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It is the diagram for the equation. Now once this is calculated one can find the value of Lambda.

So the final solution shall be as below.

thanks

As we know, Meena gives an interest of rupees 45 for 1 year at 9% rate per annum;P=?;R=9% p.a.;T=1 year∴PRT/100=45=>P=4500/RT=4500/9=500

∴Sum=Rs.500

3 + sqrt(2)/ 4 sqrt(2)

To rationalise Multiply and Divide by 4 sqrt(2)

We get,(3+ sqrt(2))*4sqrt(2)/4sqrt(2)*4sqrt(2)

= (12 sqrt(2) + 8)/ 4*2

= 4(3sqrt(2) + 2)/8

= (3 sqrt(2) + 2)/2

5324 = 4000(1+R/100)(1+R/100)(1+R/100) 1331/1000 = (1+R/100)(1+R/100)(1+R/100) 11*11*11/(10*10*10) = (1+R/100)(1+R/100)(1+R/100) 11/10 = 1 + R/100 R/100 = 11/10 - 1 = 1/10 R = 10%

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The sum= 11 Let the number which should be added = x 9+x=11x=11-9=2The certain number is 10..

you should add 2; i.e ,9+2=11

given x=y means corresponding angle are equal so r is parallel to m similarly a=b means again corresponding angle equal so m is parallel to n. therefore r||m and m||n which gives r||n .

Let the sum be x and rate be r%

then, (x*r*15)/100 = 3x

=> r = 20%

[Important to note here is that simple interest will be 3x not 4x, because 3x+x = 4x]

25 वर्ष है भाई उम्र

25 years old age will be.

25 years old is the answer

ब 25 वर्ष है उतर पकका

25 years it will be of age

suppose sum is p so after interest sum will be 49p/40 so interest = 49p/40-p = 9p/40 9p/40 = (p*R*5)/(2×100) so R = (9×2×100)/(40×5) = 9%

Let the present age of son = x

and the present age of father = y

Difference in their ages = y - x

Given, when the ages will be as old as father today their ages will add up to 126 years

=> {x + (y - x)} + {y + (y - x)} = 126

=> {x + y - x} + {y + y - x} = 126

=> y + 2y - x = 126

=> 3y - x = 126 .................1

Again, when the father as old as son is today, their ages add up to 38 years

=> {y + (x - y)} + {x + (x - y)} = 38

=> {y + x - y} + {x + x - y} = 38

=> x + 2x - y = 38

=> 3x - y = 38 .................2

Multiply by 3 in equation 2, we get

=> 9x - 3y = 114 ..............3

Add equation 1 and 3, we get

8x = 240

=> x = 240/8

=> x = 30

From equation 1, we get

3y - 30 = 126

=>3y = 126 + 30

=> 3y = 156

=> y = 156/3

=> y = 52

So, the present age of son = x = 30 years

and the present age of father = y = 52 years

SI = P*R*T/100Given P = 1600, R = 15%, T = 18/12 = 3/2

SI = 1600*15*3/200 = 48*15/2 = 360

Amount due after 18 months = 1600 + 360 = 1960

Amount already paid = 1800

Amount he still owes = 1960 - 1800 = Rs 160

(3) is correct option

We know,SI = P*R*T/100

To calculate monthly income for given scenarioP = 4000, R = 14 - 10 = 4%,T = 1/12

SI = (4000*4*1)/(12*100) = 160/12 = 13.35

(4) is correct option

(a+b+c)(a+b+c) = a*a + b*b + c*c + 2ab + 2bc + 2ca a = x b = 2y c = 4z (x+2y+4z)(x+2y+4z) = x*x + 4y*y + 16z*z + 4xy + 16yz + 8zx

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thanks sir

Let sin^-1(1-x) = A So Sin A = 1-xlet Sin^-1 x = B So Sin B = x

Given A - 2 * B =π/2 A - π/2 =2B Cos (A -π/2) = Cos (2 B) SinA = 1 - 2 Sin² B 1 - x = 1 - 2 x² 2 x² - x = 0 x = 0 or x = 1/2

58.54 is the answer of the following

58.54 is the correct answer.

58.54 is the best answer

3 6 7 gjgjgig mgigiig jfufgi

y = X -4 y= (-3)-4y= -7

y= x-4y=0 -4y= -4

y=x-4y=6-4y=2

so bro

sorry bro

sorry that got mistake with 3/5 it was 1

Do you mean the power of (3/5) is 1?

the answer is 1 for this question

RAVI septa route to a party

1 is the right answer

Right answer is the best 1

1 is the correct answer of the given question

200 your question andwer

1 is the correct answer

x2_7x+10x2+x-6. _•__x2-x--20

1is the correct answer of this ques

1 is the right answer given in the question

According to me, 1 is the right answer of this question

1 is the answer of the following equations or statement

1 is the correct answer for this question 👍 👍👍👍👍👍

let total length =xx of 2/3=2x/3remain part = x-2x/3=3x-2x/3=x/3 part2x/3=1202x=360x= 360/2=180m1st part = 2×180/3=120m2nd part= 180/3=60mm

the right answer is a 1st parr=2.180/3=120m2nd part =180/3=60m

hope this will help you like my answer and MARK IT AS BEST ANSWER.

The right answer is a 1 st parr=1.180/3=120m2nd part =180/3=60m

60 m is correct answer

x - 10 + x - 20 + x - 35 + x + 25 = 360 4x - 40 = 360 4x = 400 x = 400/4 = 100

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thank you

please like my answer then I will also like your answer

........................

61 is the right answer.

61 is the correct answer.

Any quadratic equation having zeroes a and b can be written asx² - (a+b)x + ab = 0we have given a+b = 3 and a³ + b³ = 7so we know (a+b)³ = a³+b³ +3ab(a+b)27 = 7 + 3ab(3)20 = 9 abab = 20/9soEquation is x² -3x+20/9 = 09x² -27x +20 = 0no given option is correct

pls give correct reply

2x=50-202x=30 x=30/2x=15 answee

Area of square OABC=l²=20²=400cm²---(1)

To Find The Radius join OB

Now by applying Pythagoras in triangle OAB,We Get,

OA²+AB²=OB²

=400+400=OB²(as OABC Is a square And OA=AB=20)

Let OB²=r²

Area of quadrant =1/4*π*r²

=1/4*314/100*800

=628cm²-----(2)

Now Area Of Shaded Region =(2)-(1)

=628-400

=228cm²

a) flour to butter=200/160=(4×5)/(4×4)=5:4b) flour to sugar=200/120=(4×5)/(4×3)=5:3c) butter to sugar=160/120=(4×4)/(4×3)=4:3so these 3 are in ration 4:5:3now suppose 192 g is suppose quantity so each butter is 4/12*192=64g flour=5/12*192=80g sugar=3/12*192=48g

a.5:4b.5:3c.4:3this is the correct solution

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