the vikas age be xthen the age of Deepak will be 2xdifference in there ages be 11 yrs2x-x=11x=11the age of Deepak will be 2*11=22 yrs let Vikas age = x, deepak age = 2x, their difference ages = 11; 2x -x = 11, x = 11 = Vikas age; Deepak = 11 x 2= 22 age 11 & 22 are the correct answer lets age of deepak is Dage of vikash is Vaccording to question D=2Vthen D-V=11 2V-V=11 V=11and D=2V so D=2×11=22present age of deepak is 22and age of vikash is 11 it should be 11 bc it says 11 years apart let vilas age be x then the age of deepak became 2xaA.T.Q 2x-x=11x=11Therefore age of deepak = 2×11=22 years . Deepak age will be 22 in the question 11 and 22 are the correct answer let vikas age=x years.then Deepak age=2x yearsdifference 2x-x=11 x=11present age of vikas=11yearpresent age of Deepak=2×11 =22 years. 11 and 22 are the present ages Let Vikas age be xThen deepak age will be 2xDifference of there age is 11 i. e 2x-x =11x=11So present age of vikas is 11 years andPresent age of deepak is 22 years Let the vikash age be x.Then the age of Deepak will be 2x.Given that difference in their ages be 11 years2x-x= 11x=11.The age of deepak will be 2×11=22years. Let vikas age be x Then the age of deepaj will be 2x Differece in their ages=11x 2x-x=11 x=11 The age of deepak will be 2*11=22years 22 is the anwer because 11x2 = 22 sooo thats the answer your WELCONEEEEEE let the vikas age be x Athena the age of deepest will be 2xGiven that difference in their ages will be 11 years. 2x-x=11x=11The age of deepak will be 2*11=22 years vikas age = 11deepak age = 22this is the correct answer for this question Thank you 2x-x=11x112x11=2222isanswer 22 years is the right answer 22 years is the right answer Deepak's age is 22 andhis brother's age is 11 Let the Vikas age be xThen the age of Deepak will be 2xGiven the difference in their ages be 11 years2x-x=11x=11Deepak age will be 2*11=22 years let vikas's age be x yearsThen deepak's age is 2xGiven- difference in their ages is 11 years 2x-x = 11 (1)x=11 (2) The age of deepak will be2 × 11 = 22 years Deepak will be 22 years old .And vikas is 11 years old..at present.solved.... let vikas age be x.then his brother (deepak)age will be 2x difference of their ages be 11 years therefore 2x-x=11x=11 vikas age =11yearshis brother (deepak)age=2x 2×11 22 years let the vikas age be xthen the age of deepak will be2 given the difference in there ages be 11 years 2x-x=11x=11deepak age will be 2*11=22 years Let vikas age be g. Then age of Deepak be 2g . because given that it was twice given: 2g-g=11 g= 11 the age of Deepak will be 2.11= 22yrs please like my answer |
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| 7. |
Deepak is twice as old as his brother vikas .if the difference of their age be 11years, find their present age. |
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| 8. |
Deepak is twice as old as his brother Vikas. If the difference of their ages be 11 years, findtheir present ages. |
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| 9. |
epak is twice as old as his brother Vikas. If the difference of their ages be 11 years, findtheir present ages13. De |
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| 10. |
9. By selling 144 notebooks, Kailash lost the S.P. of 6 notebooks. Find his loss per cent. Had he puthem for 7200, what would have been the S.P. of one notebook? (Type IV Example 31)400 to Seema at a profit of 200, Seema then sells it to Nehar |
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| 11. |
In a ÎPQR, <Q = 90°. IfPQ = 10 cm and PRThen find the value of tan2 P +sec2 P+1 |
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Answer» As angle Q=90°Hence, PR will be the longest side that is hypotenuse =15cmPR^2=PQ^2+RQ^215^2=10^2+RQ^2225-100=RQ^2125=RQ^2RQ=5√5cmhencenowtanP=RQ/QP=5√5/10=√5/2and cosP=QP/PR==10/15=2/3hence secP=3/2hence tan^2P+sec^2P+1=5/4+9/4+1=14/4+1=7/2+1=4.5 |
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| 12. |
DJD W 3 4 B 5 153. Give the steps you will use to separate the variable and then solve the equation:(d) 16 = 6(a) 31 – 2 = 46 (b) 5m + 7 = 17 (c) 202 = 404. Solve the following equations:(a) 10p = 100 (b) 10p + 10 = 100 (c) F-5(d)=53P=6(e) 4(f) 3s = -9(1) 29 – 6=0(9) 3s + 12 = 0(k) 29 +6=0(h) 3s = 0( 29+ 6 = 12 !(1) 2q = 6 |
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Answer» 4:1:3n- 2=463n=46+23n=48n=48÷3n=16ans 2:5m+7=175m=17- 75m=10m=10÷5m=2ans 20p÷3=4020p=40×320p=120p=120÷20p=6 |
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| 13. |
ears ago, a mother was seven times as old as her daughter. Five yearsshe will be three times as old as her daughter. Find their present ages.e, |
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| 14. |
Uhl, Jul and 7.1 cm. 3vears ago, Shyam's age was 3 times of Ram'se. Their total age will be 44 years after 4 yearsence. Find their present ages. |
