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ŕ¤ŕ¤ż . \sqrt{23+\sqrt{528}}=2 \sqrt{3}+\sqrt{11} |
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Answer» Proof: RHS=2√3+√11 Square the RHS:(2√3+√11)^2 Apply (a + b)² = a² + 2ab + b²:RHS^2=(2√3)^2+2*2√3*√11+√11^2 =4(3)+4√33+11 =23+4√33 Write 4 as √16: RHS^2=23+√528 Square root it: RHS=√23+√528hence LHS=RHS |
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