1.

x3+y3=(x+y)(x2_xy+y2)

Answer»

R.H.S =>(x+y) ( x2- xy + y2)=> x3- x2y + xy2+ x2y - xy2+ y3 {On multiplying x3+ y3with(x+y) ( x2 - xy + y2)}=> [x3+ y3] + ( -x2y+ x2y) + (xy2- xy2)=> x3+ y3Since R.H.S = L.H.S,That is x3+ y3= x3+ y3Hence, verified that x3+ y3=(x+y) ( x2- xy + y2)



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