है ~ A yescdical pudo 4 loasgle G onCusiea ol p कि. लि.

1.	है ~ A yescdical pudo 4 loasgle G onCusiea ol p कि. लि.
Answer» Length of the vertical pole = 6m (Given) Shadow of the pole = 4 m (Given) Let Height of tower =hm Length of shadow of the tower = 28 m (Given) In ΔABC and ΔDEF, ∠C = ∠E (angular elevation of sum) ∠B = ∠F = 90° ∴ ΔABC ~ ΔDEF (By AA similarity criterion) ∴ AB/DF = BC/EF (If two triangles are similar corresponding sides are proportional) ∴ 6/h= 4/28 ⇒h= 6×28/4 ⇒h=6 × 7 ⇒h= 42 m Hence, the height of the tower is 42 m.

Answer»

Length of the vertical pole = 6m (Given)

Shadow of the pole = 4 m (Given)

Let Height of tower =hm

Length of shadow of the tower = 28 m (Given)

In ΔABC and ΔDEF,

∠C = ∠E (angular elevation of sum)

∠B = ∠F = 90°

∴ ΔABC ~ ΔDEF (By AA similarity criterion)

∴ AB/DF = BC/EF (If two triangles are similar corresponding sides are proportional)

∴ 6/h= 4/28

⇒h= 6×28/4

⇒h=6 × 7

⇒h= 42 m

Hence, the height of the tower is 42 m.

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