(5)Area of the sector of angle 60° of a circle with radius 10 cm is52 – InterviewSolution

1.

(5)Area of the sector of angle 60° of a circle with radius 10 cm is52읖cm4(a)5221-crm (b)cm 2 (c) 522cm2(d)52

Answer»

Area of a sector =[ x/360] pi r^2

= [60/360] x 3.14 10 x10

= 314/6 = 52.3cm^2

Area of the cicle is 3.14 x 10 x 10 = 314

Hence area of the major sector = 314 - 52.3 = 261.7cm^2

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