Saved Bookmarks
This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
x3+y3=(x+y)(x2_xy+y2) |
|
Answer» R.H.S =>(x+y) ( x2- xy + y2)=> x3- x2y + xy2+ x2y - xy2+ y3 {On multiplying x3+ y3with(x+y) ( x2 - xy + y2)}=> [x3+ y3] + ( -x2y+ x2y) + (xy2- xy2)=> x3+ y3Since R.H.S = L.H.S,That is x3+ y3= x3+ y3Hence, verified that x3+ y3=(x+y) ( x2- xy + y2) |
|
| 2. |
9.Six candidates contested an election and got the following numbers of votes:Candidate A7,06,563Candidate B9,52,7657,35,904CandidatecCandidate ECandidate DCandidate F9,45,8829,97,7796,52,867(a) Which candidate got the maximum votes?(b) Who got the minimum votes?(c) Compare the votes of all the candidates and write in the ascending order. |
|
Answer» I don't know what is the A)candidate fB)candidate eC)e,a,c,d,b,f a) Candidate Fb) Candidate Ec) E, A, C, D, B, F a) candidate Fb) candidate Ec) E,A,C,D,B,F |
|
| 3. |
वैन &/द 8ठ८5/ न ६८, २ श&09उत I |
| Answer» | |
| 4. |
In Lok Sabha election, the elected candidate got 5,87,500 votes and defeated candidategot 3,52,768. By how many votes did the winner win the election? |
| Answer» | |
| 5. |
a mango has 10 rupees .10 mangos have_______rupees |
|
Answer» cost of 1 mango = ₹ 10cost of 10 mangoes = 10 × 10 = ₹ 100 |
|
| 6. |
.ड.:. R B उत्तर7 7. 23 +6 न 14 के युग्म केझनेक हल होने के लिए, : का मान 1 होना चाहिए। क्याय है? कारण टीजिए। फल सं ix+3 |
| Answer» | |
| 7. |
है शW g त्रिश दर भुजाओंAB 97 w1 . |या 11 Soed .देखिए . |‘ : ; =l Bi और "न कद (7 खींचेये शीर्षलम्ब= |
| Answer» | |
| 8. |
4 और 007 इस प्रकार हैं कि 20008 : 204 न 4 : ज 1ZAOC - ZBOC = 5 440B.हिका 2i |
| Answer» | |
| 9. |
ही 2 ool= जाएं, श ना .्| तक अन्यथा न कहां T, 5 लीजिए। .जार बर्तन के आधार की परिधि 132 ८्ण और उसकीलीटर पानी आ सकता हैं? (1000 ८7” - 1लीटर) |
| Answer» | |
| 10. |
। (य, ८0 12% ८03 8%,०0152% ८01 78% ८0६60 न कि |
| Answer» | |
| 11. |
B.)Obtain all ather zeroes of 3a1 +6x-2x-10x-5, if two of its zeroes areand |
|
Answer» the other roots will bex^2-(3+2)x+6=0x^2-3x-2x+6= 0x(x-3)+2(x-3)=0x= -2 and x= 3 will be the other roots |
|
| 12. |
In an election, out of two candidates, acandidate got 58% of the votes cast and wonby 73,344 votes. Find the number of votesreceived by the defeated candidate. |
|
Answer» divide ₹3780 between Nikhita and akhila in the ratio of 4 5 |
|
| 13. |
4 In an election, out of two candidatescandidate got 58% of the votes cast andby 73,344 votes. Find the number of vereceived by the defeated candidate.only74 |
|
Answer» let the total no of votes cast be Xnow 58%of X=42%X+73344he won by 73,344 voteshence 0.58x=0.42x+733440.16x=73344X=73344/0.16458400 |
|
| 14. |
Exam de 0:Find the least number that must besubtracted from 5607 so as to get a perfect square. Also find the square root of theperfect square. |
| Answer» | |
| 15. |
we have 3kg mango now we can give one kg mango find total mangos |
|
Answer» Total amount of mango left=3 kg-1 kg=2 kg nice sir iam just chek the aap |
|
| 16. |
Profit and Loss Ch10-98. A man went to market and purchased an temof 5000 and sold it at a loss of 10%. Fromthat amount he purchased another item and soldit a profit of 16%. What is the amount of overallprofit made by him in whole dealing?(a) 650(b)660 |
|
Answer» Explanation:By successive formula, overall profit % = -10 + 16 + (-10)(16)/100 [ – for loss] = 6 – 1.6 = 4.4%So, overall profit = 4.4 *15000/100 = 660 |
|
| 17. |
and-SObtain all other zeroes of 3r+6x-2-10r-5, if two of its zeroes are4.otient and remaindOn dividingx3-3x2+x + 2 by a polynomialg(x), the quand-2r +4, respectivelu |
