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In a ÎPQR, <Q = 90°. IfPQ = 10 cm and PRThen find the value of tan2 P +sec2 P+1 |
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Answer» As angle Q=90°Hence, PR will be the longest side that is hypotenuse =15cmPR^2=PQ^2+RQ^215^2=10^2+RQ^2225-100=RQ^2125=RQ^2RQ=5√5cmhencenowtanP=RQ/QP=5√5/10=√5/2and cosP=QP/PR==10/15=2/3hence secP=3/2hence tan^2P+sec^2P+1=5/4+9/4+1=14/4+1=7/2+1=4.5 |
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