Write a Pythagorean triplet whose one member is.(ii) 14(ii) 16

1.	Write a Pythagorean triplet whose one member is.(ii) 14(ii) 16
Answer» I)6Let 2m = 6m = 3 m²+ 1 = 3²+ 1= 9 + 1 = 10 m²- 1 = 32- 1 = 9 - 1 = 8 check: 6²+ 8²= 36 + 64 = 100 = 10² Hence, the triplet is 6, 8 & 10 ii) 14 Let 2 m = 14 m = 7 m²+ 1 = 7²+ 1 = 49 + 1 = 50 m²- 1 = 7²- 1 = 49 - 1 = 48 check: 14²+ 48²= 196 + 1304 = 2500= 50² Hence, the triplet is 14, 48, and 50 iii) 16 Let 2 m = 16, m = 8 m²+ 1 = 8²+ 1 = 64 + 1 = 65 m²- 1 = 82- 1 = 64 - 1 = 63 check: 16²+ 63²= 256 + 3969 = 4225 =65²Hence, the triplet is 16, 63 & 65Like if you find it in

Answer»

I)6Let 2m = 6m = 3

m²+ 1 = 3²+ 1= 9 + 1 = 10

m²- 1 = 32- 1 = 9 - 1 = 8

check:

6²+ 8²= 36 + 64 = 100 = 10²

Hence, the triplet is 6, 8 & 10

ii) 14

Let 2 m = 14

m = 7

m²+ 1 = 7²+ 1 = 49 + 1 = 50

m²- 1 = 7²- 1 = 49 - 1 = 48

check:

14²+ 48²= 196 + 1304 = 2500= 50²

Hence, the triplet is 14, 48, and 50

iii) 16

Let 2 m = 16,

m = 8

m²+ 1 = 8²+ 1 = 64 + 1 = 65

m²- 1 = 82- 1 = 64 - 1 = 63

check:

16²+ 63²= 256 + 3969 = 4225 =65²Hence, the triplet is 16, 63 & 65Like if you find it in

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