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lfsin(A + 2B)-and cos (A + 4B)-0, A > B, and A + 4B90, then find A and B. |
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Answer» Sin(A+2B)=√3/2sin(A+2B)=sin60 {sin60=√3/2}on comparing---A+2B=60---eq.1 cos(A+4B)=0cos(A+4B)=cos90 {cos90=0}on comparing ---A+4B=90----eq. 2 on subtracting eq.1 by eq.2A+4B-A-2B=90-602B=30B=15° put in eq.1A=30° |
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