Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

3+/52V5+ 3- a + bv5, find the values of rational numbers a and b

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plzz give me the ans

2.

3.Construct Δ XYZ in which ZY-30, <Z = 60 and XY + YZ + ZX-11cm.

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Step 1: A line segmentAB= 11 cm is drawn. (XY + YZ + ZX = 11 cm)Step 2: An angle, ∠A= 30° is constructed at point A and an angle ∠B = 90° at point B.Step 3: ∠A and ∠B are bisected . The bisectors of these angles intersect each other at point X.Step 4: Perpendicular bisectors TS of AX and ZU of BX are constructed.Step V: Let TS intersect ABat Y and ZU intersect AB at Z. XY and XZ are joined.Thus,ΔXYZis the required triangle.

3.

Q17 If tane 11, then find the values of the other trigonometric ratios.

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4.

NQ17. Ifand app, then find raive of e2715157Ans: 416 267N

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5.

\begin{array} { l } { \text { If } x + y - z = 4 \text { and } x ^ { 2 } + y ^ { 2 } + z ^ { 2 } = 30 \text { , then find the } } \\ { \text { value of } x y - y z - z x \text { . } } \end{array}

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no

thanks a lot for your help.

6.

Z-(z+h)p - (h - x) 70 + XÇU (A)

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7.

what is null matrix?

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Ans :- A null matrix is basically a matrix, whose all elements are zero. In a matrix basically there are two elements, first one is diagonal matrix and another one is non-diagonal elements. In Null matrix both diagonal and off-diagonal elements are zero. Null matrix is also called zero matrix.

8.

Il)Null vectors :

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Zerovectorornull vectoris avectorwhich has zero magnitude and an arbitrary direction. It is represented by . If avectoris multiplied by zero, the result is a zerovector.

9.

ling a flower pot for 322, a man gains 15%. At what price should he sell it to gain20%?

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10.

EXERCISE 17.11. A paper is in the form of a rectangle DARK in which DA 30 cm30 cmand KD 21 cm. A semicircular portion with AR as diameter iscut-off. Find the area of the remaining part.21 c

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Area of ractangle = 30*21= 630 cm^2

Area of semicircle = 1/2*pi*r*rr = 21/2= 1/2*22/7*21/2*21/2=11*3/2*21/2= 33*21/4= 173.25 cm ^2

Area of remaining portion= 630-173.25 = 456.75 cm ^2

11.

A eylindrical tube open at both enda ismade of nctal. The internal diameterof the tube is 11.2 cm and its length is21 cm If the metai thickness is 0.4 cm,then the volume of metal wil(A) 2067.87 em3(B) 306.24 cm3(C) 1922.81 om(D) 103394 cm3IT

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12.

5246. Pick the odd one out.20 2-1 32221 0 5 3 1 0 4 -1203 4 4 5 5-1Lab

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this type of questions I don't know

They all have something in common, exceptone. You must find theodd one out.Choosethe shape that you think does not go with the other three and select A, B, C or D as your

option (c) is the right answer.

13.

20. The binomial (z-6) is a factor of which of the following trinomials(a) 322-13z + 12(b) 4z16z+ 15 (c) 222 -13z + 6(d) 2-11z + 24

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z-6 is a factor that means if we put z=6 then answer need to be 02z^2-13z+6=2(6)^2-13(6)+6=72-78+6=0so its a factor of 2z^2-13z+6

wrong

14.

1. The rodi of two circular ends of frastum shape bucket are 14 om and 7 cm.Height of the bucket is 30 cm. How many liters of water it can hold ?(1 litre1000 cm)

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15.

८८10५: T P ' j*fi’(j (_ L )SX (_K\m'_. (_‘q‘ 4

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16.

9. J, F, M, A, M,?(a) J(b) N(C) O(d) P

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I think answer may be N by numerical position of m+A

I think it's ans. is. j.

17.

9 - 30 z + 25 z ^ { 2 }

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18.

25. If x:y:z=3: 4:5 and x' + y + z = 1728, then find(x-y+z)

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8

19.

Q17 Find the value of x, y, z in the following figure:25

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thanks didi

20.

