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23. In the given figure, ABCD is aparallelogram. L is the mid-point of AB.Prove that ACBM is a parallelogram. |
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Answer» Construct:ACandMBIn∆ALMand∆BLCAL=BL(LismidpointofAB)∠ALM=∠BLC(VerticallyoppositeAngle)∠AML=∠LCB(Alternateangles)Therefore,In∆ALM≅∆BLC(byASA)AM=BC(byCPCT)Hence,ACBMisaPararllelogram(Apairofoppositesidesisequalinparallel) |
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