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For this find percentage in each testhence1)10/15*100=66.67%2)15/20*100=15*5=75%3)22/25*100=22*4=88%hence best was 3rd test

22 out of 25you have to find the percentage of each one. 10/15=66.67%15/20=75%22/25=88%

(x+1) (x+2) (x+3) is correct answer

(x+1)(x+2)(x×3) is this answer

7

2

Given, x³+ y³+ z³= 3xyz

Therefore, x³+ y³+ z³- 3xyz =0

This means,x³+ y³+ z³- 3xyz = (x + y + z) (x2+ y2+ z2- xy - yz - zx)

Now if x + y + z = 0, then......

x³+ y³+ z³- 3xyz = ( 0 ) (x²+ y²+ z²- xy - yz - zx) . .... [ subsituting the value of x + y + z ]

x³+ y³+ z³- 3xyz = 0

x³+ y³+ z³= 3xyz . please like the solution 👍 ✔️👍

Given x+y+z=0. ------(1)thenx+y= -z

cubing on both side(x+y)^3= -z^3

formula =(x+y)^3= x^3+3xy(x+y)+ y^3

so here alsox^3+3xy(x+y)+y^3 = -z^3

x^3+3xy( -z)+y^3= -z^3

hencex^3+ y^3+ z^3== 3xyz

pagal

rank is 3

We Know That

Angle(in Radian) = Arc/ Radius

108° = 108π/180= 3π/5

3π/5 = Arc/159πcm = Arc28.28cm = Arc

(x*x-4x)(x*x-4x-1) - 20 = x*x*x*x - 8x*x*x + 15x*x + 4x - 20 = x*x*x*x - 2x*x*x - 6x*x*x + 12x*x + 3x*x - 6x + 10x - 20 = (x*x*x-6x*x+3x+10)(x-2) = (x*x*x - 2x*x - 4x*x + 8x - 5x + 10)(x-2) = (x*x-4x-5)(x-2)(x-2) = (x-5)(x+1)(x-2)(x-2)

Ans :- a= 2nth term an = a + (n - 1)da19 = 59=> a + 19d = 59=> d = (59 - 2)/19=> d = 3

sixth term from end = last term - 5d = 59 - 5×3 = 59 - 15 = 44

Let the marks of the students be Xhenceaverage of marks=62+48+X/3but minimum average marks is 6062+48+X/3=60x=70minimum of 70 marks should be obtained to get an average of 60

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2×2×2×2×2×2 =64 is the correct answer of the given question

If my answer is correct so please like my answer

64 hiiiiiiiiiiiii friendssssssssss

64 is the correct answer of this question

2×2×2×2×2×2=64 answer

2 x 2 x 2 x 2 x 2 x 2= 64

2×2×2×2×2×2=64answer

64 is the correct answer

2 x 2 x 2 x 2 x 2 x 2 is the answer

2^6=2×2×2×2×2×2=64 ans

2^6=64 that is answer to your question

your answer will be 64

2×2×2×2×2×2=64 is the correct answer for the question

2×2×2×2×2×2= 64 is the correct answer

64 is the right answer

2×2×2×2×2×2=64 is the right answer

64 is correct and best answer 👍 👍👍 👍👍 👍👍 👍👍 👍

2×2×2×2×2×2=64it is a correct answer

280+50+60+120+180+70-80=690-80=610

610 is the answer of 280+50+60+120+180+70-80

Distance between the two points=√{(5-4)^2+(-2+8)^2}=√37 =6.08

Distance=√10 D=√(x1-x2)^2+(y1-y2)^2 √(4-3)^2+(1-2k)^2 = √10 Taking squares,1+(1-2k)^2 =10 (1-2k)^2=9 Taking square root,1-2k=3 or 1-2k=-3 2k=-2 or 2k=4 k=-1 or k=2

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I don't know this answer sorry

l cm(p-q) x hcf(p,q); lcm(a^2b^3-a^3b=a(b^2) x hcf(b^2-a^2)=

| 2x x | | 3 | | 16 || y 3y| | 2 | = | 9 |

(6x + 2x) | 16 |(3y + 6y) = | 9 |

8x = 16x = 16/8 = 2

3y + 6y = 9y = 9/9 = 1

Value of x = 2, y = 1

If we consider the complex numbers z1, z2and z3to be the points corresponding to A,B and C, then

Since z1, z2and z3are gievn to be in A.P., hence by definition we have,

2z2 =z1+ z3

Hence, this means z2 = (z1+ z3) / 2

This means that B is the mid point of line AC.

We can say that A, B and C are collinear.

This means that the points z1, z2and z3lie on a line.

∴Option (b) is correct.

We know that,x³-y³=(x-y)(x²+xy+y²)........................1Given that,x/y+y/x=-1

(x²+y²)/xy=-1

x²+y²=-xy

x²+y²+xy=0

(x²+xy+y²)=0Multyplying by (x-y) on both sides we get,(x-y)(x²+xy+y²)=(x-y)×0By eq1 we get,x³-y³=0

Hence x³-y³=0.

Total number of ways in which he can fail is

= C(5, 1) + C(5 2) + C(5, 3) + C(5, 4) + C(5, 5)= 5+10+10+5+1= 31

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total subjects =5way to fail=5*5=25

60 mangoes=₹50therefore cost of one mango=50/60=0.833cost of 120 mangoes=0.833*120=99.99=₹100

By successive formula, overall profit % = -10 + 16 + (-10)(16)/100 [ – for loss] = 6 – 1.6 = 4.4%

So, overall profit = 4.4 *15000/100 = 660

incomplete questionplease provide fig. also

(i) tan 48° tan 23° tan 42° tan 67° = tan (90° - 42°) tan (90° - 67°) tan 42° tan 67° = cot 42° cot 67° tan 42° tan 67° = (cot 42° tan 42°) (cot 67° tan 67°) = 1×1 = 1

(ii) cos 38° cos 52° - sin 38° sin 52° = cos (90° - 52°) cos (90°-38°) - sin 38° sin 52° = sin 52° sin 38° - sin 38° sin 52° = 0

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Let us assume that √3 is a rational number.

then, as we know a rational number should be in the form of p/q

where p and q are co- prime number.

So,

√3 = p/q { where p and q are co- prime}

√3q = p

Now, by squaring both the side

we get,

(√3q)² = p²

3q² = p² ........ ( i )

So,

if 3 is the factor of p²

then, 3 is also a factor of p ..... ( ii )

=> Let p = 3m { where m is any integer }

squaring both sides

p² = (3m)²

p² = 9m²

putting the value of p² in equation ( i )

3q² = p²

3q² = 9m²

q² = 3m²

So,

if 3 is factor of q²

then, 3 is also factor of q

Since,3 is factor of p & q both

So, our assumption that p & q are co- prime is wrong

Therefore√3 is an irrational numberLike if you find it useful

thnx