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Total Milk =13LTotal milk use =750*3=2250 mLthen = 2.250Lmake butter = 13-2.250 = 10.750LFinally answer is 10.750L

1L=1000ml13L=13000ml

750ml to each children that means (750×3=2250ml) in total is given.

Remaining milk = 13000-2250 =10750ml =10.75LTherefore 10.75L milk was made into butter

she maked butter of 9 L 750 ml

10.750 L. is a right answer

10.75 L milk was made into butter

correct answer is 9 L 750 ml

Total Milk=13LTotal Milk Use =750*3=2250MLthen =2.250Make Butter=13- 2.250 =10.750L Is the right answer for this questions....

She also maked butter of 9L 750ml

Your correct answer is 10.750L

Total milk=13L So,13L =13 * 1000ml =13000mlMilk that she give her 3 childrens =750ml*3 =2250mlRemaining milk =13000ml -2250ml= 10750ml = 10 l 750 ml （ans ）

10.750L is the right answer.

10.750 L milk was made into butter

Total milk=13lTotal milk use=750×3=2250 mlthen=2.250 lmake butter=13-2.250 =10.750 l answer.

10.750l is correct result..

herbal had milk=13l 750×3 =2250 ml so now makes butter =13-2.250l =10.750l is left over with him

10.75l is the correct answer

heerabai had 13 L of milk

in ml = 1300 then she gave 750 ml then 1300 - 750 =1150 ml

13L = 13000ml13000-(750)313000-225010750mlor 10.75Land you explain thik Qus batter then me 👍

10.750 l is the right answer

10.750l is the answer

Total Milk =13LTotal milk =750*3=2250 mLthen =2.250Lmake butter =13-2.250 =10.750LFinally answer is =10.750L

10.75L is correct and best answer please accept as a best 👍👍👍🥺🥺

she made butter using 10.750L

r is the correct answer

(d) 35+(-17)=-595 (e)-49+(-11)=539,(f) 28+(-35)=-980

(g) -13+(-23)=299(h)-17+50=-850(i)-41+(-117)=4749

d) 35-17= this is the answer

(d)=18,(e)=-60,(f)=-7,(g)=-36,(h)=33,(i)=-158

d-18; e-60 ;f- -7; g- -36 ;h-33 ;i- -158;

1kg=1000g200*100/100020%

Two circles with centres O and O’AB = PQTo prove: ∠AOB =∠PO’QProof:InΔAOB andΔPO’QAB = PQ (Given)OA = O’P (Radii)OB=O’Q (Radii)HenceΔAOB ≅ΔPO’Q [By SSS Congruence property]⇒∠AOB =∠PO’Q[CPCT]

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prove the two triangles congruent by ASS axiom

thank you so much

Let the common multiple be X(31X/23X)31X+23X=21654X=216X=431X = 31(4)=12423X=23(4)=92

thanks

let the first number be = 31x and the second number be= 23x

their sum=216

so,31x+23x=21654x=216x=216/54x=4

hence,the first number= 31x = 31*4=124the second number=23x=23*4=92

cube root of 216 is 6.

6³= 6×6×6 = 216.

Solution :- Sugar=200=200gmSugar+Eggs+Flour+DryFruit=200+800+600+200 =1800=1800gm

Sugar Percentage=(200/1800)×100=0.1111×100=11.11%

solution :200=200gm / sugar+eggs+flour+dryfruit=200+800+600+200=1800gm sugar percentage = (200/1800)×100= 0.1111×100 = 11.11

1kg = 1000gto convert gram to kg = divided by 10001) 200 g = 200÷1000 = 0.2kg2) 3470 g = 3470÷1000= 3kg 470 g

Conversion: 1kg =1000g(I)200g200/1000=0.2kg

(ii)3470g3470/1000=3.47kg

1 g=10^(-3)kgso 200g=200/1000=0.2kg

200×10^-3 I.e 0.2kg

for you dear t2

Gain % = 15% , Gain = 156CP = 156×100÷15= 1040.Gain % = 15% , CP = 1040SP = 100+15÷100×1040= 1196.SP = 1196 , Discount = 8 %MP = 100×SP÷100-Discount %= 100×1196÷100-8= Rs. 1300.So, Marked Price = Rs. 1300