\left. \begin{array} { l } { \text { If } x ^ { 2 } + 9 y ^ { 2 } + 25 z ^ { 2 } = x y z ( \frac { 15 } { x } + \frac { 5 } { y } + \frac { 3 } { z } ) \text { then } x , y , z \text { in } } \\ { ( A ) A P \quad ( B ) G P } & { ( C ) H P } \end{array} \right.

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X2+ 9y2+25z2= 15yz + 5xz + 3xyÞX2+ 9y2+ 25z2-15yz-5xz - 3xyÞ(x-3y)2+ (3y-5z)2+(5z-x)2= 0Þx = 3y , 3y = 5z, 5z = xÞx =lm, y = (l/3) , z = (l/5)or x, y, z are in H.P

kuch bhi

it is correct yrr.....

21.

Du somIke of grapes on a day was found to be 160. After aThe cost of 2 kg of apples and 1kg of grapes on a day was found tocost of 4 kg of apples and 2 kg of grapes is 300. Represent the situationalgebraically and geometrically.

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Let cost each kg of apples= Rs x

Cost of each kg of grapes= Rsy

Given that The cost of 2 kg of apples and 1kg of grapes on a day was found to be Rs 160

So that

2 x +y= 160… (1)

2x= 160- y

x=(160 – y)/2

Let y = 0 , 80and 160we get

x= (160 – ( 0 ))/2=80

x= (160- 80 )/2= 40

x= (160 – 2* 80 )/2= 0

X

80

40

0

y

0

80

160

Given that the cost of 4 kg of apples and 2 kg of grapes is Rs 300

so we get

4x +2y= 300… (2)

Divide by 2 we get

2x + y= 150

Subtract 2x both side we get

y= 150 – 2 x

Plugx = 0 , 50 , 100we get

y= 150 – 2*0= 150

y= 150 – 2* 50= 50

y= 150 – 2 * (100 )= - 50

X

0

50

100

Y

150

50

-50

Algebraic representation

2 x +y= 160… (1)

4 x +2y= 300… (2)

22.

5.(1+%)(1+%)(1+%)(1 +1 /1 20)III?

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( 1 + 1 /2 ) = ( 2 + 1 ) / 2 = 3/2

( 1 + 1/3 ) = ( 3 + 1 ) /3 = 4 / 3

( 1 + 1/ 4 ) = ( 4 + 1 ) / 4 = 5 / 4

...( 1 + 1/ 120 ) = ( 120 + 1 ) / 120 = 121 / 120

Therefore ,

(1 + 1/2 ) ( 1 + 1/3 ) ( 1 + 1/4 ) ....( 1 + 1/ 120)

= ( 3/2 ) ( 4/3) ( 5/4 ) ..... ( 121 / 120 )

after cancellation ,

= 121 / 2

23.

Convert 45 °C into ° F.

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After solving F= 113°F

24.

6.0 a -b-~ 0 T —C _—OB oD

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By expanding it

0(0+c)-a(0+bc)-b(-ac)abc-abc=0

25.

311. x45-

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26.

If a and b are rational numbers and 52 +25z atblo find the value of andb212+B.

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you can solve from next I have sold the difficult part and in which school you study

27.

3.Whidh of the folloving is null set:

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28.

'- पूर्ण वर्ग बनाने की विधि से समीकरण 522 - 6५ - 2 न 0 के मूल हल कीजिए।

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29.

(iii) A = {x : x + 5 = 5). It is null set or universal set.

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It is an universal set because, the set has one item, that is 0. So it can not be a null set. Null set should not contain any component.

Please hit the like button if this helped you

30.

(5)Area of the sector of angle 60° of a circle with radius 10 cm is52읖cm4(a)5221-crm (b)cm 2 (c) 522cm2(d)52

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Area of a sector =[ x/360] pi r^2

= [60/360] x 3.14 10 x10

= 314/6 = 52.3cm^2

Area of the cicle is 3.14 x 10 x 10 = 314

Hence area of the major sector = 314 - 52.3 = 261.7cm^2

31.

UDOU 522590-590 +18 X45+)2 - 10HA

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-768 is the correct answer of the given question

-768 is the right answer

-768 is correct answer.

the answer of this question is -778

32.

5.Usingthe given pattern, find themis12 +22 +22 3222 +32+627232 +42+122 1342 +52 2 212522+302 31262 +722

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1*2=22*3=63*4=124*5=20Therefore, 4^2+5^2+20^2=21^26*7=426^2+7^2+42^2=43^2

33.

