Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

\left. \begin{array} { l } { \text { If } f ( x ) = \frac { x - 1 } { x + 1 } , \text { then } f ( a x ) \text { in terms of } f ( x ) \text { is equal to } } \\ { \text { (a) } \frac { f ( x ) + a } { 1 + a f ( x ) } } \end{array} \right.

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2.

If z varies directly as x and inversely asincrease of 12% in x and a decrease of 20% in y.Find the percentageasy. Find the percentage increase in z due to anIfx+1 men will do the work in x + 1 days, find the number of dayfinish the same work.I days, find the number of days that (x+2) men can

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Given z∝ (x/y)Hence z = (x/y) assuming proportionality constant as 1.x increase by 12% and y decreases by 20%Hence z value becomes, z = 1.12x/0.8y = 112x/80yChange in z value = (112x/80y) - (x/y)= 32x/80yIncrease in z% = (32x/80y)/(x/y) x 100= (32/80) x 100 = 40%

3.

If the equation 3x2 2(a + b + c)x+ a2+b2 +c0 has real roots thenSelect an answerA a bD of these

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4.

17. Find total number of prime factors ofexpression (6)15 (5) * (9)"

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=2^15×3^15×3^11×3^11×5^11=2^15×3^37×5^11

2^15×3^15×3^11×3^11×5^11=2^15×3^37x5^11

5.

thnewtienu4. If x varies directly as y, then find the missing entry.1560

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where the four comes

ok

thanks

6.

lf.), varies directly as x2 and y = 8 when x=2, findy when x = 6.l 10

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7.

2. दर्शाइए कि कोई भी धनात्मक विषम पूर्णांक 64+1, या 64+3. या 6q+ 5, के रूप का होता है ।जहाँ कोई पूर्णाक है।

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8.

4. Divide 340 in the ratio 2:3.

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9.

If 5" 125, then 5625(64)5052 of these

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10.

64. 0.2x -53.5x-3 5

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Thank you

11.

24*(text*(60*(f*o))) %2B 220 - 11

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the correct answer is1649

220+24 of 60 -1089÷99220+24*60-11220+1440-111649

12.

2*(470/235) %2B 220

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13.

. If d varies directly as t, and ifd=4 when t = 9, find d when t=21.

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d is proportional to td = kt4 = k × 9k = 4/9So when t = 21then d = (4×21)/9 = (4×7)/3 = 28/3

14.

-e ) ;.”".f?"f हक.कि जे

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(1-x)tan(pie*x)/2 = (1-x)/cot(pie*x)/2 lim x->1 (1-x)/cot(pie*x)/2 if we will put x=1 we will get 0/0 form so using L'hospital rule lim x->1 (-1)/(-cosec(pie*x)/2*cosec(pie*x)/2) = (-1)/(-1) = 1

your answer is wrong

15.

18) x varies directly as y, when x = 5, y - 30. Find the constant of variation and equation of variation

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option a is the right answer

option a is the right answer

option a . is the correct answer

16.

if p varies directly as q and p is equal to 282,when q =5.1. if q=6.8,then what is p

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17.

5.y varies directly as square root of x. When x = 16, y = 24. Find the constant olvariation and equation of variation.

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It is given that ,

y varies directly as square root of x .

x = 16 , y = 24

y = k × √x ( k is a constant )

24 = k × √16

24 = 4k

24/4 = k

6 = k

Therefore ,Required constant = k = 6

And Equation y = 6√x

18.

.2: Find the area of the sector of ciich subtends an angle of 120° at the cente radius of the circle is 6 cnm.

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Area of sector = (120/360)*π*r²= (1/3)*(22/7)*(6²)= 37.71 cm²

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19.

BSelect a figure from the options which will complete the patterFigure (X)

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Sarah, Leah, Haley, and Kim bought555bottles of water to share among themselves. They divided each bottle of water into444equal portions. Sarah took111portion from each bottle of water.

Which equation represents how much of a bottle of water Sarah took?

20.

Q27 Two dice are thrown simultaneously. What is the probability that the total scoprime number? u cne ae o

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first hav to write prime numbers below 12 because 6,6 sum ends with 12,so there ll be 15 terms as like 1 1,2 1,1 2,.........6 5,so 15/36=5/12

can u tell it in a simple way

21.

लॉग,Wi<

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Ans :- (4/7) ÷ (-5/7) = (4/7) × (-7/5) = -4/5

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22.

S. D, E and F are respectively the mid-points of0) BDEF is a parallelogram.(ii) ar (DEF)ar (ABC)the sides BC, CA and AB of a ΔABC. Show that^ ar (ABC.(ii) ar (BDEF) -

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Proof (I) and (ii)

Proof (III)

23.

2. If E,FG and H are respectively the mid-points ofthe sides of a parallelogram ABCD, show thatD EFigar (EFGH)--ar (ABCD).dAn resnectively

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24.

Express each of the ratios in the simplest form:(i) 6 and 50 p to? 4m 60 cm to 5 m

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i) 1 rupee= 100 paise.₹6.5 : ₹4= 6.5:4= 13:8ii) 1m = 100cm.3m 60cm = 360cm.5m = 500cm.3m 60cm : 5m = 360:500= 18:25

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thanks you

25.

645.) 1 km to 600 m in simplest form is:(a) 5:3(b) 100:6

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1 km = 1000 m

So, ratio is

1000 m : 600

10 : 6

5 : 3

a) Option is correct

26.

(iii)SP. =340 and gain =が20

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Gain= sp-cp20= 340- CPCP= 320 ruppes

27.

20 - 85 %2B 220*340

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340×220-340÷4+2074800-85+2074800-6574735

28.

450+340=?

