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\begin{array} { l } { \text { In Fig. } 6.18 , \text { if } \mathrm { LM } \| \mathrm { CB } \text { and } \mathrm { LN } \| \mathrm { CD } \text { , prove that } } \\ { \frac { \mathrm { AM } } { \mathrm { AB } } = \frac { \mathrm { AN } } { \mathrm { AD } } } \end{array} |
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Answer» LM || CBBy using basic proportionality theorem, we get,AM/MB = AL/AC ...(i)Similarly, LN || CD∴ AN/AD = AL/AC ...(ii)From(i)and(ii), we getAM/MB = AN/AD thankyou soo much |
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