MJUQ406513. In Fig., a square OABC is inscribedin a quadrant OPBQ. If

1.	MJUQ406513. In Fig., a square OABC is inscribedin a quadrant OPBQ. If OA = 20 cm,find the area of the shaded region.(Use A = 3.14)Sol. Side of a square OABC = 20 cmArea of a square OABC = (20)2- 100 cm2
Answer» Area of square OABC=l²=20²=400cm²---(1) To Find The Radius join OB Now by applying Pythagoras in triangle OAB,We Get, OA²+AB²=OB² =400+400=OB²(as OABC Is a square And OA=AB=20) Let OB²=r² Area of quadrant =1/4πr² =1/4314/100800 =628cm²-----(2) Now Area Of Shaded Region =(2)-(1) =628-400 =228cm²

MJUQ406513. In Fig., a square OABC is inscribedin a quadrant OPBQ. If OA = 20 cm,find the area of the shaded region.(Use A = 3.14)Sol. Side of a square OABC = 20 cmArea of a square OABC = (20)2- 100 cm2

Answer»

Area of square OABC=l²=20²=400cm²---(1)

To Find The Radius join OB

Now by applying Pythagoras in triangle OAB,We Get,

OA²+AB²=OB²

=400+400=OB²(as OABC Is a square And OA=AB=20)

Let OB²=r²

Area of quadrant =1/4*π*r²

=1/4*314/100*800

=628cm²-----(2)

Now Area Of Shaded Region =(2)-(1)

=628-400

=228cm²