6) of AC345 show that met 1-3. Ales find me the

1.	6) of AC345 show that met 1-3. Ales find me the
Answer» a= (3+√5)/21/a = 1/[(3+√5)/2] => 1/a = 2/(3+√5) => 1/a = 2(3-√5)/(3+√5)(3-√5)rationalizing the denominator => 1/a = (6-2√5)/3²-(√5)²=> 1/a = (6-2√5)/9-5 => 1/a = (6-2√5)/4 (a+1/a)² = a²+1/a ²+2 (3+√5)/2 + (6-2√5)/4] = a²+1/a²+2 => [2(3+√5)/(2)2 + (6-2√5)/4] = a²+1/a²+2Making denominator equal => (6+2√5+6-2√5)/4 = a²+1/a²+2=> 12/4 = a²+1/a²+2 => 3 = a²+1/a²+2 => 3-2 = a²+1/a² => 1 = a²+1/a²

Answer»

a= (3+√5)/21/a = 1/[(3+√5)/2]

=> 1/a = 2/(3+√5)

=> 1/a = 2(3-√5)/(3+√5)(3-√5)rationalizing the denominator

=> 1/a = (6-2√5)/3²-(√5)²=> 1/a = (6-2√5)/9-5 => 1/a = (6-2√5)/4

(a+1/a)² = a²+1/a ²+2

(3+√5)/2 + (6-2√5)/4] = a²+1/a²+2

=> [2(3+√5)/(2)2 + (6-2√5)/4] = a²+1/a²+2Making denominator equal

=> (6+2√5+6-2√5)/4 = a²+1/a²+2=> 12/4 = a²+1/a²+2

=> 3 = a²+1/a²+2

=> 3-2 = a²+1/a²

=> 1 = a²+1/a²

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