\left. \begin{array} { l } { 200 cm ^ { 2 } } \\ { 288 cm ^ { 2 } } \e

1.	\left. \begin{array} { l } { 200 cm ^ { 2 } } \\ { 288 cm ^ { 2 } } \end{array} \right.
Answer» And one diagonal = 24 cm We know,Pythagorean Theorem!H² = B² + P²(AB)² = (OA)² + (OB)²(20)² = (OA)² + (12)²400 = (OA)² + 144400 - 144 = (OA)²256 = (OA)²16 cm = OAThen,AC = 2 x 16 = 32cm Now, Area = 1/2 × ( product of the diagnosis) = 1/2 ×( 24 × 32) =384cm^2

\left. \begin{array} { l } { 200 cm ^ { 2 } } \\ { 288 cm ^ { 2 } } \end{array} \right.

Answer»

And one diagonal = 24 cm

We know,Pythagorean Theorem!H² = B² + P²(AB)² = (OA)² + (OB)²(20)² = (OA)² + (12)²400 = (OA)² + 144400 - 144 = (OA)²256 = (OA)²16 cm = OAThen,AC = 2 x 16 = 32cm

Now, Area = 1/2 × ( product of the diagnosis) = 1/2 ×( 24 × 32) =384cm^2

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\left. \begin{array} { l } { 200 cm ^ { 2 } } \\ { 288 cm ^ { 2 } } \end{array} \right.

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