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all other zeroes of 3r* +6x 2x -10r 5, if two of its zeroes areand13 |
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Answer» Since √(5/3) and – √(5/3)are the two zeroes therefore, (x - √(5/3))(x + √(5/3)) =1/3(3x^2- 5)is a factor of given polynomial. Divide the given polynomial by 3x^2– 5. For other zeroes, x2+ 2x + 1 = 0 (x + 1)2= 0 x = –1, –1 Zeroes of the given polynomial are √(5/3), – √(5/3), –1 and –1. |
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