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Today is India vs England match who win

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who win

0.00006cm is the correct answer

0.00006cm is the correct answer

A sequence of numbers is called aHarmonic progressionif the reciprocal of the terms are inAP.

In simple terms, a, b, c, d, e, f are in HP if 1/a, 1/b, 1/c, 1/d, 1/e, 1/f are in AP.

For example, 1/a, 1/(a+d), 1/(a+2d), and so on are in HP because a, a + d, a + 2d are in AP.

We know that, a complex number is purely real if its imaginary part is zero.

Here, the given complex number =

One of the way to write A in the set-builder form is following:

A={x: x is a natural number; x≤7}

simplest form = 92/115=3/5 is simplest form

Given,Ratio is 92:115

To convert in simplest form find the HCF of 92 and 115

HCF of 92 and 115 = 23

Thus,92:115 = 4*23 : 5*23

Therefore, Simplest form is 4:5

Part-1

For pure real imaginery part should be 0

We know that, a complex number is purely real if its imaginary part is zero.

Here, the given complex number =

Hint

198

solution

√99= √3*3*11=3√11√396= √2*2*3*3*11= 6√11= √99*√396= 198

2x^3-12x^2+14; x+1=0; x=-1; 2(-1)^3-12(-1)^2+14=-2+12+14=10+14=24

24 is the correct answer

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Proof:

RHS=2√3+√11

Square the RHS:(2√3+√11)^2

Apply (a + b)² = a² + 2ab + b²:RHS^2=(2√3)^2+2*2√3*√11+√11^2

=4(3)+4√33+11

=23+4√33

Write 4 as √16:

RHS^2=23+√528

Square root it:

RHS=√23+√528hence LHS=RHS

Set of rational numbers;)A = { 1/2,3/4,5/4,6/4}The elements of set A are 1/2,3/4,5/4,6/4OrA = { x : x € N , x is a rational number}yes we can

tan theta = root(3)

tan theta = tan 60°

Hence, theta = 60°

Therefore,Cot theta = cot 60° = 1/root(3)

Cosec theta = Cosec 60°= 2/root(3)

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There is error in you question.Length of circle is an absurd term.

the question might have been length of common chord.

if equation have equal too then there should be b*b = 4ac ii) 3*3 = 4*m*(-5) 9 = -20m m = -9/20 iii) (-6)*(-6) = 4(3)(m) 36 = 12m m= 3

2x-y=6-----(1)3x-2y=4----(2) multiple by 2 in eq 1

2x-y=6----(1)3x-2y=3---(2)multiply by 2 in eq 14x-2y=123x-2y=3substrate 1 -2 x=9putting the value of X in eq 12x-y=62x+6=y2×9+6=y24=y

430/323 or in decimal 1.33

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11/17 + 13/19 =11(19)+13(17)/323 = 209 + 221/323 = 430/323

121+121+121+121+121=605

(11+√11)(11-√11)=(11)^2 - (√11)^2=121-11=110

11()

In linear algebra, thetraceof an n-by-n squarematrixA is defined to be the sum of the elements on the main diagonal

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Area = theeta/360°x( πr^2)60/360(22/7

Given, radius of circle (r) = 6 cm

Angle of the sector (θ) = 60°

Now, area of sector = (θ/360°) * πr2

= (60°/360°) * (22/7) * 62

= (1/6) * (22/7) * 6 * 6

= (22/7) * 6

= 132/7 cm2

Zero pairs of line

I see the last page were answer is a,b

how to solve this problem

a pair of parallel lines are those which form a 90° angle between them..... in this problem a and b are inclines at an angle of 90° ,this implies they are parallel to each other ...