1.

7. Find the area of the thin sheeting required for making an open cistern (i.e., without a lid), 5 m long, 3mwide, 4 m deep.

Answer»

length = 5 m breadth = 3 m height = depth = 4 mTSA = 2 ( lb + bh + hl )but by condition without lid here TSA = 2 ( lb + bh + hl ) - lb = 2 ( 15 + 12 + 20 ) - 15 = 2 ( 47 ) - 15 = 94 - 15 = 79 sq.m



Discussion

No Comment Found