| Answer» | |
| 18. |
all other zeroes of 3r* +6x 2x -10r 5, if two of its zeroes areand13 |
|
Answer» Since √(5/3) and – √(5/3)are the two zeroes therefore, (x - √(5/3))(x + √(5/3)) =1/3(3x^2- 5)is a factor of given polynomial. Divide the given polynomial by 3x^2– 5. For other zeroes, x2+ 2x + 1 = 0 (x + 1)2= 0 x = –1, –1 Zeroes of the given polynomial are √(5/3), – √(5/3), –1 and –1. |
|
| 19. |
(iii) 1-3x+1,3-4x+ +30+3.3x + 6-27-10r-5 के अन्य सभी शून्यक ज्ञात कीजिए, यदि इसके दो शून्यकअन्य सभी शून्यक ज्ञात कीजियऔर पोषाफल कमश. |
| Answer» | |
| 20. |
A man got a 10% increase in his salary. If his new salary is? 154,000, find hisoriginal salary.1.945On Mondt only 160 peonle went What |
|
Answer» Let the original salary be x. According to question, x+10% of x=154000 1.1x= 154000 x= Rs 1,40,000 Hence, the original salary is Rs 1,40,000. |
|
| 21. |
EXERCISE 8.21. A man got a 10% increase in his salary. If his new salary is? 1,54,000, find hisoriginal salaryt to the 70o, On Monday only 169 people went. What |
| Answer» | |
| 22. |
d)120m1s. The area of a square is 256 cm. The perimeter of the square is(a) 16 cm(b) 32 cm(c) 48 cm(d) 64 cm |
| Answer» | |
| 23. |
7. Vinay bought a pizza and cut it into three pieces. Whenhe weighed the first piece he found that it was 7g lighterthan the second piece and 4g heavier than the third picceIf the whole pizza weighed 300g. How much did each ofthe three pieces weigh?(Hint: weight of first piece be 'x' then weight of secondpiece is 'x+7', weight of the third piece is 'x-4') |
| Answer» | |
| 24. |
to cut three lengths from a single piece of board of length 91cm.A man wantsThe second length is to be 3cm longer than the shortest and the third length is to Ube twice as long as the shortest. What are the possiblę lengths of the shortestboard if the third piece is to be at least 5cm longer than the second? |
| Answer» | |
| 25. |
A man wants to cut three lengths from a single piece of board of length 91 cm. Thesecond length is to be 3 cm longer than the shortest and the third length is to be twiceas long as the shortest. What are the possible lengths of the shortest board if the thirdpiece is to be at least 5 cm longer than the second?[Hint: If x is the length of the shortest board, then x, (x 3) and 2x are the lengths ofthe second and third piece, respectively. Thus, x = (x + 3) + 2x 91 and 2x (x + 3)+ 51 |
| Answer» | |
| 26. |
6. A man wants to cut three lengths from a single piece of board of length 91cm.The second length is to be 3cm longer than the shortest and the third length is tobe twice as long as the shortest. What are the possible lengths of the shortestboard if the third piece is to be at least 5cm longer than the second?nt It is the length of the shortest board, then r. Gr +3) and 2r are thelengths of the second and third piece, respectively. Thus,r+(r+3)+2rs91 and2re (r+3) + 5] |
| Answer» | |
| 27. |
The curved surface area of a right circular cylinder of height 14 cm is $ mdiameter of the base of the cylinder..em is 88cin2 |
| Answer» | |
| 28. |
21.The sum of the radii of two circles is 140 cm and thedifference of their circumference is 88 cm. Find theratio of their areas. |
|
Answer» gnejstejasrjsjscngdfndnd |
|
| 29. |
Given A= {a, b, c), B = {2, 31, Find the number ofrelations fromA to BWhat is maximum vaue of3-7cos 5x |
| Answer» | |
| 30. |
0.04Divide RstAblehe ratio of3:5. |
|
Answer» 910 in the ratio 3:5so that means total eight parts and from that the first will be 3 and the second will be 5 |