Are these identities true for0° SA S 90° ? If not, for which valuesof A they are true ? (Page No. 290)(AS)i) sec? A-tan? A = 1

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it is applicable only for 0 degreessec^2(0 )-tan^2(0)=1-0 =1

this statement does not suits.for 30 45 90 degrees

34.

nscuivebddIhlegers,sumofwhosesquaresis290.18. How man419. If tangents PA and PR from o

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A.p= 9,17,25a=9d=17-9=8Sum of n terms=n÷2[2a+(n-1)d

636=n÷2[2(9)+(n-1)8]636=n÷2[18+8n-8]636=n÷2[10+8n]1272=10n+8n^28n^2+10n-1272=02[4n^2+5n-636]=04n^2+5n-636=04n^2+53n-48n-636=0n(4n+53)-12(4n+53)=0(n-12)(4n+53)=0n-12=0n=12

12 terms must be given to sum of 636

35.

8. A, B, C, D have Rs 290 between them; A has twice as much asC, and B has three times as much as D; also C and D together haveRs 50 less than A. Find how much each has

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.

super

36.

8. A, B, C, D have Rs 290 between them; A has twice as much asC, and B has three times as much as D; also C and D together haveRs 50 less than A. Find how much each has.

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37.

LXdmple-ZSahameli had (Rs 600e amount which Chameli had.NCERTlfter spending 75% of herth

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let the amount chameli had be xthen (75/100)*x =600=>x= 200×4=800

hit like if you find it useful

38.

if the cost of a dress is 25175the cost of one dress.Find

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cost of 9 dress is 5175 rsso cost of 1 dress is 5175/9 = 575 rs

575®the day cost of one dress

575 Rs. is correct answer.

cost of 9 dress = 5175 rscost of 1 dress= 5175/9=575rs

575 is the right answer

39.

jab do samantar rekha ko koi triak chedi rekha partiched kare to parkar bane kono ka sambandh batate

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याचे उत्तर आहे काटकोन

40.

Pointing to a lady in a photograph, Kashi said, "Sheis the mother of my son's wife's daughter". How isthe lady related to Kashi?A. Daughter-in-law.B DaughterC GranddaughterD Cousin

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correct option is A: daughter in law Son's wife would be here daughterin law, the child of her daughter in law would be her grandchild and her grandchild's mother would be again her daughter in law.

41.

(a). (b). (c) a (duilau vai63a1θ.어: (c) {(1, 0))1) b (3

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x=3y+13x+y=39y+3+y=3so y=0so x=0+1=1

42.

EXERCISE 2B1. Write each of the following numbers in standard form:(1) 57.36(ii) 3500000(iv) 168000000(v) 4630000000000

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43.

Two customers Shyam and Ekta are visiting a particular shop in the same week (Tuesdayto Saturday). Each is equally likely to visit the shop on any day as on another day. Whatis the probability that both will visit the shop on (i) the same day? (ii) consecutivedays? (iii) different days?

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44.

sed the area of the following figure

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Area of circle = pi × r²

Area of circle 22/7 ×20²cm²=1,257.14 cm²

45.

Express each of the following decuma semExpress.cach of the followimedeme m

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46.

6.State with reason, which of the following are sech of the following are sets and which are not(i) All big rivers of India.

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1) No because there is no accurate information about the river. we need a similar set of rules for its elements. there is no specific measurement of comparison here

Ganga is biggest river in India 🇮🇳

47.

. Ramita can complete 1/20 part of a work in one day. How long will she tai20complete the work ?

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she will take 20 days to complete the work

48.

- If a=566= 9, calculate the value of:at matt-tb this

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a=(5+5)-(9+1)+(5+1)=(10)-10+6=6

a=5, b=9a=(5+5) -(9+1) +(5+1) =(10) -(10) +(6) =6

49.

z=\frac{\pi}{4}(1+i)^{4}\left(\frac{1-\sqrt{\pi} i}{\sqrt{\pi}+i}+\frac{\sqrt{\pi}-i}{1+\sqrt{\pi} i}\right),

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50.

8. For the equations (a) y43 (b) 3z2 +3z +2y 0 (c) 9y? -6y-9- 0complete the square and reduce to one of the standard forms v-b A(z-a) or -a A(y-b)

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