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790 is the correct answer...

29.

4. Divide 340 in the ratio 2:3

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Let the parts be 2x and 3x2x + 3x = 3405x = 340x = 68

340 can be divided in 2:3as 136, 204

30.

4. Divide 340 in the ratio 2: 3.

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Total parts = 3+2= 5now we have to divide it 3/5*340= 204and second part2/5*340= 136

31.

IfE F.G and H are respectively the mid-points ofthe sides of a parallelogram ABCD, show thatar (EFGH)ar (ABCD)2

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32.

Examine the tile pattern shown at right.a. On graph paper, draw Figure 4b. How many tiles will Figure 10 have?慍慍1-15.Figure 1Figure 2FigureHow do you know?

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In figure 10 tiles will be 6+12+16+20+24+28+32+36+40+44....

these are the sequence of tile which will formed ... at 10th place there will be 44 tiles

It would be an AP with a= 6 and d=4Figure 10 will have6 + 9*4 = 42

33.

Q7, i Define regular poly[Draw any figure of polygon)any figure of polygon) Find xy.z, w in the given司Find , w z wint eg eachfigure(2 mark each)120

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Apolygonisregularwhen all anglesareequal and all sidesareequal (otherwise it is "irregular"). This is aregular pentagon(a 5-sidedpolygon).

34.

2.IfE,FG and H are respectively the mid-points ofthe sides of a parallelogram ABCD, show that"ar (EFGH)ar (ABCD)

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35.

Figure A is a scale image of figure B.Figure AFigure BFigure A maps to figure B with a scale factor ofWhat is the value of x?

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the answer is,the value of x is 12

how

36.

है ~ A yescdical pudo 4 loasgle G onCusiea ol p कि. लि.

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Length of the vertical pole = 6m (Given)

Shadow of the pole = 4 m (Given)

Let Height of tower =hm

Length of shadow of the tower = 28 m (Given)

In ΔABC and ΔDEF,

∠C = ∠E (angular elevation of sum)

∠B = ∠F = 90°

∴ ΔABC ~ ΔDEF (By AA similarity criterion)

∴ AB/DF = BC/EF (If two triangles are similar corresponding sides are proportional)

∴ 6/h= 4/28

⇒h= 6×28/4

⇒h=6 × 7

⇒h= 42 m

Hence, the height of the tower is 42 m.

37.

2, If E,F,Gand H are respectively the mid-points ofthe sides of a parallelogram ABCD, show that]ar(EFGH) = - ar (ABCD) ,

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38.

21 ABCD is a parallelogram. E and F are points on side AB such thatAE-EFzfB. Show that arDAE) =-ar (ABCD).A4

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39.

2.94 (-€((७न का + iol = न 3 दि3 P

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p = tanФ + secФp -secФ = tanФp² + sec²Ф - 2 p secФ = tan²Ф= sec²Ф - 1So secФ = (p² + 1) / 2p

so cosФ = 2p/(1+p²)sinФ = √[1 - cos²Ф ] = (p²-1)/(1+p²)

Samagh nahi aa rha

40.

s. D, E and F are respectively the mid-points of the sides BC, CA and AB of a AABC.Show thatG) BDEF is a parallelogram.(iii) ar (BDEF) ar(ABC)(i) ar (DEF4 ar (ABC)2

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41.

3, 4 weeks3 daysdays

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1 week=7 days4 weeks=7×4=24 days4 weeks 3 days=24 days +3 days= 27 days

thank

42.

ratios in simplest form 1m 5 cm: 63 cm

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1 m = 100 cm

1 m 5 cm = (100+5) cm =105 cm

105 : 63 = 5 : 3

43.

Which of the following ratios is the largest?(A) 7:15(B) 15:23(C) 17:25(D) 21:29

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21/29 is largest in all the given ratio

44.

3, 4 weeks 3 daysdays

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4 weeks=4*7=28 days1 week=7 days28+3=31 days

45.

TR U P WP L OL = वितन० हे विद न ०

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nPk = n!/(n-k)! (n+2)P3 : (n+1)P3 = 10 : 7 (n+2)!/(n+2-3)! : (n+1)!/(n+1-3)! = 10 : 7 (n+2)!/(n-1)! : (n+1)!/(n-2)! = 10 : 7 (n+2)(n+1)!/((n-1)(n-2)!) : (n+1)!/(n-2)! = 10/7 (n+2)/(n-1) = 10/7 7n + 14 = 10n - 10 3n = 24 n = 8

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46.

340 days into months, weeks and days

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Months= 340/30 = 11 monthsWeeks = {340 - (11*30)}/7= 10/7= 1 week and 3 days.

47.

MPLE 27 The angle of elevation of a jet fighter from a point A on the ground is60°. After a flight of 15 seconds, the angle of elevation changes to 30If the jet is flying at a speed of 720 km/hour, find the constantheight at which the jet is flying. [Use 3 1.732.] [CBSE 20080

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48.

ICBSE 2010]a rectangle.19. In the given figure, ABCD is aparallelogram, AM CN. Prove thatBNDM is a parallelogram.riren figure, ABCD is a

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49.

23. In the given figure, ABCD is aparallelogram. L is the mid-point of AB.Prove that ACBM is a parallelogram.

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Construct:ACandMBIn∆ALMand∆BLCAL=BL(LismidpointofAB)∠ALM=∠BLC(VerticallyoppositeAngle)∠AML=∠LCB(Alternateangles)Therefore,In∆ALM≅∆BLC(byASA)AM=BC(byCPCT)Hence,ACBMisaPararllelogram(Apairofoppositesidesisequalinparallel)

50.

Divide (5x-4x+3x +18) by (3-2x +x2).

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