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Answer» 4 years ago :_______________________________ let age of ram be = x yr age of shyam =3/ 4 times of ram's age = 3/ 4 x yr _______________________________Present age : _______________________________present age of ram = ( x + 4 ) yr present age of shyam = ( 3/ 4 x + 4 ) yr _______________________________4 years hence :_______________________________ age of ram = ( x + 4 + 4 ) yr age of shyam = 3 / 4 x + 4 + 4 _______________________________ according to question , after 4 years , shyam's age will be 5 / 6 times that of ram ,_______________________________ 3 /4 x + 4 + 4 = 5 / 6 ( x + 4 + 4 ) 3 x / 4 + 8 = 5 / 6 ( x + 8 ) ( 3 x + 32 ) / 4 =( 5x + 40 ) / 6 ( 3 x + 32 ) / 2 = ( 5x + 40 ) / 3 3 ( 3 x + 32 ) = 2 ( 5 x + 40 ) 9 x + 96 = 10 x + 80 10 x - 9 x = 96 - 80 => x = 16 hence , present age of shyam = 3/ 4 x + 4 = 3 / 4 × 16 + 4 = 16 yr therefore, present age of shyam = 16 yr _______________________________Your Answer : 16 yr __________________________ the present ages is 16 year old. 16 yr is the right answer of the following 16 yrs is the correct answer of the given question is |
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| 15. |
their present ages ?Deepak is twice as old as his brother Vikas. If the difference of their ages be 11 years,their present ages.DlhAL |
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Answer» ygrgggs had a great day at work and present age of deepak is22 vikas age is 11 years Deepak's age is 22 years |
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| 16. |
0. Calculate the mean deviation about median age for the age distribution of 100 persons given below:16-20 21-25 26-30 31--35 36-40 41-45 46-50 51-55AgeNumber :2612169.1214 |
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| 17. |
012. Compute the mode for the following frequency distribution.Class38-4040-42 42-44 44-46 46-488-50 50-52Frequency144 |
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| 18. |
- Find the HCF of the numbers using the division method.225, 630 2. 145, 165, 175 3. 180, 144, 192147, 168, 210 6. 91, 130, 156 7. 130, 195, 3904. 51, 64, 1198. 420, 480, 720 |
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Answer» So MAny questions only one question should be |
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| 19. |
5. The altitude of a right triangle is 7 cm less than its base. If the hypotenuse is 13 cm, findthe other two sides. |
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| 20. |
ĺĽ"La Ikleslatel EykSletd !bleajblele llelselt tik a) b.kadallelaSLI .11LI |
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Answer» Sorry we are currently taking questions in English only. |
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| 21. |
18. (कोएनां वाश्क वार्विक 5% झोएज् मत्ल सून (मम । अंडे वाशक गोशूवानू वात AT 15000 Tt &ए्थयांत्र 3 बाग शप्त 3000 की डुएन निएनन थवर Bieel PUA GERIE 3 3P AT A र्जि8000 को जगा निफनन | 5 वक्त (एव किशूवानू सूएन-आमएल कऊ फोकों शॉएवन TRel g |
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| 22. |
(g) 3s 12 0 |
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Answer» 3s+12=03s= -12s= -4 |
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| 23. |
(1) In ÎABC, LACB is an obtuseangle. Seg AD 1 line BC, thenshow that : AB2 BC2 + AC2+2BC.CD |
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| 24. |
15^3-8^3-7^3s disible by which of the following? |
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Answer» 15^3=33758^3=5127^3=34315^3-8^3-7^3=3375-512-343=2520so it is divisible by factors of 2520. |
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| 25. |
1f2 sin (3s-153, then find the value of sin2 (2x +10)+ tan2 |
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Answer» Thanks |
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| 26. |
if the volume of cube is same as that of cuboid of dimensions 27m×9m×3m. find the edge of the cube |
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| 27. |
The altitude of a right triangle is 7 cm less than the base x and the hypotenuse is 13 cm.Find the quadratic representation of this situation. |
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| 28. |
The volume of a cuboid is 0.256m3 more than that of a cube. If the volume ofthe cuboid is 3m. find the length of an edge of the çube17· |
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| 29. |
Miscellaneous Practice problems1.The base of the parallelogram is 16 cm and the height is 7 cm less than its baseFind the area of the parallelogram.hose area |
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| 30. |
cach ef these and show that they can be rewritten in the form 3m or Sm5. Vse Eaclid's division lemma to show that the cube of any positive integer is of the form |
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| 31. |
4. Find two corisetuuve puIThe altitude of aright triangle is 7 cm less than its base. If the hypotenuse is 13 cm, fiThe altitude of a right triangle isthe other two sides. |
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Answer» very absolute and perfect answer , thanks scholr |
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| 32. |
5. The altitude of a right triangle is 7 em lessthan its base. If the hypotenuse is 13 cm, find theother two sides. |
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| 33. |
