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p(5p^2 - 80) को 5p(p-4) से भाग दीजिए | |
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Answer» p(5p^2 -80)/ 5p(p-4)p5(p^2-16)/5p(p-4)Now 5p will get cancelledand a^2-b^2=(a+b)(a-b)(p^2-16)=(p+4)(p-4)therefore(p+4)(p-4)/(p-4)=p+4 |
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