Du somIke of grapes on a day was found to be 160. After aThe cost of 2

1.	Du somIke of grapes on a day was found to be 160. After aThe cost of 2 kg of apples and 1kg of grapes on a day was found tocost of 4 kg of apples and 2 kg of grapes is 300. Represent the situationalgebraically and geometrically.
Answer» Let cost each kg of apples= Rs x Cost of each kg of grapes= Rsy Given that The cost of 2 kg of apples and 1kg of grapes on a day was found to be Rs 160 So that 2 x +y= 160… (1) 2x= 160- y x=(160 – y)/2 Let y = 0 , 80and 160we get x= (160 – ( 0 ))/2=80 x= (160- 80 )/2= 40 x= (160 – 2* 80 )/2= 0 X 80 40 0 y 0 80 160 Given that the cost of 4 kg of apples and 2 kg of grapes is Rs 300 so we get 4x +2y= 300… (2) Divide by 2 we get 2x + y= 150 Subtract 2x both side we get y= 150 – 2 x Plugx = 0 , 50 , 100we get y= 150 – 20= 150 y= 150 – 2 50= 50 y= 150 – 2 * (100 )= - 50 X 0 50 100 Y 150 50 -50 Algebraic representation 2 x +y= 160… (1) 4 x +2y= 300… (2)

Du somIke of grapes on a day was found to be 160. After aThe cost of 2 kg of apples and 1kg of grapes on a day was found tocost of 4 kg of apples and 2 kg of grapes is 300. Represent the situationalgebraically and geometrically.

Answer»

Let cost each kg of apples= Rs x

Cost of each kg of grapes= Rsy

Given that The cost of 2 kg of apples and 1kg of grapes on a day was found to be Rs 160

So that

2 x +y= 160… (1)

2x= 160- y

x=(160 – y)/2

Let y = 0 , 80and 160we get

x= (160 – ( 0 ))/2=80

x= (160- 80 )/2= 40

x= (160 – 2* 80 )/2= 0

160

Given that the cost of 4 kg of apples and 2 kg of grapes is Rs 300

so we get

4x +2y= 300… (2)

Divide by 2 we get

2x + y= 150

Subtract 2x both side we get

y= 150 – 2 x

Plugx = 0 , 50 , 100we get

y= 150 – 2*0= 150

y= 150 – 2* 50= 50

y= 150 – 2 * (100 )= - 50

100

150

-50

Algebraic representation

2 x +y= 160… (1)

4 x +2y= 300… (2)