Add →5634From here →Subtract →45From here →13Remember the following:1. The value of the number remains the same by addinginto it. For example: 5 + 0 = 5.2. The value of the number remains the sameubtracting from it. For example: 5 - 0 = 5.3. Always small number from the large number.4. Always multinly any number with zero the produc |
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| 34. |
2/3p = 6 |
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| 35. |
Add →453From here →Subtract →4 53From here →13Remember the following:1. The value of the number remains the same by addinginto it. For example: 5 +0=5.2. The value of the number remains the same bySubtracting 0 from it. For example: 5-0 =5.3. Always small number from the large number.4. Always multiply any number with zero the productorresult will be zero.48Teacher's Signature:Date: |
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Answer» 7+3,7+4,7+5,7+6, (1)8+3,8+4,8+5,8+6, (2)9+3,9+4,9+5,9+6(3)10+3,10+4,10+5,10+6(4) |
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| 36. |
(c) 3p=18 |
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Answer» Ans :- 3 × p = 18 p = 18/3 p = 6 think you |
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| 37. |
A godown is 50 m long, 40 m broad and 10 m high. Find the cost of whitewashing its fourwalls and ceiling at 20 per square metre. |
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| 38. |
6. A godown is 50 m long, 40 m broad and 10 m high. Find the cost of whitewashing its fourwalls and ceiling at20 per square metre. |
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| 39. |
16. A godown is 50 m long, 40 m broad and 10 m high. Find the cost of whitewashing its fourwalls and ceiling at 20 per square metre |
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| 40. |
a room is 10 M long 8m wide and 3.3 M high how many men can be accommodated in this room if each man require 3M cube of space |
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Answer» The room is in shape of a cuboid.Given.Length of cuboid= 10mBreadth of cuboid= 8mHeight of cuboid= 3.3mVolume of cuboid= l*b*h = 10*8*3.3 = 264 m3Given each man requires 3m3 of spaceNo of men can be accommodated in the room= Volume of room/ volume of each man = 264/3 =88Therefore, maximum 88 men can be accommodated in the room. |
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| 41. |
16. A godown is 50 m long, 40 m broad and 10 m high. Find the cost of whitewashing its fourwalls and ceiling at20 per square metre |
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| 42. |
The inner diameter of a circular well is 4.2 m. It is 12 m deep. Find (0) its hner curved surface areai) the cost of plastering the inner curved surface at the rate of R50 per m^2 |
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Answer» Thank you |
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| 43. |
7. Find the area of the thin sheeting required for making an open cistern (i.e., without a lid), 5 m long, 3mwide, 4 m deep. |
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Answer» length = 5 m breadth = 3 m height = depth = 4 mTSA = 2 ( lb + bh + hl )but by condition without lid here TSA = 2 ( lb + bh + hl ) - lb = 2 ( 15 + 12 + 20 ) - 15 = 2 ( 47 ) - 15 = 94 - 15 = 79 sq.m |
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| 44. |
Let's Doith a weight of 4 kilograms was cdlvicted into 3 bgower as a decimal rounded to 1 decimal place. A tin of tea with a weight oExpresslght. What was the weight of each bag of tea?ssonThe weight of each bag okilograms.f tea was四Chapter 31-1. Idin.Practice 1unres eoch improper fraction as a whole number or a mixedumber in its simplest form.7221350c) 6a)b) 24und nmber in its simplest form |
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| 45. |
olve the following Smpe qui0 6m = 12(ii) - 5y = 30m) 14p = - 42(iv)-2x = -12m =-334x = -51(viii) 3x + 1 = 16(vi) ** = 181 3p-7=0(xi) 2007 - 51 - 49(x) 13 - 6n= 7(xii) lin+1 = 1(xiv) 8x + = 13(xi) 7c-9 = 16(xv) x+=3حد ادرا |
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Answer» vi). n=-21.viii). X=5is). p=7/3. abs (ix) 3p-7=0 3p=0+7 3p=7 p=7/3 (vi)n/7=-3 n= -3×7 n= -21 (viii)3x+1=16 3x=16-1 3x=15 x=15/3 x=5 |
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| 46. |
N “ 3p* - 3p’_ 4p* + 4p » (p* - p) |
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| 47. |
(3p- 1/2) (3p- 1/2) |
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Answer» =(3p-1/2)^2=(3p)^2+(1/2)^2-2(3p)(1/2)=9p^2+1/4-3p 👎rong ane |
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| 48. |
यदि p +3p- +3p=7 है, तो p+2p कामान ज्ञात करें। |
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Answer» the answer if this math is 3 |
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| 49. |
3p -10 =53p-10 + 10 = 5 + 10 |
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| 50. |
Use division algorithm to show that the square of any positive integer is of theform 3p, 3p + 1. |
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Answer» let us take,'x'= 3q , 3q+1,3q+2when,x=3q x2= (3q)2 x2= 9q2 x2= 3(3q2)we see that3q2= m so we have done the first equation3m when ,x=3q+1 x2= (3q+1)2[since,(a+b)2= a2+2ab+b2] x2= 9q+6q+1 x2= 3(3q+2q)+1 in this we see that3q+2q= m Therefore, this satisfy the equationm+1 |
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