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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
lfsin(A + 2B)-and cos (A + 4B)-0, A > B, and A + 4B90, then find A and B. |
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Answer» Sin(A+2B)=√3/2sin(A+2B)=sin60 {sin60=√3/2}on comparing---A+2B=60---eq.1 cos(A+4B)=0cos(A+4B)=cos90 {cos90=0}on comparing ---A+4B=90----eq. 2 on subtracting eq.1 by eq.2A+4B-A-2B=90-602B=30B=15° put in eq.1A=30° |
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| 2. |
p(5p^2 - 80) को 5p(p-4) से भाग दीजिए | |
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Answer» p(5p^2 -80)/ 5p(p-4)p5(p^2-16)/5p(p-4)Now 5p will get cancelledand a^2-b^2=(a+b)(a-b)(p^2-16)=(p+4)(p-4)therefore(p+4)(p-4)/(p-4)=p+4 |
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| 3. |
4p - 6 .5p + 4 |
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| 4. |
By remainder theorem, find the remainder when 3x - 4x - 3x -- lis divided by x + 12 |
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| 5. |
p(x)=6x³-x²-10x-3;g(x)=2x-3,find the remainder and verify by remainder theorem |
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| 6. |
Q2.- 2x + x + 1is divided by (x - 1) using RemainderFind the remainder whentheorem |
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Answer» By remainder theorem, When p(x) = x³ - 2x² + x + 1 divided by (x-1) remainder is p(1) = 1³ - 2 × 1² + 1 + 1 p(1) = 1 - 2 + 2 = 1 1 is the remainder |
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| 7. |
Using Remainder theorem, find the remainder when x3-2x-4x-1 is divided by x+ |
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Answer» x^3-2x^2-4x-1as it is divided by X+1/3 put in X=-1/3hence(-1/3)^3-2(-1/3)^2-4(-1/3)-1=-1/27-2/9+4/3-1=-9/27-6/27+36/27-27/27=-9-6+36-27/27=-6/27=-2/9 I can't understand |
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| 8. |
Find the greatest number that can divide 89, 112 and 158, when 3 isadded to each one of them.iuudod by12 and 16 leaves no |
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| 9. |
3. सरल कीजिए:) 23.1123.0 (3) canसरc) 7. ।3({}}114 |
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Answer» (1) 2^2/3 * 2^1/5= (2)^[2/3 + 1/5]= (2)^[(10 + 3)]/15= (2)^13/15 (2) (1/3^3)^7= (1/3^21)= 3^-21 (3) 11^1/2 / 11^1/4= 11^[1/2 - 1/4]= 11^[(2 - 1)/4]= 11^1/4 (4) 7^1/2 * 8^1/2= (7*8)^1/2= (56)^1/2 |
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| 10. |
22-52²+ 112-7 is divided by 2x-3 |
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Answer» yes it is divisible itolis 2x+3 is the correct answer me |
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| 11. |
4. Find the smallest number which when divided by 8, 12, 15, 18 and 24 leaves 3 as remainder.Solution |
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| 12. |
4. Find the smallest number which when divided by 8, 12, 15, 18 and 24 leaves 3 as remainder.Solution: |
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| 13. |
manjit bought an iron bale lor2 12160 and baid 2340 borits transportation. Then he soldit for a 12875. Find his gainper cent. |
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| 14. |
1.If a +1, 3a and 4a + 2 are in A.P., find the value of a.यदि a +1, 3a और 4a + 2 समानांतर श्रेणी में हैं, तो a का मान बतायें। |
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Answer» 6a=5a+3a=3 is the correct answer of the given question a = a+1d = 2a - 1n = 3an = 4a + 2 a = 3 hoga |
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| 15. |
20. E and F are points on the sides PQ and PR respectively of a APOR. Show that EF lORIf PQ = 1 .28 cm, PR= 2.56 cm, PE0.18 cm and PF-0.86 cm.540, find a. |
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Answer» Like if it is useful |
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| 16. |
4a^2-4b^2+4a+1 |
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Answer» If you find the solution helpful, Please give it a 👍 |
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| 17. |
2) 4A-2)(x-1) 7-3littONON |
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Answer» [{(2/5)^2}^4]^x+2 = [{(2/5)^-2}^(x-1)]^-3 {(2/5)^8}^x+2 = {(2/5)^(-2x+1)}^-3 (2/5)^8x+16 = (2/5)^6x-3 8x + 16 = 6x - 3 8x - 6x = - 16 - 3 2x = - 19 x = - 19/2 |
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| 18. |
Exercise 621.Add the followings:(a) 5x + 2x(c) 4p +(-5p) + 3pAdd the followings:(a) 2x^2 -4x + 6, 5x- 3x^2-1 and 3(b) 4a^2b +3b^2 - 5c^2+2, 4b^2 - 4a^2(b) 3y +(-4(d)(-2p) +2. |
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| 19. |
() a + 10a + 25 |
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| 20. |
Tick the correct answer in the following and justify your choice : If the perimeter andarea of a circle are numerically equal, then the radius of the circle is(A) 2 units5.(B) π units(C) 4 units(D) 7 units |
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| 21. |
- The length of a ranglar ale musim 25 cm and to50 cm Find the perimeter of the table top |
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Answer» perimeter=2(325+50) CM =2×375 =750cm 750 cm is the right answer |
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| 22. |
0 a' + 10a + 25 |
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Answer» a2 + 10a + 25 = a2 + 5a + 5a + 25 = a (a+5) + 5 (a + 5) Therefore, the factors are a+5 and a+5 |
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| 23. |
llowing and justify your choice: If the perimeter and theTick the correct answer in the foarea of a circle are numerically equal, then the radius of the circle is(A) 2 units5.(B) t units(C) 4 units(D) 7 units |
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| 24. |
