13-1f x + y + z0, show that x3 + y3 +23xyz.

1.	13-1f x + y + z0, show that x3 + y3 +23xyz.
Answer» Given, x³+ y³+ z³= 3xyz Therefore, x³+ y³+ z³- 3xyz =0 This means,x³+ y³+ z³- 3xyz = (x + y + z) (x2+ y2+ z2- xy - yz - zx) Now if x + y + z = 0, then...... x³+ y³+ z³- 3xyz = ( 0 ) (x²+ y²+ z²- xy - yz - zx) . .... [ subsituting the value of x + y + z ] x³+ y³+ z³- 3xyz = 0 x³+ y³+ z³= 3xyz . please like the solution 👍 ✔️👍

Answer»

Given, x³+ y³+ z³= 3xyz

Therefore, x³+ y³+ z³- 3xyz =0

This means,x³+ y³+ z³- 3xyz = (x + y + z) (x2+ y2+ z2- xy - yz - zx)

Now if x + y + z = 0, then......

x³+ y³+ z³- 3xyz = ( 0 ) (x²+ y²+ z²- xy - yz - zx) . .... [ subsituting the value of x + y + z ]

x³+ y³+ z³- 3xyz = 0

x³+ y³+ z³= 3xyz . please like the solution 👍 ✔️👍

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