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Sum of angles =1802x-7+3x+13=1805x+6=1805x=174x=34.8

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a= (3+√5)/21/a = 1/[(3+√5)/2]

=> 1/a = 2/(3+√5)

=> 1/a = 2(3-√5)/(3+√5)(3-√5)rationalizing the denominator

=> 1/a = (6-2√5)/3²-(√5)²=> 1/a = (6-2√5)/9-5 => 1/a = (6-2√5)/4

(a+1/a)² = a²+1/a ²+2

(3+√5)/2 + (6-2√5)/4] = a²+1/a²+2

=> [2(3+√5)/(2)2 + (6-2√5)/4] = a²+1/a²+2Making denominator equal

=> (6+2√5+6-2√5)/4 = a²+1/a²+2=> 12/4 = a²+1/a²+2

=> 3 = a²+1/a²+2

=> 3-2 = a²+1/a²

=> 1 = a²+1/a²

-14 +5=19

a). 7(-2)+5=19 -14+5=19 -14=19-5=14 =14+14=28.👍

b). 4(-4)-3=13 -16-3=13 -3 =13+16=29 =. 29+3 = 32 👍

I want all the dimensions of the trianglelengths of sides n angles

using trigonometry

plz give me answer

bhout hi asan hai bhia kar ke dekh

(3,2) is the answer .

bhai pura solve kar ke dika

it was written solve graphically..

please you solve my second answer

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argument = tan(theta)= -1/-sqrt(3) so theta = 30

(a+b+c)^3 = a^3+b^3+c^3 + 3(a+b)(b+c)(a+c)most commonly used

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Right answer thank for solution this

(a)

(b)

(c)

15÷5×4+2=8+63×4+2=8+612+2=1414=14

-1.48

Point of intersection is x = 5 and y = 2

Red line is x + y = 10

Blue line is x - y = -4

So, point of intersection (3, 7)

(1,4) is the answer

3/7 - 6/11 - 8/11 + 5/11 = 3/7 - 9/11 = (3×11-9×7)/(11×7) = (33-63)/77 = -30/77

thanks😀😁😂

we get graph intersect x axis at x = 1 and y = 0 which are solution of the equation

z=1/(2+3i)(2+3i): z = 1/(2+3i)²now solve |z|

Red line is 2x + y - 6 = 0Blue line is 4x - 2y - 4 = 0So, point of intersection is (2,2) , which is solution of system

correct answer isx = -1, x = -13/6

6x^2-7x-13=0, 6x^2-13x-6x-13=x(6x-13)+1(6x-13)=(6x-13)(x+1); 6x=13; x=13/6; x=-1

Starting fromθ=0θ=0and going counterclockwise, the first time this is true is at 45 degrees, orπ4π4. It happens again at 225 degrees, or5π45π4, where they're both negative.

The two have the samelengthat 135 degrees, but at that pointcos(θ)cos(θ)is negative andsin(θ)sin(θ)is positive, so the signs aren't equal. The same is true at 315 degrees -- they have the same length but the signs are opposite.

You can keep going counterclockwise past 360 degrees and you hit the same lines again, but now the angles are 360+45 = 405 degrees (9π49π4) and 360+225 = 585 degrees (13π413π4).

This continues on with more rotations -- the pattern is that every 180 degrees after 45 degrees, this solution occurs. So all solutions can be described with the expression:

45+180n45+180ndegreesorπ4+πnπ4+πnradianswherenncan be any integer.

a is the answer of the following