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a room is 10 M long 8m wide and 3.3 M high how many men can be accommodated in this room if each man require 3M cube of space |
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Answer» The room is in shape of a cuboid.Given.Length of cuboid= 10mBreadth of cuboid= 8mHeight of cuboid= 3.3mVolume of cuboid= l*b*h = 10*8*3.3 = 264 m3Given each man requires 3m3 of spaceNo of men can be accommodated in the room= Volume of room/ volume of each man = 264/3 =88Therefore, maximum 88 men can be accommodated in the room. |
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