1.

When the son will be as old asfather today, the sum of their ageswill be 126. when the father wasold as his son today, the sum of thisages then was 38. Find their presentage. [Ans. 52 yrs. and 30 yrs.]

Answer»

Let the present age of son = x

and the present age of father = y

Difference in their ages = y - x

Given, when the ages will be as old as father today their ages will add up to 126 years

=> {x + (y - x)} + {y + (y - x)} = 126

=> {x + y - x} + {y + y - x} = 126

=> y + 2y - x = 126

=> 3y - x = 126 .................1

Again, when the father as old as son is today, their ages add up to 38 years

=> {y + (x - y)} + {x + (x - y)} = 38

=> {y + x - y} + {x + x - y} = 38

=> x + 2x - y = 38

=> 3x - y = 38 .................2

Multiply by 3 in equation 2, we get

=> 9x - 3y = 114 ..............3

Add equation 1 and 3, we get

8x = 240

=> x = 240/8

=> x = 30

From equation 1, we get

3y - 30 = 126

=>3y = 126 + 30

=> 3y = 156

=> y = 156/3

=> y = 52

So, the present age of son = x = 30 years

and the present age of father = y = 52 years



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