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let the no. of rs 5 coins be x

& the no. of rs 1 coin be y

& no. of rs 2 coins be 3 x

a.q.t total no. of coins = 160

x + 3x+y = 160

4x + y = 160 eq. 1

again a.q.t total rs = 300

5x + 2(3x) + 1y = 300

11x + y = 300 eq. 2

by elimination method

on subtracting both the equations

4x + y = 160

-11x -y = -300

=-7x =-140

x =20

on putting the the value of x in eq 2

4(20) + y =160

80 + y = 160

y =80

now,

no of rs 2 coins = 3(20)

= 60

no. of rs 5 coins = 20

no. of rs 1 coins=80

it should not be done with two variables

thanks

27,000 is the right answer of the following

27000 is the right answer

27000 is the answer of the following

27000 is right answer

27000 is correct answer.

₹27,000 is the answer of the question

Correct answer is ₹27,000 of the following question answer

angle prt =110 angle p=35 angle q=35

कृपा लाइक करें अगर सहायक हो

volume of sphere is 4/3πr^3=4/3*22/7*7=29.33cm^3

thanks sister

Hi

26/5 is answer and 90/2 Is answer of second

S.I is given by:-I= prt/100

Let n no. Of pouches can be preparedThenn x 30 x 20 = 2500 x 600n = 25002500 pouches

p

2 Kg=2000gm.2000:300::100:? =(100×300)÷2000=30%

your answer is 15 percentages

answer of this question will be 30 percent

X/100×1000=300X=300/10X=30

ANSWER - 30%

2 kg = 2000 g.2000×?/100 = 300?=300×100/2000?=30/2?=15 Ans.

2kg=2000g2000x?/100 =300?=300x100/2000?=30/2?=15 the answer is 15%

15% is the correct answer.

Suppose its x percentage of 2kgNow we know that 1kg= 1000gmSo 2kg= 2000gNow2000*x/100= 3002000x= 300002x= 30X= 15 So answer = 15 percentage

16/45=0.35555555555555………

the correct answer is 16/45=0.35555555555555

0.3555555555 is the right answer

According to the question,

Principal = 6500

Rate = 8%

Time = 73 days

Now,

S.I=prt/100

=6500×8×73/365×100=104

Simple Interest will be 104 .Ans

decimal representation22/7=3.14

find 5 rational nos between -2 and 5

Consider A as theta and solve

Given,

∠PQR= ∠PRQ

To prove:∠PQS= ∠PRT

Proof:

∠PQR+∠PQS =180° (by LinearPair axiom)

∠PQS=180°– ∠PQR— (i)

∠PRQ+∠PRT= 180° (by Linear Pair axiom)

∠PRT= 180° – ∠PRQ

∠PRQ=180°– ∠PQR — (ii)

[∠PQR = ∠PRQ]

From (i) and (ii)

∠PQS= ∠PRT= 180°– ∠PQR

∠PQS= ∠PRT

Hence, ∠PQS = ∠PRT

1 divide 256 by 10

2 the remainder will be=6

ans = 6(it is the smallest no which should be subtracted from 256 so that it is exactly divisible by 10)

simple interest =p*r*t/100I=prt/100prt=100xI

Consider ΔOPS and ΔOPTOS = OT ( radii)∠OSP = ∠OTP = 90 (tangents are perpendicular to the radii)SP = ST ( tangents to a circle from the external point are congruence)ΔOPS ≅ ΔOPT ( By SAS criterion)The corresponding parts of the corresponding triangles are congruent.∠OPS = ∠OPTsince ∠SPT = 120° and ∠OPS = ∠OPTwe have ∠OPS = ∠OPT = 60°∠POS = ∠POT = 30°Consider In a ΔPOSsin 30° = PS / OP1 / 2 = PS / OPOP = 2PS.

Face value= rs.1200market value=rs. 120dividend(income)= 1200×8 /100= rs.96

1/7 = 0.142857142857...hence option a 0.142857

what is your question

what is your question

seventh math book of DAV has answers on its back

pearson math is best for 7

there are so many books for 7th classyou should use ncert bookand the book which is suggested by your maths teacher

What is your question

what is your questions

sinA= √3/2cosecA=2/√3cos^2A= 1- sin^2A = 1-3/4 = 4-3/4=1/4cosA= √1/4=1/2secA= 2tanA= sinA/cosA = √3/2 / 1/2 = √3cotA= 1/√3

Mark one specific question to be solved please!

sin²(45°) + cos²(30°) + tan(45°)

1/(√2)² + (√3/2)² + 1

1/2 + 3/4 + 1

3/2 + 3/4

(6+ 3)/4

9/4

30+cos 60=30+1/2=30.5