This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
MODERN'S abc OF MATHEMATIOS.lrr the fig., o<AOB = 70°. Cis the centre of the circle andalculate the values of (i) LOCA1centre o(ii) ZOAC.70° |
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| 2. |
(i) 6g+4b2a+5b |
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Answer» 8a + 9b hit like if you find it useful |
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| 3. |
37. In the given figure TA is a tangent to thecircle ABC at A. If mZTAB=80° andmZBAC=30°, then what is m ABC ?(A) 50°(C) 70°(B) 60°(D) 80° |
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Answer» As its linear anglesso 80+30+CAT= 180CAT= 70°now angle BAT= 80° = ABC= 80° |
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| 4. |
2a+3b =83a-4b=-5 |
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Answer» 2a + 3b = 8a = (8 - 3b)/2.......(1) 3a - 4b = - 5..........(2) Put value of a from eq(1) in eq(2)3(8-3b)/2 - 4b = - 524 - 9b - 8b = - 1034 = 17bb = 34/17 = 2 From eq(1)a = (8 - 3*2)/2 = 2/2 = 1 |
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| 5. |
(i)y +18=-70 |
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| 6. |
17) If 2A-4B-5C, find A:B:C. |
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Answer» Assume 2a = 4bso a/b = 4/2 = 16/4(cross multiply and multiply 4.we do this in order to get b=b for the next step)also 4b = 5cso b/c = 5/4 |
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| 7. |
IV) 4If A 2a - 4b, B 3a 5b and C -a + 2b, then A + B-C is |
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| 8. |
13.Find the sum and product of zeros of the polynomial 6x² - 3 - 7x |
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| 9. |
(iv) Determine, the type of triangleAB= 4cm,BC=5 cm,CA=5 cm |
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| 10. |
of- find the value of the polynomial6x-2x2 +3 at |
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Answer» first ka bhi dusre ka mines |
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| 11. |
find the value of the polynomial 6x-2x²+3 at (i) X=0 (ii) X=-1 |
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Answer» i)3ii)-5 just put the value of x in the equation ansafter putting given value in 6x-2x^2+3i) putting x=0=6(0)-2(0)^2+3=0-0+3=3 ans ii) putting x=-1=6(-1)-2(-1)^2+3=-6-2+3=-8+3=-5 ans |
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| 12. |
In △ABC, LB = 45° and LC= 65°.In △ABC, state greatest side with reason. |
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| 13. |
2. If A is a square matrix of order 3 and 2A k|Al, then find the value of k. |
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Answer» For a squarematrix of order n, |kA| = k^n|A||2A| = k |A|2^3|A| = k |A|k=8 |
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| 14. |
( \frac \operatorname sin 77 ^ \circ \operatorname cos 13 ^ \circ ) ^ 2 %2B ( \frac \operatorname cos 77 ^ \circ \operatorname sin 13 ^ \circ ) ^ 2 - 2 \operatorname cos ^ 2 45 ^ \circ |
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| 15. |
EXERCISE 11.21. Construct a triangle ABC in which BC 7cm, 4B 75° and AB +AC 13 cm. |
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| 16. |
Construct a triangle ABC in which BC7cm, LB # 75° and AB+A |
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| 17. |
-isoscelestarianglewith AB=AC and LB=7018ABC |
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| 18. |
EXERCISE 11.2a triangle ABC in which BC-7cm, 4B-75 and AB-AC-18m |
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Answer» post clear photo of the question |
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| 19. |
EXERCISE 11.2ruct a triangle ABC in which BC-7cm, 4B-75 and AB +AC-13 cm. |
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| 20. |
(1) 6a+4b2a+ 5b |
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Answer» PLEASE LIKE AND SHARE THIS APP |
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| 21. |
if alpha and beta be the zeros of the polynomial 2 X square + 5 x plus Que such that Alpha square plus beta square + alpha beta equal to 21 by 4 find k |
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| 22. |
X square plus 8x plus 16 |
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Answer» Plz can you tell me this answer with using identity a square plus 2ab plus b square |
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| 23. |
what is c to 5 square plus 13 square |
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Answer» C = 5²+13²C = 25 + 169C = 194 |
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| 24. |
if a + b + c equal to 6 and a square + b square + c square equals to 34 ,then ab+bc+ca= |
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Answer» Given : a+b+c = 6 a² + b² + c² = 34 We know, (a+b+c)² = a² + b² + c² + 2(ab+bc+ac) 6² = 34 + 2(ab+bc+ac) 36 - 34 = 2(ab+bc+ac) 2/2 = (ab+bc+ac) (ab+bc+ac) = 1 |
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| 25. |
a plus b whole square |
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Answer» (a+b)^2= a square + b square+ 2ab |
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| 26. |
a^ 2 + 4b^2 = 12ab log(a + 2b) |
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Answer» a^2 + 4b^2 = 12ab a^2 + (2b)^2+4ab = 12ab + 4ab (a+2b)^2 = 16ab Take log on both sides 2log(a+2b) = log16 + logab log(a+2b) = 1/2 (4log2+logab) log(a+2b)=2log2+1/2logab tq |
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| 27. |
solve the equation 9xsquare-9(a+b) x+ (2a square +5ab +2b square) =0 |
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| 28. |
(2a-b)square+(2a-b)-8 |
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Answer» (2a-b)^2+(2a-b)-84a^2+b^2-4ab+2a-b-84a^2+2a+b^2-b-4ab-8 |
