Explore topic-wise InterviewSolutions in Current Affairs.

In the given figure, LM || CB

By using basic proportionality theorem, we get,AM/MB = AL/AC ...(i)Similarly, LN || CD∴ AN/AD = AL/AC ...(ii)From(i)and(ii), we getAM/MB = AN/AD

In the given figure, LM || CBBy using basic proportionality theorem, we get,AM/MB = AL/AC ...(i)Similarly, LN || CD∴ AN/AD = AL/AC ...(ii)From(i)and(ii), we getAM/MB = AN/AD

alpha and beta are zeroes that means they are solutions of the equation. To get that we have to compare equation with zero.2x^2+7x-4=02x^2+8x-x-4=02x(x+4)-1(x+4)=0so x=-4,1/2

now we have to find equation whose zeroes are 1/alpha and 1/betaso values are = -1/4,2so equation is (x+1/4)(x-2)=x^2-2x+x/4-1/2so equation is x^2-7/4x-1/2

LM || CBBy using basic proportionality theorem, we get,AM/MB = AL/AC ...(i)Similarly, LN || CD∴ AN/AD = AL/AC ...(ii)From(i)and(ii), we getAM/MB = AN/AD

thankyou soo much

Given that the remainder is (x + a)⇒ (4k – 25 + 16 – 2k)x + [10 – k(8 – k) ] = x + a ⇒ (2k – 9)x + [10 – 8k + k2] = x + aOn comparing both the sides, we get2k – 9 = 1

⇒ 2k = 10∴ k = 5Also 10 – 8k + k2= a⇒ 10 – 8(5) + 52= a⇒ 10 – 40 + 25 = a∴ a = – 5

For first km taxi fare = 15For each additional km taxi fare = 8

Then taxi fare for trip of n km= 15, 8, 8, 8, 8.........n

This is not Airthmetic Progression as in AP difference between any two successive term is same.

आरुणि का शरीर सर्दी से अकड़ने लगा किंतु उसे तो एक ही धुन... गुरु की आज्ञा का पालन। बहता हुआ पानी कल-कल करता मानो आरुणि को कहने लगा-

मैं वर्षा का बहता पानी,

मेरी चाल बड़ी तूफानी।

उठ आरुणि अपने घर जा,

रास्ता दे दे, हट जा, हट जा।।

मगर गुरु भक्त बालक आरुणि का उत्तर था-

गुरुजी का आदेश मुझे है,

मैं रोकूंगा बहती धारा।

जय गुरु देवा, जय गुरु देवा,

आज्ञा पालन काम हमारा।।

By Thales theorem or basic propositionality Theorem

IN∆ABCLM||BC so by B.P.TAL/AC=AM/AB-----------(1)

IN∆ADC

AL/LC=AN/AD------(2)from equation 1 &2 L.H.S is same so R.H.S will also same.soAM/AB=AN/AD

In parallelogram ABCD so,

angle A = angle C(opposite angle are equal)

angle A = 55°

Now in parallelogram AGFE,So,angle A = angle F (opposite angle are equal)

angle F = 55°

Area of four walls = 2(l+b) * h

= 236m * 4.5m

= 1,062 m^2

Hence cost to do that at rate of ₹8.40 per square metre = ₹1062*8.40

= ₹8,920.8

from 1 and 2 angle PQS = angle PRT

Like my answer if you find it useful

Given:

ΔABC is an isosceles∆ with AB = AC, OB & OC are the bisectors of ∠B and ∠C intersect each other at O. i.e, ∠OBA= ∠OBC & ∠OCA= ∠OCB

To Prove: i)OB=OC ii)AO bisects ∠A.

Proof:

(i)In ∆ABC is an isosceles with AB = AC, ∴ ∠B = ∠C [Since , angles opposite to equal sides are equal]

⇒ 1/2∠B = 1/2∠C [Divide both sides by 2]

⇒ ∠OBC = ∠OCB & ∠OBA= ∠OCA.......(1) [Angle bisectors]

⇒ OB = OC .......(2) [Side opposite to the equal angles are equal]

(ii)In ΔAOB & ΔAOC, AB = AC (Given) ∠OBA= ∠OCA (from eq1) OB = OC. (from eq 2)

Therefore, ΔAOB ≅ ΔAOC ( by SAS congruence rule)

Then, ∠BAO = ∠CAO (by CPCT)

So, AO is the bisector of ∠BAC.