|
| 31. |
(5/7)4×(7/5)2 |
| Answer» | |
| 32. |
24. A boy spentof his money on buying cloth and 4 of his money on buying shoes.If initially he has2,400 how much did he spend on shoes. |
| Answer» | |
| 33. |
I = 16 cm , b = 14 cm |
|
Answer» Area of rectangle=l×b=16×14=224cm^2 |
|
| 34. |
(3928)²*984 |
|
Answer» (3928)^2* 9841.518*10^10 will be the answer |
|
| 35. |
6. In the Fig., sides of a square are surrounded by four same semicircleseach of radius 10.5 cm. The perimeter of the region so formed is(b) 88 em21 cm(a) 132 cm) 120 cm(d) 288 cm7. In the Fig., an equilateral triangle-shaped |
|
Answer» please like my answer if you find it useful |
|
| 36. |
कक पर28. 2 + 271 + 21 के छथ्का मान क्या |
|
Answer» 2+2-¹+2²+2-²=2+(1/2)+4+(1/4)=6+3/4=27/4 |
|
| 37. |
(0१% न डकIhislite 21 28 14% beb-lorkelhb Dl B2} |
| Answer» | |
| 38. |
The number of boys and girls in a school are 1264 and 984 respectively. Express the ratio of the number of boys to that of girls in the simplest form. |
|
Answer» number of boys = 1264 number of girls = 984 therefore, ratio of number of boys to that of girls = 1264 by 984= 4 by 3= 4:3 Ans = 4:3 is the ratio 4:3is the correct answer of the given question no sorry 158:123 is correct answer 1264/984=754:123is the right answer. 158:123 is right answer i 158:123 is the correct answer |
|
| 39. |
IV)21and Ac4. In a LABC, AD is the bisector of <A,1.(0) If AB 64 cm,AC -8 cm and BD -5.6find DC(ii) If AB 10 cm, AC 14 cm and BC-6cm,12.find BD and DC.(ii) If AB -5.6 cm, BD 3.2 cm and BC 6 cm,find A(iv) If AB 5.6 cm, AC 4 cm and DC 3 cm,find BO |
| Answer» | |
| 40. |
Multiple choice questions!ar(AABC)_9AABC - APQR. If= and AB = 18cm then length of PQ isar(APQR) 4 anda)14 cmb) 8 cmc) 10 cmd) 12 cmD CADATT |
|
Answer» option B8 cm is correct 8 cm is correct by method ok the answer is 8 is correct 8cm is the answer of your question option b. 8cm is correct answer. 8 is the answer of Ur questions |
|
| 41. |
A.Multiply and write each product in its lowest terms.342.9×272 ,4 |
| Answer» | |
| 42. |
26. Find the area of a parallelogram ABCD Dandin which AB- 14 cm, BC-10 cmAC-16 cm. (Given, V3-173.)10 cmA 14 cm B |
| Answer» | |
| 43. |
\begin{array} { l } { \text { Multiply: } } \\ { \text { (i) } \frac { 3 } { 4 } \text { by } \frac { 5 } { 7 } } \end{array} |
|
Answer» 3 5----- × ----- 4 7 = 15/28 |
|
| 44. |
21 m16. Find the area of the following figures :7 cm14 cm10 cm14 cm |
|
Answer» 1) Area = 1/2 (7)(10-3.5) + 1/2 π(3.5)^2 cm^2 =22.75 +17.6 =40.34 cm^2 2) Area = (14)^2 - 1/2 π(7)^2 = 196 - 77 cm^2 = 119 cm^2 |
|
| 45. |
\left. \begin array l l 73.5 cm \\ 65.5 cm & \text (D) & 74.5 cm \end array \right. |
| Answer» | |
| 46. |
\left. \begin{array} { l } { 200 cm ^ { 2 } } \\ { 288 cm ^ { 2 } } \end{array} \right. |
|
Answer» And one diagonal = 24 cm We know,Pythagorean Theorem!H² = B² + P²(AB)² = (OA)² + (OB)²(20)² = (OA)² + (12)²400 = (OA)² + 144400 - 144 = (OA)²256 = (OA)²16 cm = OAThen,AC = 2 x 16 = 32cm Now, Area = 1/2 × ( product of the diagnosis) = 1/2 ×( 24 × 32) =384cm^2 |
|
| 47. |
(21/28) - (12/20) |
|
Answer» 21/28 - 12/20 = (7×3)/(7×4) - (4×3)/(4×5) = 3/4 - 3/5 = (5×3-3×4)/(4×5) = (15-12)/20 = 3/20 |
|
| 48. |
Find the quadratic polynomial if the zeroes of it are 2 and -1/3 respectively. |
| Answer» | |
| 49. |
14-(-21-{28-(14-3)}) |
|
Answer» 14-(-21-{28-(14-3)})14-(-21-{28-11})14-(-21-{17})14-(-21-17)14-(-38)14+38=52 |
|
| 50. |
vr87cS28 1611pidus 21 |
|
Answer» iii) is the correct answer III) is the right answer of the following |
|