o a' + 10a+ 25 |
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Answer» a^2+(5+5)a+25= 0a^2+5a+5a+25= 0a(a+5)+5(a+5)=0(a+5)(a+5)= 0a= -5 and a= -5 |
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| 25. |
Factorise the followin( a' + 10a+ 25 |
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| 26. |
Which are perfect trinomial10a+ 162. |
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Answer» a²+10a+16= a²+8a+2a+16= a(a+8)+2(a+8)= (a+2)(a+8) This is not a perfect square trinomial. |
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| 27. |
2. The lid of a rectangular box of sides 40 cm by 10 cm is sealed all round withtape. What is the length of the tape rĂŠquired?3. A table-top measures 2 m 25 |
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Answer» thank you thanks |
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| 28. |
Find the perimeter of a rectangular table top with sides 1 m 15 cm, and 80 cm. |
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Answer» Perimeter of table top= 2 (length + breadth)= 2(115 + 80)= 2(195)= 390 cm |
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| 29. |
9. Find the perimeter of a rectangular table top with sides 1 m 15 cm, and 80 cm. |
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Answer» Perimeter = sum of the sides = 100 cm + 15 cm + 80 cm = 195 cm |
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| 30. |
00(m9. Find the perimeter of a rectangular table top with sides 1 m15 cm, and 80 cm. |
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| 31. |
20. The length and breadth of the rectangular top of your table are 1.8 m and I m respec-tively. If each of your book is 15 cm long and 10 cm broad, how many books can be keptside by side on the tablei? |
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| 32. |
Table Top measure com 25 cm de- 1m 50cm. what is the perimeter of thetable top |
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Answer» My answer is 7m 50 cm |
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| 33. |
a table top measure 2 metre 25 CM by 1m 50 cm what is the perimeter of the table top |
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| 34. |
(1) Prove that\operatorname{se}\left(\frac{51}{80}\right)+\log \left(\frac{44}{85}\right)-\log \left(\frac{99}{160}\right)-\log \left(\frac{8}{15}\right)=0 |
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Answer» 51=17×380=16×544=11×2×285=17×599=11×3×3160=16×5×28=2×2×215=3×5log(a/b)=loga-logblogab=loga+logblog17+log3-log16-log5+log11+log2+log2-log17-log5-log11-log3-log3+log16+log5+log2-log2-log2-log2+log3+log5=0 |
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| 35. |
Four square tables with side i 2m each are placed end to end to form one big rectangular table.What is the perimeter of this rectangular table?9. |
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Answer» Length of the rectangular table= 4(1.2)m=4.8mbreadth=1.2mperimeter=2(1.2 + 4.8) m=(2 x 6)m=12 m |
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| 36. |
5. Three angles of a quadrilateral are in the ratio 4: 5:6. Thesum of the least and the greatest of these is 160. Find theangles of the quadrilateral. |
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| 37. |
Write four more rational numbers in each of the following patterns3 -6 -9 -125'10 15' 204 8 12 |
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| 38. |
19. Find the lengths of the sides labeled x and y. Then find the perimeter. Label your answerusing correct units6.8ft4ft9.3ft15.4ft9.6ft5.1ft |
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Answer» thanks |
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| 39. |
निम्नलिखित समीक| 7-6r 1| 915 |
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| 40. |
15 xy - 6r + 5y-2 |
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Answer» hello hello |
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| 41. |
(il) The amount of air present in the cylinder when a vacuum pump removes each time 14of their remaining in the cylinder |
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| 42. |
42-7r-6r+r2=12 |
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Answer» 42 - 7r - 6r + r*r = 12 r*r - 13r + 30 = 0 (r-10)(r-3) = 0 r = 3 , 10 thank u so much |
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| 43. |
tfind the roots of the quadratic equation 6r-x-2=0. |
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| 44. |
ito 6 |
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| 45. |
Find ito are |
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| 46. |
of the angle of a Triangle is 160iTo prove sum |
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| 47. |
Fig. 12.1OFind the area of a triangle two sides of which are 18cm and 10cm and the perimeter is10. 11715 nnd its nerimeter is 540cm. Find its area. |
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| 48. |
28. The value of a in the following pattern is124821639101520 |
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Answer» 16=2+4+1039=16+8+15so a=39+12+20=71 |
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| 49. |
I.Four alternatives are given for each of tstatements. Choose the correct alternacorrect answer using the letter of the asheet:The birth place of Jesus Christ isa) Meccab) Madina1. |
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Answer» Bethlehem Birthplace of Jesus Christ The birth place of Jesus Christ is Bethlehem |
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| 50. |
ite 'T' for true and 'F' for false for-) Area of a triangle = (base x height |
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