(3×3×5×5×4)÷(7×8) = (9×25) ÷ (7×2) = 225/14

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LHS:(tan60°+1/tan60°-1)^2 =[(√3+1)/(√3-1)]^2=[(√3+1)(√3+1)/(√3-1)(√3+1)]^2=[(3+2√3+1)/(3-1)]^2=[(4+2√3)/2]^2 =[2(2+√3)/2]^2 =(2+√3)^2= 4 + 4√3 + 3= 7 + 4√3

RHS:(1 + cos30°)/(1 - cos30°)= (1 + cos30)^2/(1 - cos^2 30)= (1 + cos 30)^2/sin^2 30= (1 + cos^2 30 + 2cos30)/ sin^2 30= (1 + 3/4 + √3) /(1/4)= [(7 + 4√3)/4]/(1/4)= 7 + 4√3

LHS = RHS

Hence proved

1 Gaj or square Yard= 9 square feetsimilar 100gaj= 900square feet

Assuming you asked this question for quadratic equation

For example consider :4x² + 17x + 4

Now rule to split middle term is think two numbers whose sum is 17 and product is 16.

So, observing gives the numbers are 1 and 16

4x² + 16x + x + 4

4x( x + 4) + 1 ( x + 4)

( 4x + 1) ( x + 4)

A=6d=7Tn= a+ (n-1)d216=6+(n-1)*7n=31total no. of terms=31middle term=(31+1)/2 =16thT16= a+(16-1)d = 6+(15*7) =111therefore the middle term of the AP is111 answer

Vro font thora chota kar do

Bro font chota kar do kuch samagh nahi aa raha

222 + 554 = 776 is the answer

thanks for your help

1222+(554×245)+21=1222+135730+21=136,973

I=(3680*2*25)/(4*100)=460so amount=3680+460=4140

Too easy question = 11666

please don't mind the cuts

998+ 555=. 1543 is the answer hahagaha

1543 is the right answer .........

1543 is the right answer......

good answer

Firstly we will find the hcf of 55 and 210 by applying Euclid's division algorithm 210>55*210=55x3+45........(1)*55=45x1+10.......(2)*45=10x4+5..........(3)*10=5x2+0..........(4)so, HCF is 5from equation 3 we have 5=45-(10x4)

5 = 45 – (55 – 45)*4. ( from equation 2)

5 = 45 – 55*4 + 45*4

5 = 45 *5 – 55*4

5 = (210 – 55*3) *5 – 55*4

5 = 210*5 – 55*15 – 55*4

5 = 210*5 – 55*19

5 = 210a + 55b where a = 5, b = –19

I)6Let 2m = 6m = 3

m²+ 1 = 3²+ 1= 9 + 1 = 10

m²- 1 = 32- 1 = 9 - 1 = 8

check:

6²+ 8²= 36 + 64 = 100 = 10²

Hence, the triplet is 6, 8 & 10

ii) 14

Let 2 m = 14

m = 7

m²+ 1 = 7²+ 1 = 49 + 1 = 50

m²- 1 = 7²- 1 = 49 - 1 = 48

check:

14²+ 48²= 196 + 1304 = 2500= 50²

Hence, the triplet is 14, 48, and 50

iii) 16

Let 2 m = 16,

m = 8

m²+ 1 = 8²+ 1 = 64 + 1 = 65

m²- 1 = 82- 1 = 64 - 1 = 63

check:

16²+ 63²= 256 + 3969 = 4225 =65²Hence, the triplet is 16, 63 & 65Like if you find it in

When n is a member of a pythagorean tripplet then the triplet is :

n² - 1

2n

n² + 1

In our case n = 323

Doing the substitution we have :

n² - 1 = 323² - 1 = 104328

2n = 323 × 2 = 646

n² + 1 = 104330

The tripplet is thus :

104328, 646, 104330

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32×32=102435×35=122586×86=739671×71=504146×46=2116

6,8,1014,48,5012,16,20