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3.Construct Î XYZ in which ZY-30, <Z = 60 and XY + YZ + ZX-11cm. |
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Answer» Step 1: A line segmentAB= 11 cm is drawn. (XY + YZ + ZX = 11 cm)Step 2: An angle, ∠A= 30° is constructed at point A and an angle ∠B = 90° at point B.Step 3: ∠A and ∠B are bisected . The bisectors of these angles intersect each other at point X.Step 4: Perpendicular bisectors TS of AX and ZU of BX are constructed.Step V: Let TS intersect ABat Y and ZU intersect AB at Z. XY and XZ are joined.Thus,ΔXYZis the required triangle. |
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