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| 29. |
solve the value of xand y 2(ax_by) +(a+4b)=02(bx+ay) +(b_4a)=0 |
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| 30. |
(76 + 29) (0 рдиреЗ 4b) |
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Answer» (7a + 2b) ( a + 4b) 7a² + 28ab + 2ab + 8b² 7a² + 8b² + 30ab |
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| 31. |
Expand : (3a â4b + "oc)2| |
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Answer» Two adjacent sides of a parallelogram are 10cm and 12cm. If it's one diagonal is 14cm long, find the area of the parallelogram. |
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| 32. |
foctorize the following.(1)a^2+4b^2-4ab |
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Answer» a² + 4b² - 4ab = (a)² + (2b)² - (2)(a)(2b) = (a - 2b)² |
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| 33. |
16 (a + b)2- 4a -4b |
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Answer» Factorization (a+b)² - 4a - 4b (a+b)² - 4 ( a + b) Take ( a + b) common (a+b) ( a + b - 4) Please hit like button if you find my solution useful |
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| 34. |
(8) ञ. कम नयदि बहुपद 7 0 +5 के शून्यकों का योग 1 की |1(b) -5 (© 5L o 4B (2) 1 |
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| 35. |
EXERCISE 4B1. Draw the graph of each of the following equations(ii) x + 4i) x = 40 |
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Answer» 1) red line2) blue line |
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| 36. |
x3 + 3x² + 3xt!divided by at |
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Answer» We use the remainder theorem here Given divider = x + 1 So of it is a factor p (x) = 0 x + 1= 0 => x = -1 When will it be a factor, when we subtract the remainder According to the question P ( -1 ) - r = 0 Polynomial =x^3+3x^2 -3x-1 Therefore-1^3 +3 × -1 ^2 -3 ×-1 - 1 -r =0-1 +3+3-1 = r Remainder = 4 iska answer hai fourhai |
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| 37. |
EXERCISE 2.3Find the remainder when x + 3x + 3x + 1 is divided by1.(i)+1 |
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Answer» 0, 5/2 is the correct answer of the given question |
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| 38. |
Find the remainder when x, 3x' + 3x + 1 is divided byO r+1(ii) x(i |
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| 39. |
1. Find the square of:(i) 2a +b |
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| 40. |
B. The area of a square is 4a2 sq. metres. Whatis its boundary?1. 2a2. 4 a3. 8 a4. 16 a. |
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| 41. |
यदि वर्ग आव्यूह A की कोटि 3 और [A] = 4 है, तो |-2A का मान लिखिए ।If A is a square matrix of order 3 with | A] = 4, then write the value of- 2A|. |
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Answer» If |A|=4 then |-2A|=8 |
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| 42. |
EXERCISE 10AFind each of the following ratios in the simplest form:(i) 24 to 56(i) 84 paise to 3(il1) 4 kg to 750 goitto I hour(vil 2.4 km to 900 m |
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| 43. |
6. Find the smallest number which when divided by 15, the remainder is 10, whendivided by 25, the remainder is 20 and when divided by 35, the remainder is 30.(1) 530 (2) 525 (3) 520 (4) 515 |
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Answer» NONE OF THE ABOVE THIS IS THE WRONG QUESTION this question is wrong option 2 is the correct answer |
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| 44. |
When a polynomial f(x) is divided by (x - 1), the remainder is 5 and when it is divideby (r -2), the remainder is 7. Find the remainder when it is divided by (x-1) (2) |
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| 45. |
Manjit bought an iron safe for 12160 and paidäš340 for its transportation. Then, he sold itforäš12875, Find his gain percent. |
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Answer» Cost price for iron safe=₹12160+₹340=₹12500 Selling price=₹12875 Gain=Selling price-Cost price=₹12875-₹12500=₹375 Gain percent=(375/12500)*100= 3% |
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| 46. |
24 and 36.Find the largest four-digits number which when divided by 47leaves a remainder of 3 in each case.1 which should be added to 2497 so that the sum |
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Answer» L.c.m of 4,7,13=364we known that the greatess 4 digit no. is 9999now we divide the l.c.m by greatness no. 9999we get 27 as quotient and 171 as remainder now substrate the remainder by 99999999-171=9828 |
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| 47. |
है ७८ समकोण त्रिभुज है, जिसमें 24 = 90° SR 4B = AC है। 4B |
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| 48. |
24b 100 |
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| 49. |
If sin (A+2B)-and cos (A+4B)-0, A B and A +4B < 90°, then find the value of A and B. |
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Answer» sin(A+2B)=sin60°.=>A+ 2B=60°. cos(A+4B)=cos90° =>A+4B=90°. Now we have Subtract both equation. - 2B=-30° =>B=15°. Hence A+2.15°=60°=>A=60°-30°=30°. A=30°,B=15° As we have sin(A+2B)=sin60°.=>A+ 2B=60°. cos(A+4B)=cos90° =>A+4B=90°. Now we havenow |
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| 50. |
31. If ZA and 4B are acute angles such that tan A tan B then prove thatLA 4B. |
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Answer» If angle A and angle B. are acute angle and tanA = tanB so, sinA/cosA = sinB/cosB => sinAcosB -sinBcosA. = 0=> sin(A-B) = 0 ... ( standard identity ) so A-B = 0 or A = B. |
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