1.

If x/y+y/x=-1, where x!=0 and y!=0 , then find value of x3-y3

Answer»

We know that,x³-y³=(x-y)(x²+xy+y²)........................1Given that,x/y+y/x=-1

(x²+y²)/xy=-1

x²+y²=-xy

x²+y²+xy=0

(x²+xy+y²)=0Multyplying by (x-y) on both sides we get,(x-y)(x²+xy+y²)=(x-y)×0By eq1 we get,x³-y³=0

Hence x³-y³=0.


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