1.

all other zeroes of 3r* +6x 2x -10r 5, if two of its zeroes areand13

Answer»

Since √(5/3) and – √(5/3)are the two zeroes therefore,

(x - √(5/3))(x + √(5/3)) =1/3(3x^2- 5)is a factor of given polynomial.

Divide the given polynomial by 3x^2– 5.

For other zeroes, x2+ 2x + 1 = 0

(x + 1)2= 0

x = –1, –1

Zeroes of the given polynomial are √(5/3), – √(5/3), –1 and –1.



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